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AQA · GCSE · Biology

  • 1

    Cell biology

    1.1

    Cell biology: the unit of life

    Every living thing is built from cells, and the differences between them decide what each can do. This reference covers AQA GCSE Biology 8461, topic 4.1 Cell biology.

    How the exam treats this topic:

    • Paper 1 (4.1–4.4) carries Cell biology. Required practicals: RP1 (light microscope), RP2 (antiseptics/antibiotics on agar, biology only) and RP3 (osmosis in plant tissue).
    • Culturing microorganisms is biology only; standard-form answers for bacterial numbers are HT only.
    • Calculations the exam demands: magnification (image ÷ real), real size from image and magnification, area by πr², percentage change in mass, surface-area-to-volume ratio, bacterial division counts.
    1.1

    Cell structure: eukaryotes and prokaryotes

    Syllabus

    Cell structure, specialisation, microscopy and culturing (AQA 8461 statements 4.1.1.1-4.1.1.6, RP1, RP2).

    1. Describe plant, animal and bacterial cells, naming structures and their functions.
    2. Relate specialised cells' structures to their functions.
    3. Explain the importance of cell differentiation.
    4. Calculate magnification, real size and image size, with standard form and prefixes.
    5. Describe aseptic technique with reasons, bacterial division counts and zone areas (biology only).

    Source: Cambridge International syllabus

    An animal cell, a plant cell and a bacterial cell with their key structures labelled.
    Learn the labels — the exam asks you to name and function them.
    Structure Function
    nucleus genetic material (DNA); controls the cell
    cytoplasm jelly where reactions happen
    cell membrane controls what enters and leaves
    mitochondria aerobic respiration releases energy
    ribosomes protein synthesis
    chloroplast (plant) photosynthesis
    permanent vacuole (plant) cell sap, keeps the cell firm
    cell wall (plant, cellulose) strength and support
    • Eukaryotic 真核 cells (plant and animal): genetic material enclosed in a nucleus.
    • Prokaryotic 原核 cells (bacteria) are much smaller; cytoplasm and cell membrane surrounded by a cell wall; genetic material is not in a nucleus — a single DNA loop plus one or more plasmids (small rings of DNA).

    Scale: use the prefixes centi (10⁻²), milli (10⁻³), micro (10⁻⁶), nano (10⁻⁹) and order-of-magnitude comparisons in standard form.

    Vocabulary Train
    English
    eukaryotic/ˌjuːkərɪˈɒtɪk/
    prokaryotic/ˌprɒkərɪˈɒtɪk/
    1.1

    Cell specialisation, differentiation and microscopy

    Syllabus

    Cell structure, specialisation, microscopy and culturing (AQA 8461 statements 4.1.1.1-4.1.1.6, RP1, RP2).

    1. Describe plant, animal and bacterial cells, naming structures and their functions.
    2. Relate specialised cells' structures to their functions.
    3. Explain the importance of cell differentiation.
    4. Calculate magnification, real size and image size, with standard form and prefixes.
    5. Describe aseptic technique with reasons, bacterial division counts and zone areas (biology only).

    Source: Cambridge International syllabus

    Specialised cells relate structure to function (learn one feature ↔ one advantage each):

    Cell Adaptation Function
    sperm cell tail for swimming, many mitochondria, acrosome with enzymes fertilisation
    nerve cell long axon, insulating sheath carrying impulses
    muscle cell many proteins fibres, many mitochondria contraction
    root hair cell large surface area, thin wall absorbing water and minerals
    xylem cell hollow, lignified walls, no end walls transporting water
    phloem cell sieve plates, few organelles transporting sugars

    Differentiation 分化: cells acquire different sub-cellular structures to become specialised. Animal cells differentiate mostly at an early stage; plant cells throughout life. In mature animals, cell division is mainly for repair and replacement.

    Microscopy: a light microscope uses lenses; an electron microscope has much higher magnification and resolving power 分辨能力, so far more sub-cellular structures could be seen and understood.

    $$\text{magnification} = \frac{\text{size of image}}{\text{size of real object}}$$

    Worked example. A cell image is 4.8 cm wide at magnification ×1200.

    • Convert first: $4.8\ \text{cm} = 4.8\times10^{-2}$ m $= 48\,000\ \mu\text{m}$.
      $$\text{real size} = \frac{\text{image size}}{\text{magnification}} = \frac{48\,000\ \mu\text{m}}{1200} = 40\ \mu\text{m}$$

    RP1: observe, draw and label plant and animal cells with a magnification scale included (e.g. a scale bar or the printed magnification).

    Vocabulary Train
    English
    Differentiation/ˌdɪfəˌrenʃɪˈeɪʃn/
    resolving power/rɪˈzɒlvɪŋ ˈpaʊə/
    1.1

    Culturing microorganisms (biology only)

    Syllabus

    Cell structure, specialisation, microscopy and culturing (AQA 8461 statements 4.1.1.1-4.1.1.6, RP1, RP2).

    1. Describe plant, animal and bacterial cells, naming structures and their functions.
    2. Relate specialised cells' structures to their functions.
    3. Explain the importance of cell differentiation.
    4. Calculate magnification, real size and image size, with standard form and prefixes.
    5. Describe aseptic technique with reasons, bacterial division counts and zone areas (biology only).

    Source: Cambridge International syllabus

    Bacteria multiply by binary fission 二分裂 as often as once every 20 minutes with enough nutrients and a suitable temperature. They grow in nutrient broth or as colonies on agar gel.

    Aseptic technique 无菌操作 (each point earns a mark — know the why):

    • sterilise Petri dishes and culture media before use — kills unwanted microorganisms;
    • flame the inoculating loop before transferring bacteria — kills contaminants on the loop;
    • secure the lid with adhesive tape and store upside down — stops airborne contamination and condensation dripping;
    • in schools, incubate at a maximum of 25 °C — prevents growth of pathogens harmful to humans.

    Worked example (division count). One bacterium divides every 20 minutes for 3 hours.

    • 3 hours = 180 min = 9 division times; number $= 2^9 = 512$.

    Worked example (zone area). A clear zone of radius 4 mm around an antibiotic disc.

    $$A = \pi r^2 = \pi \times 4^2 = 50\ \text{mm}^2\ \text{(2 s.f.)}$$

    RP2: effect of antiseptics/antibiotics on bacterial growth — measure zones of inhibition with a ruler (several diameters, mean, ÷2), controls with no substance.

    Vocabulary Train
    English
    binary fission/ˈbaɪnəri ˈfɪʃn/
    Aseptic technique/æˈseptɪk tekˈniːk/
    1.2

    Cell division: chromosomes, mitosis and the cell cycle

    Syllabus

    Cell division and stem cells (AQA 8461 statements 4.1.2.1-4.1.2.3).

    1. Describe chromosomes and their pairing in body cells.
    2. Describe the cell cycle including the three overall stages and mitosis.
    3. Describe stem cell function in embryos, adult animals and plant meristems.
    4. Evaluate stem cell use in medicine and plant cloning, including risks and ethical objections.

    Source: Cambridge International syllabus

    • The nucleus contains chromosomes 染色体 made of DNA; each chromosome carries many genes; body cells have chromosomes in pairs (humans: 23 pairs).
    • The cell cycle: DNA replicates → growth (more ribosomes and mitochondria) → mitosis 有丝分裂 (one set of chromosomes pulled to each end; nucleus divides) → cytoplasm and membranes divide → two identical cells.

    Mitosis matters for growth and development of multicellular organisms, and repair. Recognise contexts where mitosis is occurring (a growing root tip, healing skin, a tumour).

    Vocabulary Train
    English
    chromosomes/ˈkrəʊməsəʊmz/
    mitosis/maɪˈtəʊsɪs/
    1.2

    Stem cells

    Syllabus

    Cell division and stem cells (AQA 8461 statements 4.1.2.1-4.1.2.3).

    1. Describe chromosomes and their pairing in body cells.
    2. Describe the cell cycle including the three overall stages and mitosis.
    3. Describe stem cell function in embryos, adult animals and plant meristems.
    4. Evaluate stem cell use in medicine and plant cloning, including risks and ethical objections.

    Source: Cambridge International syllabus

    A stem cell 干细胞 is an undifferentiated cell that can give rise to many more of the same type and, by differentiation, to other cell types.

    Source Can become
    embryo most types of human cell
    adult bone marrow many cells, including blood cells
    plant meristems any type of plant cell, throughout life

    Uses and evaluation (the credited pairs — benefit and risk/objection):

    • Medicine: potential treatment for diabetes and paralysis; therapeutic cloning makes an embryo with the patient's own genes, so cells are not rejected.
    • Risks/ethics: transfer of viral infection; ethical and religious objections to using embryos.
    • Plants: meristem clones — rare species preserved from extinction; disease-resistant crops cloned quickly and economically.
    Vocabulary Train
    English
    stem cell/stem sel/
    1.3

    Transport in cells

    Syllabus

    Transport in cells (AQA 8461 statement 4.1.3, RP3).

