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Cell biology

AQA · GCSE · Biology · Topic 1

1.1

Cell biology: the unit of life

Every living thing is built from cells, and the differences between them decide what each can do. This reference covers AQA GCSE Biology 8461, topic 4.1 Cell biology.

How the exam treats this topic:

  • Paper 1 (4.1–4.4) carries Cell biology. Required practicals: RP1 (light microscope), RP2 (antiseptics/antibiotics on agar, biology only) and RP3 (osmosis in plant tissue).
  • Culturing microorganisms is biology only; standard-form answers for bacterial numbers are HT only.
  • Calculations the exam demands: magnification (image ÷ real), real size from image and magnification, area by πr², percentage change in mass, surface-area-to-volume ratio, bacterial division counts.
1.1

Cell structure: eukaryotes and prokaryotes

Syllabus

Cell structure, specialisation, microscopy and culturing (AQA 8461 statements 4.1.1.1-4.1.1.6, RP1, RP2).

  1. Describe plant, animal and bacterial cells, naming structures and their functions.
  2. Relate specialised cells' structures to their functions.
  3. Explain the importance of cell differentiation.
  4. Calculate magnification, real size and image size, with standard form and prefixes.
  5. Describe aseptic technique with reasons, bacterial division counts and zone areas (biology only).

Source: Cambridge International syllabus

An animal cell, a plant cell and a bacterial cell with their key structures labelled.
Learn the labels — the exam asks you to name and function them.
Structure Function
nucleus genetic material (DNA); controls the cell
cytoplasm jelly where reactions happen
cell membrane controls what enters and leaves
mitochondria aerobic respiration releases energy
ribosomes protein synthesis
chloroplast (plant) photosynthesis
permanent vacuole (plant) cell sap, keeps the cell firm
cell wall (plant, cellulose) strength and support
  • Eukaryotic 真核 cells (plant and animal): genetic material enclosed in a nucleus.
  • Prokaryotic 原核 cells (bacteria) are much smaller; cytoplasm and cell membrane surrounded by a cell wall; genetic material is not in a nucleus — a single DNA loop plus one or more plasmids (small rings of DNA).

Scale: use the prefixes centi (10⁻²), milli (10⁻³), micro (10⁻⁶), nano (10⁻⁹) and order-of-magnitude comparisons in standard form.

Vocabulary Train
English
eukaryotic/ˌjuːkərɪˈɒtɪk/
prokaryotic/ˌprɒkərɪˈɒtɪk/
1.1

Cell specialisation, differentiation and microscopy

Syllabus

Cell structure, specialisation, microscopy and culturing (AQA 8461 statements 4.1.1.1-4.1.1.6, RP1, RP2).

  1. Describe plant, animal and bacterial cells, naming structures and their functions.
  2. Relate specialised cells' structures to their functions.
  3. Explain the importance of cell differentiation.
  4. Calculate magnification, real size and image size, with standard form and prefixes.
  5. Describe aseptic technique with reasons, bacterial division counts and zone areas (biology only).

Source: Cambridge International syllabus

Specialised cells relate structure to function (learn one feature ↔ one advantage each):

Cell Adaptation Function
sperm cell tail for swimming, many mitochondria, acrosome with enzymes fertilisation
nerve cell long axon, insulating sheath carrying impulses
muscle cell many proteins fibres, many mitochondria contraction
root hair cell large surface area, thin wall absorbing water and minerals
xylem cell hollow, lignified walls, no end walls transporting water
phloem cell sieve plates, few organelles transporting sugars

Differentiation 分化: cells acquire different sub-cellular structures to become specialised. Animal cells differentiate mostly at an early stage; plant cells throughout life. In mature animals, cell division is mainly for repair and replacement.

Microscopy: a light microscope uses lenses; an electron microscope has much higher magnification and resolving power 分辨能力, so far more sub-cellular structures could be seen and understood.

$$\text{magnification} = \frac{\text{size of image}}{\text{size of real object}}$$

Worked example. A cell image is 4.8 cm wide at magnification ×1200.