    1. Define diffusion, osmosis and active transport with examples and the energy distinction.
    2. Explain factors affecting the rate of diffusion.
    3. Calculate and compare surface area to volume ratios; explain exchange-surface adaptations.
    4. Investigate the effect of solute concentration on plant tissue mass and calculate percentage change (RP3).

    Source: Cambridge International syllabus

    Process Direction Energy Examples
    diffusion 扩散 high → low concentration (net) no O₂/CO₂ in gas exchange; urea from cells to blood plasma
    osmosis 渗透 water from dilute → concentrated solution through a partially permeable membrane no water into plant cells
    active transport 主动运输 low → high (against the gradient) yes — from respiration mineral ions into root hairs; glucose from gut to blood

    Rate of diffusion increases with: concentration gradient, temperature, surface area of the membrane.

    Diffusion, osmosis and active transport compared in three panels.
    Direction and energy separate the three processes.
    Two cubes showing how doubling the side halves the surface-area-to-volume ratio.
    Bigger organisms need exchange surfaces.

    Surface area to volume ratio: single-celled organisms have a large SA:V — enough exchange across the surface alone. Multicellular organisms need exchange surfaces and a transport system. Exchange surfaces are effective by: large surface area, thin membrane (short diffusion path), (animals) good blood supply, (animals, gas exchange) ventilation.

    Adapted exchange surfaces to know: small intestine and lungs in mammals, gills in fish, roots and leaves in plants.

    Worked example (SA:V). A cube of side 2 mm: SA $= 6\times2^2 = 24$ mm², V $= 8$ mm³, SA:V $= 3:1$. A cube of side 4 mm: SA $= 96$, V $= 64$, SA:V $= 1.5:1$ — doubling the side halves the ratio.

    RP3 (osmosis): potato pieces (same surface area, blotted dry, exact masses) in a range of sugar or salt solutions; measure percentage change in mass:

    $$\%\ \text{change} = \frac{\text{change in mass}}{\text{initial mass}} \times 100$$

    Interpretation: gain in dilute solutions (water enters); no change where the solution matches the cell concentration; loss in concentrated solutions (water leaves). Control variables: volume of solution, temperature, time, surface area.

    Vocabulary Train
    English
    diffusion/dɪˈfjuːʒn/
    osmosis/ɒzˈməʊsɪs/
    active transport/ˈæktɪv ˈtrænspɔːt/
    1.3

    Checklist before you call this topic done

    • Label animal, plant and bacterial cells; match every structure to its function.
    • Specialised cells: one structural feature linked to one function each.
    • Magnification, real size and image size — convert units before dividing.
    • Aseptic technique whys; binary-fission counts; πr² zones (RP1, RP2).
    • Cell cycle stages and where mitosis occurs; stem cell sources with benefits and risks.
    • Diffusion, osmosis, active transport: direction, energy, examples; the three rate factors.
    • SA:V calculations; four exchange-surface features; percentage change in mass (RP3).
  • 2

    Organisation

    2.1

    Organisation: from cells to systems

    Cells form tissues, tissues form organs, organs form systems — and the digestive system, blood and plants each show the pattern. This reference covers AQA GCSE Biology 8461, topic 4.2 Organisation.

    How the exam treats this topic:

    • Paper 1 carries Organisation. Required practicals: RP4 (food tests) and RP5 (pH and amylase rate).
    • You must evaluate heart-disease treatments and stem-cell/lifestyle risk data, and interpret graphs and tables of risk factors.
    • Recall exactly: the enzymes table, the heart's vessels, blood components, plant tissues, transpiration factors.
    2.1

    Principles of organisation

    Syllabus

    Principles of organisation and the digestive system (AQA 8461 statements 4.2.1-4.2.2.1, RP4, RP5).

    1. Order cells, tissues, organs, organ systems and organisms.
    2. Describe enzyme nature and lock-and-key action; relate activity to temperature and pH.
    3. Recall sites and actions of amylase, proteases and lipases, with word equations.
    4. Explain bile's two functions; test foods (RP4) and investigate pH on amylase (RP5).

    Source: Cambridge International syllabus

    Cells → tissues → organs → organ systems → organism.

    • A tissue 组织 is a group of cells with a similar structure and function.
    • An organ 器官 aggregates tissues performing specific functions.
    • Organ systems 器官系统 work together to form the whole organism.

    The digestive system is the named example of an organ system.

    Vocabulary Train
    English
    tissue/ˈtɪʃuː/
    organ/ˈɔːɡən/
    organ systems/ˈɔːɡən ˈsɪstəmz/
    2.1

    The human digestive system (4.2.2.1)

    Syllabus

    Principles of organisation and the digestive system (AQA 8461 statements 4.2.1-4.2.2.1, RP4, RP5).

    1. Order cells, tissues, organs, organ systems and organisms.
    2. Describe enzyme nature and lock-and-key action; relate activity to temperature and pH.
    3. Recall sites and actions of amylase, proteases and lipases, with word equations.
    4. Explain bile's two functions; test foods (RP4) and investigate pH on amylase (RP5).

    Source: Cambridge International syllabus

    Enzymes 酶 are biological catalysts: proteins with an active site whose shape fits one substrate — the lock and key model. Temperature and pH change the rate; far from the optimum the enzyme denatures (active site changes shape).

    Enzyme Made in Acts on Products
    amylase (a carbohydrase) salivary glands, pancreas, small intestine starch simple sugars (glucose)
    protease stomach, pancreas, small intestine protein amino acids
    lipase pancreas, small intestine lipids glycerol + 3 fatty acids

    Digestive enzymes turn food into small soluble molecules that can be absorbed into the bloodstream. The products build new carbohydrates, lipids and proteins; some glucose is used in respiration.

    Bile 胆汁: made in the liver, stored in the gall bladder. It is alkaline, neutralising hydrochloric acid from the stomach, and emulsifies fat into small droplets, increasing the surface area — both raise the rate of fat breakdown by lipase.

    RP4 food tests (learn reagent, colour change, substance):

    Test Reagent Positive result
    sugars (reducing) Benedict's, heat blue → brick-red
    starch iodine orange/brown → blue-black
    protein Biuret blue → purple
    lipids Sudan III red-stained layer on top

    RP5 (pH and amylase): buffer solutions at pH values, amylase + starch, continuous sampling onto a spotting tile with iodine, record the time for the starch to disappear — shortest time = fastest rate at the optimum pH.

    Vocabulary Train
    English
    enzyme/ˈenzaɪm/
    Bile/baɪl/
    2.2

    The heart, blood vessels and blood (4.2.2.2–4.2.2.3)

    Syllabus

    The heart, blood vessels, blood and coronary heart disease (AQA 8461 statements 4.2.2.2-4.2.2.4).

    1. Describe the heart and double circulation with the five named vessels and the pacemaker cells.
    2. Relate artery, vein and capillary structure to function.
    3. Know plasma, red cells, white cells and platelets with their adaptations.
    4. Explain CHD and evaluate stents, statins, valves, transplants and artificial hearts.

    Source: Cambridge International syllabus

    The human heart with its four chambers and the five named vessels.
    Right side to the lungs; left side to the body.
    • The heart pumps blood in a double circulatory system: the right ventricle pumps blood to the lungs (gas exchange); the left ventricle pumps it around the rest of the body.
    • Vessels to know: aorta, vena cava, pulmonary artery, pulmonary vein, coronary arteries.
    • The resting heart rate is set by cells in the right atrium — the natural pacemaker; artificial pacemakers correct irregular rates.
    • Lungs: trachea → bronchi → alveoli 肺泡, surrounded by capillaries; alveoli are adapted by a large surface area, thin walls, good blood supply and ventilation.
    Vessel Structure Function
    artery thick, elastic, muscular walls; small lumen carries blood away at high pressure
    vein thin walls, large lumen, valves returns blood at low pressure
    capillary one cell thick exchange with tissues
    Red cells, white cells, plasma and platelets.

    Blood is a tissue: plasma 血浆 (carries dissolved sugars, amino acids, CO₂, urea, hormones, and heat), red blood cells 红细胞 (no nucleus, packed with haemoglobin, biconcave — large surface area for oxygen transport), white blood cells 白细胞 (engulf pathogens or make antibodies), platelets 血小板 (clotting).

    Vocabulary Train
    English
    alveoli/ˈælvɪɒli/
    plasma/ˈplæzmə/
    red blood cells/red blʌd selz/
    white blood cells/waɪt blʌd selz/
    platelets/ˈpleɪtlɪts/
    2.2

    Coronary heart disease (4.2.2.4) and treatments

    Syllabus

    The heart, blood vessels, blood and coronary heart disease (AQA 8461 statements 4.2.2.2-4.2.2.4).

    1. Describe the heart and double circulation with the five named vessels and the pacemaker cells.
    2. Relate artery, vein and capillary structure to function.
    3. Know plasma, red cells, white cells and platelets with their adaptations.
    4. Explain CHD and evaluate stents, statins, valves, transplants and artificial hearts.

    Source: Cambridge International syllabus

    In CHD layers of fatty material build up inside the coronary arteries, narrowing them — less blood, so less oxygen for the heart muscle. Evaluate each treatment with benefits and risks:

    Treatment Benefit Risk/limitation
    stents 支架 keeps the artery open, restores flow surgery risk; doesn't treat the cause
    statins 他汀 reduce blood cholesterol, slowing fatty deposits long-term medication with side effects (liver)
    valve replacement (biological or mechanical) restores one-way flow major surgery; mechanical need lifelong anti-clotting drugs
    transplant (heart / heart and lungs) cures failure donor shortage; rejection — immunosuppressants
    artificial heart keeps the patient alive while waiting, or lets the heart rest infection, clotting, bulky
    Vocabulary Train
    English
    stents/stents/
    statins/ˈstætɪnz/
    2.3

    Health, lifestyle and cancer (4.2.2.5–4.2.2.7)

    Syllabus

    Health, lifestyle and cancer (AQA 8461 statements 4.2.2.5-4.2.2.7).

    1. Define health and describe interactions between diseases and other factors.
    2. State risk factors with proven causal mechanisms for non-communicable diseases.
    3. Distinguish benign and malignant tumours and describe secondary tumours.
    4. Interpret risk-factor data, distinguishing correlation from causation.

    Source: Cambridge International syllabus

    Health is the state of physical and mental well-being — not just the absence of disease. Diet, stress and life situations affect both; different diseases interact (immune defects → more infections; viruses → some cancers; immune reactions trigger asthma; severe physical illness → depression).

    Risk factors 危险因素 are linked to an increased rate of a disease — aspects of lifestyle or substances in the body/environment. A causal mechanism is proven for some, not others: diet/smoking/exercise → cardiovascular disease; obesity → Type 2 diabetes; alcohol → liver damage and brain function; smoking → lung disease and lung cancer; smoking and alcohol → unborn babies; carcinogens including ionising radiation → cancer. Interpret risk-factor data as correlation; proven mechanism makes it causation.

    Cancer results from changes in cells producing uncontrolled growth and division:

    • Benign tumours: contained in one area, usually within a membrane; do not invade.
    • Malignant tumours (cancers) invade neighbouring tissues and spread in the blood to form secondary tumours.

    Risk factors include lifestyle and, for some cancers, genes.

    Vocabulary Train
    English
    Risk factors/rɪsk ˈfæktəz/
    2.4

    Plant tissues and transport (4.2.3)

    Syllabus

    Plant tissues, organs and transport (AQA 8461 statement 4.2.3).

    1. Relate plant tissues (epidermis, palisade, spongy, xylem, phloem, meristem, guard cells) to functions.
    2. Explain root hair, xylem and phloem adaptations and the processes of transpiration and translocation.
    3. Explain the effects of temperature, humidity, air movement and light intensity on transpiration rate.

    Source: Cambridge International syllabus

    A leaf in cross-section with its tissues labelled.
    Each tissue has one main job.
    • Epidermal tissue: protective covering; waxy cuticle on top.
    • Palisade mesophyll 栅栏组织: packed chloroplasts — most photosynthesis.
    • Spongy mesophyll: air spaces for gas exchange.
    • Xylem 木质部: hollow tubes strengthened by lignin — carries water and mineral ions from roots to leaves in the transpiration stream.
    • Phloem 韧皮部: sieve tubes — carries dissolved sugars from leaves to the rest of the plant (translocation 运输).
    • Meristem: at the growing tips of shoots and roots (stem cells).
    • Guard cells 保卫细胞 surround stomata 气孔, controlling gas exchange and water loss.
    • Root hair cells: large surface area; water enters by osmosis, mineral ions by active transport.

    Transpiration 蒸腾作用 is the loss of water vapour from the leaves (mostly through stomata); it pulls the transpiration stream. The rate increases with: temperature ↑, air movement ↑, light intensity ↑ (stomata open); decreases with humidity ↑. Measure rate by water uptake with a potometer.

    Vocabulary Train
    English
    palisade mesophyll/ˈpælɪseɪd ˈmesəfɪl/
    Xylem/ˈzaɪləm/
    Phloem/ˈfləʊɪm/
    Guard cells/ɡɑːd selz/
    stomata/ˈstəʊmətə/
    Transpiration/trænspəˈreɪʃn/
    translocation/trænsləʊˈkeɪʃn/
    2.4

    Checklist before you call this topic done

    • Order cells → tissues → organs → systems with one example each.
    • Enzyme table: name, site, substrate, products; lock and key; denaturing.
    • Bile: two functions with reasons; RP4 tests and colours; RP5 method.
    • Label the heart with all five named vessels; double circulation; pacemaker.
    • Artery/vein/capillary structure ↔ function; four blood components with adaptations.
    • CHD: cause + each treatment's benefit and risk.
    • Risk factors with causal mechanisms; benign vs malignant tumours.
    • Plant tissues and their jobs; xylem vs phloem; four transpiration factors.
  • 3

    Infection and response

    3.1

    Infection and response: the war inside

    Pathogens invade, defences respond, and medicine arms the fight. This reference covers AQA GCSE Biology 8461, topic 4.3 Infection and response.

    How the exam treats this topic:

    • Paper 1 carries this topic; RP2 (antibiotics/antiseptics on agar) links from topic 1.
    • Monoclonal antibodies (4.3.2) and plant disease (4.3.3) are biology only, and monoclonals plus plant-disease detection are HT only.
    • Recall exactly: each named disease → pathogen type, symptoms and spread; the defence systems; the drug-testing stages.
    Vocabulary Train
    English
    Pathogens/ˈpæθədʒnz/
    3.1

    Communicable diseases and pathogens (4.3.1.1)

    Syllabus

    Communicable diseases, pathogen types and named diseases (AQA 8461 statements 4.3.1.1-4.3.1.5).

    1. Explain how viruses, bacteria, protists and fungi spread in animals and plants, and how spread is reduced.
    2. Recall measles, HIV, TMV, Salmonella, gonorrhoea, rose black spot and malaria with pathogen type, spread, symptoms and control.

    Source: Cambridge International syllabus

    The four pathogen types with their key features.

    Pathogens are microorganisms 病原体 causing infectious disease: viruses, bacteria, protists, fungi. They infect plants or animals and spread by direct contact, water or air. Bacteria may produce toxins 毒素 that damage tissues; viruses live and reproduce inside cells.

    Reducing spread: hygiene (hand washing), sterilising wounds, clean water, sewage treatment, using condoms, vector control (mosquito nets, draining water).

    Vocabulary Train
    English
    toxins/ˈtɒksɪnz/
    3.1

    Named diseases (4.3.1.2–4.3.1.5)

    Syllabus

    Communicable diseases, pathogen types and named diseases (AQA 8461 statements 4.3.1.1-4.3.1.5).

    1. Explain how viruses, bacteria, protists and fungi spread in animals and plants, and how spread is reduced.
    2. Recall measles, HIV, TMV, Salmonella, gonorrhoea, rose black spot and malaria with pathogen type, spread, symptoms and control.

    Source: Cambridge International syllabus

    Disease Pathogen Spread Symptoms/signs Control
    measles virus droplet inhalation (sneezes, coughs) fever, red skin rash; can be fatal vaccination of young children
    HIV virus sexual contact, exchange of body fluids (shared needles) flu-like illness; attacks immune cells → late-stage AIDS antiretroviral drugs; safe sex; clean needles
    TMV (tobacco mosaic virus) virus (plants) contact between plants mosaic discolouration of leaves; reduced photosynthesis and growth resistant varieties; hygiene
    Salmonella bacterium food ingested in unhygienic conditions fever, cramps, vomiting, diarrhoea (bacteria + toxins) poultry vaccinated (UK); hygienic food prep
    gonorrhoea bacterium sexual contact thick yellow/green discharge, pain urinating antibiotics (resistance rising); condoms
    rose black spot fungus (plants) spores in water/air black spots on leaves; leaves yellow and drop removing/burning leaves; fungicide
    malaria protist mosquito vector recurrent fever; can be fatal nets; stopping mosquito breeding
    3.2

    Human defence systems and immunity (4.3.1.6–4.3.1.7)

    Syllabus

    Human defence systems, vaccination and drugs (AQA 8461 statements 4.3.1.6-4.3.1.9).