  • Convert first: $4.8\ \text{cm} = 4.8\times10^{-2}$ m $= 48\,000\ \mu\text{m}$.
    $$\text{real size} = \frac{\text{image size}}{\text{magnification}} = \frac{48\,000\ \mu\text{m}}{1200} = 40\ \mu\text{m}$$

RP1: observe, draw and label plant and animal cells with a magnification scale included (e.g. a scale bar or the printed magnification).

Vocabulary Train
English
Differentiation/ˌdɪfəˌrenʃɪˈeɪʃn/
resolving power/rɪˈzɒlvɪŋ ˈpaʊə/
1.1

Culturing microorganisms (biology only)

Syllabus

Cell structure, specialisation, microscopy and culturing (AQA 8461 statements 4.1.1.1-4.1.1.6, RP1, RP2).

  1. Describe plant, animal and bacterial cells, naming structures and their functions.
  2. Relate specialised cells' structures to their functions.
  3. Explain the importance of cell differentiation.
  4. Calculate magnification, real size and image size, with standard form and prefixes.
  5. Describe aseptic technique with reasons, bacterial division counts and zone areas (biology only).

Source: Cambridge International syllabus

Bacteria multiply by binary fission 二分裂 as often as once every 20 minutes with enough nutrients and a suitable temperature. They grow in nutrient broth or as colonies on agar gel.

Aseptic technique 无菌操作 (each point earns a mark — know the why):

  • sterilise Petri dishes and culture media before use — kills unwanted microorganisms;
  • flame the inoculating loop before transferring bacteria — kills contaminants on the loop;
  • secure the lid with adhesive tape and store upside down — stops airborne contamination and condensation dripping;
  • in schools, incubate at a maximum of 25 °C — prevents growth of pathogens harmful to humans.

Worked example (division count). One bacterium divides every 20 minutes for 3 hours.

  • 3 hours = 180 min = 9 division times; number $= 2^9 = 512$.

Worked example (zone area). A clear zone of radius 4 mm around an antibiotic disc.

$$A = \pi r^2 = \pi \times 4^2 = 50\ \text{mm}^2\ \text{(2 s.f.)}$$

RP2: effect of antiseptics/antibiotics on bacterial growth — measure zones of inhibition with a ruler (several diameters, mean, ÷2), controls with no substance.

Vocabulary Train
English
binary fission/ˈbaɪnəri ˈfɪʃn/
Aseptic technique/æˈseptɪk tekˈniːk/
1.2

Cell division: chromosomes, mitosis and the cell cycle

Syllabus

Cell division and stem cells (AQA 8461 statements 4.1.2.1-4.1.2.3).

  1. Describe chromosomes and their pairing in body cells.
  2. Describe the cell cycle including the three overall stages and mitosis.
  3. Describe stem cell function in embryos, adult animals and plant meristems.
  4. Evaluate stem cell use in medicine and plant cloning, including risks and ethical objections.

Source: Cambridge International syllabus

  • The nucleus contains chromosomes 染色体 made of DNA; each chromosome carries many genes; body cells have chromosomes in pairs (humans: 23 pairs).
  • The cell cycle: DNA replicates → growth (more ribosomes and mitochondria) → mitosis 有丝分裂 (one set of chromosomes pulled to each end; nucleus divides) → cytoplasm and membranes divide → two identical cells.

Mitosis matters for growth and development of multicellular organisms, and repair. Recognise contexts where mitosis is occurring (a growing root tip, healing skin, a tumour).

Vocabulary Train
English
chromosomes/ˈkrəʊməsəʊmz/
mitosis/maɪˈtəʊsɪs/
1.2

Stem cells

Syllabus

Cell division and stem cells (AQA 8461 statements 4.1.2.1-4.1.2.3).