    1. Describe the non-specific defence systems and the three white blood cell actions.
    2. Explain vaccination in the individual and its population effect.
    3. Distinguish antibiotics from painkillers; explain why antibiotics cannot treat viruses; describe resistance.
    4. Describe drug discovery sources and the preclinical/clinical testing stages including double-blind trials.

    Source: Cambridge International syllabus

    The defence layers and the drug-testing chain.

    Non-specific defences: skin (barrier, scabbing); nose (hairs, mucus); trachea and bronchi (mucus, cilia); stomach (hydrochloric acid).

    The immune system destroys pathogens that enter. White blood cells defend by:

    1. phagocytosis — engulfing 吞噬 pathogens;
    2. antibody production — proteins 抗体 that bind the specific antigen;
    3. antitoxin production — neutralising 抗毒素 toxins.

    Vaccination 疫苗: small quantities of dead or inactive pathogen stimulate white blood cells to make antibodies; on re-infection, memory cells respond quickly with the correct antibodies, preventing infection. Herd effect: immunising a large proportion reduces the spread for everyone. Evaluate: benefits (epidemic control, e.g. measles) vs rare side effects.

    Vocabulary Train
    English
    phagocytosis/ˌfæɡəsɪˈtəʊsɪs/
    antibody production/ˈæntɪbɒdi prəˈdʌkʃn/
    antitoxin production/ˌæntɪˈtɒksɪn prəˈdʌkʃn/
    Vaccination/ˌvæksɪˈneɪʃn/
    3.2

    Antibiotics, painkillers and drug development (4.3.1.8–4.3.1.9)

    Syllabus

    Human defence systems, vaccination and drugs (AQA 8461 statements 4.3.1.6-4.3.1.9).

    1. Describe the non-specific defence systems and the three white blood cell actions.
    2. Explain vaccination in the individual and its population effect.
    3. Distinguish antibiotics from painkillers; explain why antibiotics cannot treat viruses; describe resistance.
    4. Describe drug discovery sources and the preclinical/clinical testing stages including double-blind trials.

    Source: Cambridge International syllabus

    • Antibiotics 抗生素 (e.g. penicillin) cure bacterial disease by killing bacteria inside the body — specific antibiotics for specific bacteria. They cannot kill viruses (viruses live inside cells; killing them would damage body tissue). Resistance is a major concern — the race for new antibiotics.
    • Painkillers treat symptoms but do not kill pathogens.

    Drug development: traditionally extracted from plants/microorganisms — digitalis from foxgloves (heart), aspirin from willow, penicillin from Penicillium mould (Fleming). Most new drugs are chemically synthesised, but starting points may still be plant chemicals.

    Testing stages: preclinical (cells, tissues, live animals) → clinical trials on healthy volunteers (low dose, safety) then patients (optimum dose, effectiveness) → double-blind trials with a placebo; results peer-reviewed.

    Vocabulary Train
    English
    Antibiotics/ˌæntɪbaɪˈɒtɪks/
    3.3

    Monoclonal antibodies (biology only, HT)

    Syllabus

    Monoclonal antibodies, biology only and HT (AQA 8461 statement 4.3.2).

    1. Describe hybridoma production of monoclonal antibodies.
    2. Describe uses in diagnosis, measurement, research and cancer treatment.

    Source: Cambridge International syllabus

    Monoclonal antibodies 单克隆抗体 are produced from a single clone of cells, specific to one binding site on one protein antigen. Producing them: stimulate mouse lymphocytes to make the antibody → fuse with a tumour cell to make a hybridoma 杂交瘤 — it divides AND makes the antibody → clone the hybridoma → collect and purify large amounts of one specific antibody.

    Uses: pregnancy tests; measuring hormone/chemical levels in blood; detecting pathogens; research — fluorescent antibodies locate molecules; cancer treatment — antibody bound to a radioactive/toxic substance delivers it only to cancer cells.

    Vocabulary Train
    English
    Monoclonal antibodies/ˈmɒnəʊklɒnl ˈæntɪbɒdiz/
    hybridoma/ˌhaɪbrɪˈdəʊmə/
    3.4

    Plant disease (biology only)

    Syllabus

    Plant disease, biology only (AQA 8463 statement 4.3.3).

    1. Detect plant disease from signs and identify it by manual, laboratory or monoclonal tests.
    2. Explain nitrate and magnesium ion deficiencies.
    3. Describe physical, chemical and mechanical plant defence responses.

    Source: Cambridge International syllabus

    Detection (HT): stunted growth, spots on leaves, areas of decay, growths, malformed stems/leaves, discolouration, presence of pests.

    Identification (HT): gardening manual/website; laboratory analysis; testing kits using monoclonal antibodies.

    Named plant problems: TMV (viral), rose black spot (fungal), aphids 蚜虫 (insects).

    Ion deficiencies: too little nitrate → stunted growth (nitrate needed for amino acids/protein); magnesium deficiency → chlorosis (yellow leaves 缺绿 — magnesium needed to make chlorophyll).

    Defence responses: physical — cellulose cell walls, waxy cuticle, bark/dead layers; chemical — antibacterial chemicals, poisons; mechanical — thorns, hairs, drooping/curling leaves, mimicry.

    Vocabulary Train
    English
    aphids/ˈeɪfɪdz/
    chlorosis/ˈklɔːrəʊsiz/
    3.4

    Checklist before you call this topic done

    • Four pathogen types; three routes of spread; two ways to reduce each named disease's spread.
    • Recite the disease table: pathogen, spread, symptoms, control.
    • Four non-specific defences; three white-blood-cell actions.
    • Vaccination mechanism + population effect; antibiotic vs painkiller; why antibiotics fail on viruses.
    • Drug sources (foxglove, willow, Penicillium) and the preclinical/clinical stages with placebo and double-blind.
    • (HT, biology) Hybridoma production sequence and four monoclonal uses.
    • (Biology) Plant disease signs, identification methods, nitrate/magnesium deficiencies, three defence classes.
  • 4

    Bioenergetics

    4.1

    Bioenergetics: photosynthesis and respiration

    Plants capture the Sun's energy; every cell releases it again. This reference covers AQA GCSE Biology 8461, topic 4.4 Bioenergetics.

    How the exam treats this topic:

    • Paper 1 carries Bioenergetics. RP6: light intensity and the rate of photosynthesis using pondweed.
    • Limiting-factor graphs with two or three factors, the inverse square law and greenhouse economics are HT only.
    • Equations are word equations — know the symbol forms too (CO₂, H₂O, O₂, C₆H₁₂O₆).
    4.1

    Photosynthesis (4.4.1.1)

    Syllabus

    Photosynthesis (AQA 8461 statements 4.4.1.1-4.4.1.2, RP6).

    1. Write the photosynthesis word and symbol equations, and describe it as endothermic.
    2. Explain how light intensity, CO2 concentration and temperature limit the rate of photosynthesis, including interpreting limiting-factor graphs.
    3. (HT) Use the inverse-square relation between light intensity and distance, and reasons for greenhouse economics.
    4. Describe RP6: light intensity and the rate of photosynthesis with pondweed, its controls and the rate calculation.

    Source: Cambridge International syllabus

    $$\text{carbon dioxide} + \text{water} \xrightarrow{\ \text{light}\ } \text{glucose} + \text{oxygen}$$
    $$6\,\text{CO}_2 + 6\,\text{H}_2\text{O} \rightarrow \text{C}_6\text{H}_{12}\text{O}_6 + 6\,\text{O}_2$$

    Photosynthesis is an endothermic 吸热 reaction: energy is transferred from the environment to the chloroplasts by light.

    Vocabulary Train
    English
    endothermic/ˌendəʊˈθɜːmɪk/
    4.1

    Rate of photosynthesis and limiting factors (4.4.1.2)

    Syllabus

    Photosynthesis (AQA 8461 statements 4.4.1.1-4.4.1.2, RP6).

    1. Write the photosynthesis word and symbol equations, and describe it as endothermic.
    2. Explain how light intensity, CO2 concentration and temperature limit the rate of photosynthesis, including interpreting limiting-factor graphs.
    3. (HT) Use the inverse-square relation between light intensity and distance, and reasons for greenhouse economics.
    4. Describe RP6: light intensity and the rate of photosynthesis with pondweed, its controls and the rate calculation.

    Source: Cambridge International syllabus

    Rate of photosynthesis against one limiting factor at a time.
    Each curve rises then flattens where another factor limits.

    Rate increases with: light intensity, CO₂ concentration, temperature (to the enzyme optimum), and the amount of chlorophyll.

    Reading single-factor graphs: the flat top means something else has become the limiting factor 限制因素. (HT) On two- or three-factor graphs, decide which factor is limiting at each point.

    (HT) Inverse square law: doubling the distance from the lamp quarters the light intensity:

    $$\text{light intensity} \propto \frac{1}{\text{distance}^2}$$

    (HT) Greenhouse economics: adding heat, light or CO₂ raises the rate — but each costs money; the grower adds the cheapest factor that is limiting, up to the point where extra yield no longer pays.

    RP6 set-up: pondweed under an inverted funnel in a beaker, with a lamp at a measured distance.

    RP6: pondweed in water at different lamp distances; count the oxygen bubbles per minute (or collect the gas); control temperature and CO₂ (sodium hydrogencarbonate); repeat and mean; rate = bubbles ÷ time.

    Worked example. Bubbles: 30 per minute at 10 cm; at 20 cm the light intensity is a quarter, so expect about 8 per minute (if light is still limiting).

    Vocabulary Train
    English
    limiting factor/ˈlɪmɪtɪŋ ˈfæktə/
    4.1

    Uses of glucose (4.4.1.3)

    Syllabus

    Photosynthesis (AQA 8461 statements 4.4.1.1-4.4.1.2, RP6).

    1. Write the photosynthesis word and symbol equations, and describe it as endothermic.
    2. Explain how light intensity, CO2 concentration and temperature limit the rate of photosynthesis, including interpreting limiting-factor graphs.
    3. (HT) Use the inverse-square relation between light intensity and distance, and reasons for greenhouse economics.
    4. Describe RP6: light intensity and the rate of photosynthesis with pondweed, its controls and the rate calculation.

    Source: Cambridge International syllabus

    Glucose from photosynthesis is used for:

    • respiration;
    • converted to insoluble starch for storage;
    • fat or oil for storage;
    • cellulose for cell walls;
    • amino acids for protein — this also needs nitrate ions from the soil.
    4.2

    Respiration (4.4.2.1)

    Syllabus

    Respiration and metabolism (AQA 8461 statements 4.4.1.3, 4.4.2.1-4.4.2.3).

    1. Name five uses of glucose from photosynthesis.
    2. Compare aerobic and anaerobic respiration in muscle and yeast, with word equations, and fermentation's economic importance.
    3. Explain the body's response to exercise and (HT) oxygen debt and the liver's role.
    4. Define metabolism and list the reactions it includes.

    Source: Cambridge International syllabus

    Respiration is an exothermic 放热 reaction occurring continuously in living cells, transferring the energy for: building larger molecules, movement, and keeping warm.

    Aerobic Anaerobic (muscle) Anaerobic (plant/yeast)
    oxygen needed not needed not needed
    equation glucose + oxygen → CO₂ + water glucose → lactic acid glucose → ethanol + CO₂
    energy much more much less much less

    Anaerobic respiration in yeast is fermentation 发酵, economically important in bread (CO₂ makes it rise) and alcoholic drinks.

    Vocabulary Train
    English
    exothermic/eɡzəˈðɜːmɪk/
    fermentation/fɜːmənˈteɪʃn/
    4.2

    Response to exercise (4.4.2.2)

    Syllabus

    Respiration and metabolism (AQA 8461 statements 4.4.1.3, 4.4.2.1-4.4.2.3).

    1. Name five uses of glucose from photosynthesis.
    2. Compare aerobic and anaerobic respiration in muscle and yeast, with word equations, and fermentation's economic importance.
    3. Explain the body's response to exercise and (HT) oxygen debt and the liver's role.
    4. Define metabolism and list the reactions it includes.

    Source: Cambridge International syllabus

    During exercise the heart rate, breathing rate and breath volume increase to deliver more oxygenated blood to muscles. If oxygen supply is insufficient, muscles switch to anaerobic respiration: incomplete glucose oxidation builds up lactic acid 乳酸 → fatigue; an oxygen debt 氧债 builds.

    (HT) Blood carries lactic acid to the liver, which converts it back to glucose. The oxygen debt is the extra oxygen needed after exercise to react with and remove the accumulated lactic acid.

    Vocabulary Train
    English
    oxygen debt/ˈɒksɪdʒn det/
    lactic acid/ˈlæktɪk ˈæsɪd/
    4.2

    Metabolism (4.4.2.3)

    Syllabus

    Respiration and metabolism (AQA 8461 statements 4.4.1.3, 4.4.2.1-4.4.2.3).

    1. Name five uses of glucose from photosynthesis.
    2. Compare aerobic and anaerobic respiration in muscle and yeast, with word equations, and fermentation's economic importance.
    3. Explain the body's response to exercise and (HT) oxygen debt and the liver's role.
    4. Define metabolism and list the reactions it includes.

    Source: Cambridge International syllabus

    Metabolism 代谢 is the sum of all reactions in a cell or body; respiration fuels them. It includes:

    • glucose → starch, glycogen, cellulose;
    • glycerol + 3 fatty acids → lipids;
    • glucose + nitrate ions → amino acids → proteins;
    • respiration;
    • breakdown of excess protein → urea for excretion.
    Vocabulary Train
    English
    Metabolism/məˈtæbəlɪzəm/
    4.2

    Checklist before you call this topic done

    • Write the photosynthesis word and symbol equations; say endothermic + light→chloroplasts.
    • Explain the four rate factors; read flattening single-factor graphs; (HT) inverse square law and greenhouse economics.
    • Describe RP6 with its controls and the rate calculation.
    • List five uses of glucose (with nitrate for protein).
    • Compare aerobic with both anaerobic equations; name fermentation's two products and uses.
    • Exercise: three increases; lactic acid and oxygen debt; (HT) the liver's role.
    • Define metabolism with its five strands.
  • 5

    Homeostasis and response

    5.1

    Homeostasis and response: keeping conditions steady

    • Homeostasis 稳态 is the regulation of the internal conditions of a cell or organism, to maintain optimum conditions for enzyme action and all cell functions, in response to internal and external changes.
    • The body controls blood glucose concentration, body temperature and water levels.
    • Every automatic control system has: receptors (detect stimuli), coordination centres (brain, spinal cord, pancreas — receive and process information) and effectors (muscles or glands — bring about the response that restores optimum levels).
    • Nervous responses are fast and short-lived; hormonal responses are slower but act for longer.
    Vocabulary Train
    English
    Homeostasis/ˌhəʊmiːəˈstɑːsiz/
    5.1

    Homeostasis and the nervous system (4.5.1–4.5.2.1, RP7)

    Syllabus

    Homeostasis and the nervous system (AQA 8461 statements 4.5.1-4.5.2.1, RP7).

    1. Define homeostasis and name the three conditions the body controls.
    2. Describe receptors, coordination centres and effectors, and the stimulus-receptor-coordinator-effector-response pathway.
    3. Explain the reflex arc, including sensory neurone, synapse, relay neurone and motor neurone, and why reflexes are automatic and rapid.
    4. Describe RP7: the effect of a factor on human reaction time, with controls and data handling.

    Source: Cambridge International syllabus

    The pathway: stimulus → receptor → coordinator (CNS: brain + spinal cord) → effector (muscle contracts / gland secretes) → response.

    Information passes along cells called neurones 神经元 as electrical impulses. The CNS coordinates the response of effectors.

    The reflex arc: stimulus to receptor, sensory neurone with cell body, relay neurone in the CNS, motor neurone to the effector, with synapses between neurones.

    The reflex arc — automatic and rapid protection that does not involve the conscious part of the brain:

    stimulus → receptor → sensory neurone → synapse → relay neurone (in CNS) → synapse → motor neurone → effector → response.

    At a synapse 突触 the electrical impulse arrives at the end of a neurone and a chemical is released; it diffuses across the gap and triggers an electrical impulse in the next neurone.

    RP7 — reaction time: plan and investigate the effect of a factor (e.g. caffeine) on human reaction time. Drop a ruler between a partner's finger and thumb; measure the catch distance; convert to time (or use a computer test); control variables (same hand, same height); repeat and take a mean. Interpret reaction-time data from graphs and tables.

    Vocabulary Train
    English
    neurone/ˈnjuːrəʊn/
    synapse/ˈsɪnæps/
    5.2

    The brain, the eye and temperature — biology only (4.5.2.2–4.5.2.4)

    Syllabus

    The brain, the eye and body temperature — biology only (AQA 8461 statements 4.5.2.2-4.5.2.4).

    1. Identify cerebral cortex, cerebellum and medulla with their functions, and (HT) difficulties of investigating and treating the brain.
    2. Relate eye structures to functions and explain accommodation for near and distant objects.
    3. Explain myopia and hyperopia and their correction with lenses and new technologies.
    4. Explain how vasodilation, sweating, vasoconstriction and shivering control body temperature (HT in context).