  1. Describe chromosomes and their pairing in body cells.
  2. Describe the cell cycle including the three overall stages and mitosis.
  3. Describe stem cell function in embryos, adult animals and plant meristems.
  4. Evaluate stem cell use in medicine and plant cloning, including risks and ethical objections.

Source: Cambridge International syllabus

A stem cell 干细胞 is an undifferentiated cell that can give rise to many more of the same type and, by differentiation, to other cell types.

Source Can become
embryo most types of human cell
adult bone marrow many cells, including blood cells
plant meristems any type of plant cell, throughout life

Uses and evaluation (the credited pairs — benefit and risk/objection):

  • Medicine: potential treatment for diabetes and paralysis; therapeutic cloning makes an embryo with the patient's own genes, so cells are not rejected.
  • Risks/ethics: transfer of viral infection; ethical and religious objections to using embryos.
  • Plants: meristem clones — rare species preserved from extinction; disease-resistant crops cloned quickly and economically.
Vocabulary Train
English
stem cell/stem sel/
1.3

Transport in cells

Syllabus

Transport in cells (AQA 8461 statement 4.1.3, RP3).

  1. Define diffusion, osmosis and active transport with examples and the energy distinction.
  2. Explain factors affecting the rate of diffusion.
  3. Calculate and compare surface area to volume ratios; explain exchange-surface adaptations.
  4. Investigate the effect of solute concentration on plant tissue mass and calculate percentage change (RP3).

Source: Cambridge International syllabus

Process Direction Energy Examples
diffusion 扩散 high → low concentration (net) no O₂/CO₂ in gas exchange; urea from cells to blood plasma
osmosis 渗透 water from dilute → concentrated solution through a partially permeable membrane no water into plant cells
active transport 主动运输 low → high (against the gradient) yes — from respiration mineral ions into root hairs; glucose from gut to blood

Rate of diffusion increases with: concentration gradient, temperature, surface area of the membrane.

Diffusion, osmosis and active transport compared in three panels.
Direction and energy separate the three processes.
Two cubes showing how doubling the side halves the surface-area-to-volume ratio.
Bigger organisms need exchange surfaces.

Surface area to volume ratio: single-celled organisms have a large SA:V — enough exchange across the surface alone. Multicellular organisms need exchange surfaces and a transport system. Exchange surfaces are effective by: large surface area, thin membrane (short diffusion path), (animals) good blood supply, (animals, gas exchange) ventilation.

Adapted exchange surfaces to know: small intestine and lungs in mammals, gills in fish, roots and leaves in plants.

Worked example (SA:V). A cube of side 2 mm: SA $= 6\times2^2 = 24$ mm², V $= 8$ mm³, SA:V $= 3:1$. A cube of side 4 mm: SA $= 96$, V $= 64$, SA:V $= 1.5:1$ — doubling the side halves the ratio.

RP3 (osmosis): potato pieces (same surface area, blotted dry, exact masses) in a range of sugar or salt solutions; measure percentage change in mass:

$$\%\ \text{change} = \frac{\text{change in mass}}{\text{initial mass}} \times 100$$

Interpretation: gain in dilute solutions (water enters); no change where the solution matches the cell concentration; loss in concentrated solutions (water leaves). Control variables: volume of solution, temperature, time, surface area.

Vocabulary Train
English
diffusion/dɪˈfjuːʒn/
osmosis/ɒzˈməʊsɪs/
active transport/ˈæktɪv ˈtrænspɔːt/
1.3

Checklist before you call this topic done

  • Label animal, plant and bacterial cells; match every structure to its function.
  • Specialised cells: one structural feature linked to one function each.
  • Magnification, real size and image size — convert units before dividing.
  • Aseptic technique whys; binary-fission counts; πr² zones (RP1, RP2).
  • Cell cycle stages and where mitosis occurs; stem cell sources with benefits and risks.
  • Diffusion, osmosis, active transport: direction, energy, examples; the three rate factors.
  • SA:V calculations; four exchange-surface features; percentage change in mass (RP3).

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