    Source: Cambridge International syllabus

    The brain (HT extra)

    Identify on a diagram: cerebral cortex (consciousness, memory, language), cerebellum (balance, coordination of movement), medulla (heartbeat, breathing).

    (HT) Difficulties of investigating and treating the brain: it is complex and delicate, easily damaged, and hard to access. Mapping methods: studying patients with brain damage, electrically stimulating regions, and MRI scanning. Evaluate benefits and risks of brain procedures.

    The eye

    Vertical section of the eye: sclera, cornea, iris, lens, ciliary muscles, suspensory ligaments, retina and optic nerve.

    Identify and explain: retina 视网膜 (receptor cells sensitive to light intensity and colour), optic nerve (carries impulses from retina to brain), sclera (strong outer coat), cornea (refracts light), iris (coloured muscles controlling pupil size — reflex adaptation to dim/bright light), ciliary muscles and suspensory ligaments (control lens shape).

    Accommodation 视觉调节 — changing lens shape to focus:

    near object distant object
    ciliary muscles contract relax
    suspensory ligaments loosen pulled tight
    lens thicker, refracts strongly thin, refracts slightly

    Defects: myopia 近视 (short sight — distant objects focus in front of the retina; corrected with a concave lens), hyperopia 远视 (long sight — near objects focus behind the retina; convex lens). Treatments: spectacle lenses, contact lenses, laser surgery to reshape the cornea, replacement lens.

    Control of body temperature

    The thermoregulatory centre in the brain has receptors sensitive to blood temperature; skin receptors send impulses to it.

    • Too hot: blood vessels dilate (vasodilation 血管舒张) — more blood near the surface transfers energy to the environment; sweat 汗液 produced — evaporating sweat transfers energy away.
    • Too cold: blood vessels constrict (vasoconstriction 血管收缩); sweating stops; skeletal muscles contract (shivering — respiration transfers energy to warm the blood).

    (HT) Explain in context how each mechanism lowers or raises temperature back to the optimum.

    Vocabulary Train
    English
    retina/ˈretɪnə/
    accommodation/əˌkɒməˈdeɪʃn/
    myopia/maɪˈəʊpɪə/
    hyperopia/ˌhaɪpəˈrəʊpɪə/
    vasodilation/ˌvæsədɪˈleɪʃn/
    vasoconstriction/ˌvæsəkənˈstrɪkʃn/
    sweat/swet/
    5.3

    Hormonal coordination in humans (4.5.3)

    Syllabus

    Hormonal coordination in humans (AQA 8461 statements 4.5.3).

    1. Describe the endocrine system: glands, hormones, target organs, and the six named glands.
    2. Explain insulin control of blood glucose, (HT) glucagon and negative feedback, and compare Type 1 and Type 2 diabetes.
    3. (Bio) Describe water and nitrogen balance: kidneys, filtration and selective reabsorption, (HT) ADH, and dialysis vs transplant.
    4. (HT) Explain FSH, LH, oestrogen and progesterone interactions in the menstrual cycle, contraception methods and IVF.
    5. (HT) Explain adrenaline and thyroxine, with negative feedback.

    Source: Cambridge International syllabus

    The endocrine system is glands that secrete hormones 激素 directly into the bloodstream; blood carries them to target organs. Slower than nerves but longer-lasting. Identify on a body diagram: pituitary gland (brain's 'master gland'), pancreas, thyroid, adrenal gland, ovary, testes.

    Blood glucose is monitored and controlled by the pancreas:

    • Too high → pancreas secretes insulin 胰岛素 → glucose moves from blood into cells; in liver and muscle cells excess glucose is converted to glycogen 糖原 for storage.
    • (HT) Too low → pancreas secretes glucagon 胰高血糖素 → glycogen converted back to glucose, released into the blood. Insulin–glucagon is a negative feedback 负反馈 cycle.

    Diabetes: Type 1 — pancreas fails to produce enough insulin; uncontrolled high blood glucose; treated with insulin injections. Type 2 — body cells no longer respond to insulin; treated with a carbohydrate-controlled diet and exercise regime; obesity is a risk factor. Interpret graphs of blood glucose with and without diabetes.

    Water and nitrogen balance — biology only

    Water leaves via the lungs (exhalation) and the skin (sweat, with ions and urea) — no control over these. Excess water, ions and urea are removed by the kidneys in urine. Cells that lose or gain too much water by osmosis do not work efficiently. (HT) Excess amino acids from the diet are deaminated in the liver: ammonia (toxic) → urea 尿素 for safe excretion.

    The kidneys filter the blood and selectively reabsorb glucose, some ions and water. (HT) If the blood is too concentrated, the pituitary releases ADH 抗利尿激素, which makes the kidney tubules more permeable, so more water is reabsorbed — negative feedback again.

    Kidney failure: treated by transplant or dialysis — blood flows between partially permeable membranes in dialysis fluid with the right water/ion concentrations, so waste diffuses out while glucose and useful substances are retained; evaluate mechanical device vs transplant.

    Hormones in human reproduction

    Oestrogen 雌激素 (ovary) — main female hormone; at puberty eggs mature and one is released about every 28 days (ovulation 排卵). Testosterone 睾酮 (testes) — stimulates sperm production.

    (HT) The menstrual cycle:

    Hormone Source Role
    FSH pituitary causes an egg to mature in the ovary (in the follicle)
    LH pituitary stimulates the release of the egg (ovulation)
    Oestrogen ovary (follicle) maintains and builds the uterus lining; stimulates LH surge
    Progesterone ovary (corpus luteum) maintains the uterus lining; inhibits FSH and LH
    Hormone levels through the 28-day menstrual cycle: FSH early, an oestrogen rise, the day-14 LH surge and ovulation, then progesterone.

    (HT) Interpret hormone-level graphs across the cycle: FSH starts follicle growth → oestrogen rises → LH surge triggers ovulation (about day 14) → progesterone keeps the lining thick until it falls and the cycle restarts.

    Contraception — evaluate hormonal and non-hormonal methods: oral contraceptives (inhibit FSH so no eggs mature), slow-release progesterone injection/implant/patch, barrier methods (condoms, diaphragm), intrauterine devices, spermicides, abstaining when an egg may be in the oviduct, sterilisation.

    Infertility (HT): 'fertility drugs' (FSH + LH) stimulate eggs to mature. IVF: FSH and LH stimulate several eggs → eggs collected and fertilised with sperm in the laboratory → embryos grow to tiny balls of cells → one or two transferred to the uterus. Evaluate: emotionally/physically stressful, low success rates, risk of multiple births.

    Negative feedback (HT): adrenaline (adrenal glands, fear/stress) increases heart rate and delivery of oxygen and glucose to brain and muscles — 'fight or flight'. Thyroxine (thyroid) stimulates the basal metabolic rate and is important in growth and development; its level is controlled by negative feedback. Interpret simple negative-feedback diagrams.

    Vocabulary Train
    English
    hormone/ˈhɔːməʊn/
    insulin/ˈɪnsjuːlɪn/
    glycogen/ˈɡlaɪkədʒn/
    glucagon/ˈɡluːkæɡən/
    negative feedback/ˈneɡətɪv ˈfiːdbæk/
    urea/juːˈrɪə/
    ADH/ˌeɪ diː ˈeɪtʃ/
    oestrogen/ˈiːstrədʒn/
    ovulation/ˌɒvjʊˈleɪʃn/
    testosterone/teˈstɒstərəʊn/
    5.4

    Plant hormones — biology only (4.5.4)

    Syllabus

    Plant hormones — biology only (AQA 8461 statements 4.5.4, RP8).

    1. Explain phototropism and gravitropism by unequal auxin distribution in shoots and roots.
    2. Describe RP8: the effect of light or gravity on newly germinated seedlings, with length measurements and labelled drawings.
    3. (HT) Describe uses of auxins, gibberellins and ethene in agriculture, horticulture and the food industry.

    Source: Cambridge International syllabus

    Plants produce hormones to coordinate and control growth and responses to light (phototropism 向光性) and gravity (gravitropism 向地性/geotropism). Unequal distribution of auxin 生长素 causes unequal growth rates in roots and shoots — shoots bend towards light; roots grow downwards.

    RP8: investigate the effect of light or gravity on newly germinated seedlings — record as length measurements and careful labelled biological drawings.

    (HT) Gibberellins initiate seed germination; ethene controls cell division and fruit ripening.

    (HT) Uses: auxins as weed killers, rooting powders and to promote growth in tissue culture; ethene to control ripening during storage and transport; gibberellins to end seed dormancy, promote flowering and increase fruit size. Consider the effect of weed killers on biodiversity.

    Vocabulary Train
    English
    auxin/ˈɔːksɪn/
    phototropism/ˌfəʊtəʊˈtrəʊpɪzəm/
    gravitropism/ˈɡrævɪtrəʊpɪzəm/
    5.4

    Checklist before you call this topic done

    • Define homeostasis; receptor–coordination centre–effector said in order; reflex arc drawn with synapse.
    • Eye parts and accommodation table cold; myopia vs hyperopia with corrections.
    • Temperature: vasodilation/sweat vs vasoconstriction/shivering, in context (HT).
    • Insulin and (HT) glucagon with negative feedback; Type 1 vs Type 2 treatments.
    • (Bio) kidney filtration + selective reabsorption; (HT) ADH; dialysis vs transplant.
    • (HT) FSH–oestrogen–LH–progesterone interactions and graph; contraception list; IVF steps; adrenaline and thyroxine.
    • (Bio) tropisms with auxin; RP8; (HT) the three hormone uses.
  • 6

    Inheritance, variation and evolution

    6.1

    Inheritance, variation and evolution: passing it on

    • Sexual reproduction mixes genetic information; asexual reproduction clones it. Meiosis halves chromosomes for gametes; fertilisation restores them.
    • DNA → genes → alleles → phenotype: the Punnett square turns this into probabilities.
    • Natural selection changes inherited characteristics across generations. Selective breeding, genetic engineering and cloning (biology only) use different mechanisms. Fossils and resistant bacteria provide evolutionary evidence; classification uses evidence of relationships.
    6.1

    Reproduction, DNA and genomes (4.6.1.1–4.6.1.5)

    Syllabus

    Reproduction, DNA and genomes (AQA 8461 statements 4.6.1.1-4.6.1.5).

    1. Compare sexual and asexual reproduction, with the named organisms that use both.
    2. Explain how meiosis halves the chromosome number and fertilisation restores it, and trace embryo development.
    3. Describe DNA, genes and the genome, and discuss the importance of the human genome.
    4. (Bio) Describe DNA's nucleotide structure and the base code; (HT) protein synthesis and the effect of mutations.

    Source: Cambridge International syllabus

    Sexual reproduction — fusion of male and female gametes (sperm + egg in animals; pollen + egg in flowering plants). Meiosis forms gametes; mixing of genetic information gives variety in offspring. Asexual reproduction — one parent, no fusion, mitosis only: genetically identical offspring (clones 克隆).

    Meiosis: one parent cell's chromosomes are copied, then two divisions give four genetically different gametes, each with a single set of chromosomes.

    Meiosis 减数分裂: in reproductive organs, copies of the genetic information are made first, then the cell divides twice to form four gametes, each with a single set of chromosomes — all genetically different. Fertilisation restores the normal number; the new cell divides by mitosis and cells differentiate as the embryo develops.

    (Bio) Sexual vs asexual: sexual gives variation — a survival advantage if the environment changes, and the variation selective breeding uses; asexual needs no mate (time and energy efficient), is faster, and produces many identical offspring when conditions are favourable. Malarial parasites: asexual in the human host, sexual in the mosquito; many fungi: asexual spores + sexual; strawberry plants: sexual seeds + asexual runners; daffodils: bulb division.

    DNA and the genome: DNA is a polymer of two strands forming a double helix, held in the nucleus as chromosomes. A gene 基因 is a small section of DNA that codes for a sequence of amino acids → a specific protein. The genome 基因组 is the entire genetic material of the organism. Importance of the human genome: searching for genes linked to disease; understanding and treating inherited disorders; tracing human migration patterns from the past.

    (Bio) DNA structure: a polymer of four different nucleotides 核苷酸 — common sugar + phosphate group + one of four bases — A 腺嘌呤, C 胞嘧啶, G 鸟嘌呤, T 胸腺嘧啶; alternating sugar–phosphate backbone; a sequence of three bases codes for one amino acid, and the base order controls the amino-acid order of the protein.

    (HT Bio) Protein synthesis: on ribosomes, from a template; carrier molecules bring specific amino acids in the correct order; the chain folds into a unique shape that lets the protein work as an enzyme, hormone or structural protein (e.g. collagen). In complementary strands C pairs with G, T with A. Mutations change the base sequence: a mutation may leave the protein unchanged, alter it slightly, or change its shape so an enzyme no longer fits its substrate or a structural protein loses strength. Variants in non-coding DNA can switch genes on and off, changing how genes are expressed.

    Apply the reproduction and DNA knowledge

    Try first — strawberries. Seeds form after fertilisation; runners form without gamete fusion. Identify the two routes and explain which may help a population survive a new disease.

    Worked reasoning. Seeds result from sexual reproduction: meiosis makes gametes and fertilisation mixes genetic information. Variation means some offspring may resist the disease. Runners form by mitosis from one parent: clones, apart from mutation. Asexual reproduction needs no mate and is fast in favourable conditions; neither route guarantees survival.

    Try first — chromosome number. A human cell has 46 chromosomes before meiosis. Predict the number of gametes, their chromosome number, the number after fertilisation and the division growing the embryo.

    Worked reasoning. DNA is copied before two divisions form four gametes, each with 23 chromosomes (one set). DNA copying does not change the count to 92 chromosomes at that point. Fertilisation combines 23 + 23 = 46; mitosis increases embryo cell number and cells differentiate. The diagram models chromosome numbers, not the stages of meiosis.

    Try first — scale and code. Distinguish a gene, chromosome and genome. (HT Bio) Write the bases complementary to A C G T and explain whether a mutation must stop an enzyme working.

    Worked reasoning. A gene is a DNA section coding an amino-acid sequence for a protein; a chromosome contains a long DNA molecule and many genes; a genome is all the organism’s genetic material. Complementary bases are T G C A. At ribosomes, a template and carrier molecules determine the amino-acid order; the chain folds. A mutation may leave the protein unchanged or change its shape and function. Non-coding variants can change whether genes are expressed.

    Vocabulary Train
    English
    meiosis/meɪˈəʊsɪs/
    clone/kləʊn/
    gene/dʒiːn/
    genome/ˈdʒiːnəʊm/
    nucleotide/ˈnjuːklɪɒtaɪd/
    6.2

    Genetic inheritance, disorders and sex determination (4.6.1.6–4.6.1.8)

    Syllabus

    Genetic inheritance, disorders and sex determination (AQA 8461 statements 4.6.1.6-4.6.1.8).

    1. Define gamete, chromosome, gene, allele, dominant, recessive, homozygous, heterozygous, genotype and phenotype.
    2. Complete and interpret Punnett squares and family trees, with ratios and probabilities.
    3. Explain polydactyly and cystic fibrosis inheritance and judge embryo screening issues.
    4. Determine sex with the XX/XY cross, including ratios.

    Source: Cambridge International syllabus

    Learn the terms: gamete 配子 (sex cell), chromosome 染色体 (DNA structure), gene (section coding a protein), allele 等位基因 (a form of a gene), dominant 显性 (expressed with one copy), recessive 隐性 (expressed only with two), homozygous 纯合 (two same alleles), heterozygous 杂合 (two different), genotype 基因型 (alleles present), phenotype 表现型 (characteristics expressed).

    Single-gene examples: fur colour in mice; red-green colour blindness. Most characteristics result from multiple genes interacting.

    Punnett squares and crosses: complete a Punnett square, extract ratios (e.g. 3:1, 1:1) and probabilities from genetic crosses and family trees. (HT) Construct a cross from parent genotypes and predict outcomes with probability.

    Inherited disorders: polydactyly 多指症 (extra fingers or toes) — dominant allele; cystic fibrosis 囊性纤维化 (a disorder of cell membranes) — recessive allele. Make informed judgements about the economic, social and ethical issues of embryo screening.

    Left: the XX × XY sex cross giving a 1:1 ratio. Right: two cystic-fibrosis carriers (Cc × Cc), with a 1/4 probability of cc.

    Sex determination: body cells have 23 pairs of chromosomes; 22 pairs control characteristics, one pair carries the sex genes — female XX, male XY. A sex cross (X×X, X×Y) gives a 1:1 ratio, 50 % chance each.

    From terms to family inference and probabilities

    Try first — terminology. D causes dominant polydactyly; d does not. Classify Dd and predict its phenotype and gamete alleles.

    Worked reasoning. Dd is heterozygous (two different alleles); DD and dd are homozygous. Genotype means the alleles present; phenotype means the characteristics expressed. Dd is affected because one D is expressed. “Dominant” does not mean stronger or more common. Gametes contain D or d, not Dd.

    Guided family inference — adapted from AQA June 2024 Paper 2H Q06.2. An affected father and unaffected mother have an unaffected son. Deduce the father’s genotype before reading the answer.

    Worked reasoning. The mother and son are dd. The father passed d to his son, but must also carry D because he is affected. Therefore he is Dd. The child’s genotype supplies evidence that the father’s phenotype alone cannot provide.

    Construct a cross (HT). Two unaffected CF carriers are Cc and Cc. Each produces gametes C or c. Combining them gives CC, Cc, Cc, cc: probability of CF = 1/4; probability of being a carrier = 1/2. Carriers do not have CF in this recessive model. The separate XX × XY cross gives XX, XX, XY, XY: probability 1/2 each in the GCSE sex-determination model.

    Exam transfer — adapted from AQA June 2024 Paper 2H Q06.3. An affected mother Dd and unaffected father dd have three unaffected sons. Construct a cross and predict whether the fourth child will be affected.

    Worked reasoning. Egg alleles D/d combine with sperm alleles d/d to give Dd, dd, Dd, dd. Two of four equally likely combinations are affected: probability = 2/4 = 1/2. Earlier births do not change this probability. The four boxes describe possible combinations, not four promised children.

    Evaluate — teacher-written screening scenario. Screening can identify embryos with the CF genotype, but treatment is costly and some embryos may not be used. A biological benefit is identifying cc embryos to inform the couple’s decisions. Cost can limit access and creates funding choices. Some families object to selecting or not using embryos; others prioritise reducing inherited disease. An informed judgement uses the stated evidence and recognises different values.

    Vocabulary Train
    English
    gamete/ˈɡæmiːt/
    chromosome/ˈkrəʊməsəʊm/
    allele/əˈliːl/
    dominant/ˈdɒmɪnənt/
    recessive/rɪˈsesɪv/
    homozygous/ˌhɒməˈzɪɡəs/
    heterozygous/ˌhetrəˈzɪɡəs/
    genotype/ˈdʒenətaɪp/
    phenotype/ˈfenətaɪp/
    polydactyly/ˌpɒlɪˈdæktili/
    cystic fibrosis/ˈsɪstɪk fɪˈbrəʊsɪs/
    6.3

    Variation, selective breeding, genetic engineering and cloning (4.6.2)

    Syllabus

    Variation, selective breeding, genetic engineering and cloning (AQA 8461 statements 4.6.2).

    1. Describe the genome-environment interaction and the three causes of variation, and the role of mutation.
    2. Explain evolution by natural selection and the formation of new species.
    3. Describe selective breeding, its uses and the inbreeding risk.
    4. Describe genetic engineering with (HT) its main steps, benefits, risks and objections.
    5. (Bio) Describe tissue culture, cuttings, embryo transplants and adult cell cloning.

    Source: Cambridge International syllabus

    Variation 变异 — differences between individuals in a population — comes from genes inherited (genetic), conditions of development (environmental), or a combination. There is usually extensive genetic variation within a population; all genetic variants arise from mutations — most have no effect on the phenotype, some influence it, very few determine it. A rare mutation giving a new phenotype suited to an environmental change can change the species rapidly.

    Evolution: a change in the inherited characteristics of a population over time, through natural selection 自然选择, which may result in a new species. All species evolved from simple life forms that first developed over three billion years ago. Natural selection: variation → the phenotype best suited to the environment survives and breeds → those characteristics are passed on. If two populations become so different they cannot interbreed to produce fertile offspring, two new species have formed.

    Selective breeding (artificial selection): choose parents with the desired characteristic from a mixed population → breed → choose the best offspring → repeat over many generations. Uses: disease resistance in food crops; animals with more meat or milk; dogs with gentle natures; large or unusual flowers. Risk: inbreeding 近交 — breeds prone to disease or inherited defects.

    Genetic engineering: modifying the genome by introducing a gene from another organism to give a desired characteristic — GM crops resistant to insect attack or herbicides (increased yields); bacteria engineered to make human insulin. (HT) Steps: enzymes isolate the required gene → inserted into a vector (bacterial plasmid or virus) → vector inserts the gene into the required cells → transferred early in development so the organism develops with the desired characteristic. Weigh benefits (medicine, agriculture) against risks (wild-flower and insect populations, unexplored health effects) and ethical objections.

    (Bio) Cloning: tissue culture — small groups of plant cells grown into identical new plants (preserving rare species; nurseries); cuttings — simple, older gardeners' method; embryo transplants — splitting unspecialised cells of a developing animal embryo into identical embryos placed in host mothers; adult cell cloning — nucleus removed from an unfertilised egg cell → nucleus from an adult body cell inserted → electric shock makes it divide into an embryo → ball of cells placed in the womb.

    Apply variation, selection and biotechnology

    Start with variation — teacher-written seedling case. Seedlings differ in inherited disease resistance. Genetically identical plants grow to different heights under different light conditions. Identify genetic and environmental variation, then explain what may happen during a disease outbreak.

    Worked reasoning. Resistance alleles provide genetic variation; light conditions can cause environmental differences in height. Phenotype often depends on both. Resistant plants may survive the disease and reproduce more successfully, passing favourable alleles to offspring. Over generations, resistance alleles can become more common. Mutations change DNA; they do not occur because an organism needs a particular change.

    Exam transfer — adapted from AQA June 2024 Paper 2H Q01.2. Describe natural selection using insects that already vary in inherited insecticide resistance.

    Worked reasoning. The insecticide is a selection pressure: more susceptible insects die. Resistant survivors reproduce and pass resistance alleles to offspring. The population’s inherited characteristics change across generations; an individual does not evolve just by being sprayed. Speciation requires populations to become unable to interbreed to produce fertile offspring.

    Compare mechanisms — teacher-written crop case. A grower wants inherited disease resistance without transferring a gene. Select resistant parents from a mixed population, breed them, select resistant offspring and repeat over many generations. This is selective breeding, not natural selection or genetic engineering. Repeatedly breeding close relatives risks inherited defects and reduced genetic variation.

    Linked exam explanation — adapted from AQA June 2024 Paper 2H Q09.1. GM soya plants resist glyphosate. Explain how spraying the field can increase yield.

    Worked reasoning. Glyphosate kills weeds but the resistant crop survives. Less competition gives the crop more light, water and mineral ions. More light and water can support photosynthesis, producing glucose for respiration and building biomass. Nitrate ions support amino-acid and protein synthesis. Link resources to growth and harvested yield; “GM means higher yield” omits the mechanism. These are authored explanation points checked against the scheme, not an official model or a guaranteed score.

    HT — follow a gene. Enzymes isolate a required gene (for example, human insulin). Insert it into a vector such as a bacterial plasmid; use the vector to introduce it into the required cells. The modified cells express the gene and produce the substance. For a developing animal or plant, introduce the gene early so the organism develops with the desired characteristic.

    Evaluate — teacher-written GM scenario. An insect-resistant crop suffers less target-pest damage, but a study reports fewer nearby non-target insects without establishing why. Reduced damage may improve harvest. The insect decline raises a food-web concern; compare modified and unmodified fields while accounting for habitat and pesticide use. Association alone does not prove the inserted gene caused the decline. Judge the particular modification and evidence.

    Biology — choose and order cloning methods. A nursery can use tissue culture to grow plants from small groups of cells, or cuttings from a parent plant. Embryo transplants split cells before they specialise and place identical embryos into host mothers. Adult cell cloning removes an unfertilised egg’s nucleus, inserts an adult body-cell nucleus, stimulates division with an electric shock, and transfers the ball of cells to a womb. The adult body-cell donor supplies the nuclear genetic information. Environmental differences can still affect a clone’s phenotype.

    Vocabulary Train
    English
    variation/ˌveərɪˈeɪʃn/
    natural selection/ˈnætʃərəl sɪˈlekʃn/
    inbreeding/ˈɪnbriːdɪŋ/
    adenine/ˈædəniːn/
    cytosine/ˈsaɪtəsaɪn/
    guanine/ˈɡwɑːnaɪn/
    thymine/ˈθaɪmaɪn/
    6.4

    Evolution, genetics and evidence (4.6.3, biology only)

    Syllabus

    Evolution, genetics and evidence (AQA 8461 statements 4.6.3, biology only).

    1. Describe Darwin's theory, why it was accepted only gradually, and Lamarck's theory.
    2. Describe Wallace's and Mendel's contributions and the growth of genetics.
    3. Explain fossils and their formation, why the record is incomplete, extinction causes and evolutionary trees.
    4. Explain antibiotic-resistant bacteria and how to slow resistance.

    Source: Cambridge International syllabus

    (Bio) Darwin's theory: wide variation within a species; individuals best suited to the environment survive to breed; the useful characteristics are passed on. Published in On the Origin of Species (1859). Accepted only gradually: it challenged the idea that God made all living things; insufficient evidence at publication; the mechanism of inheritance was unknown for another 50 years. Lamarck's rival theory — that changes acquired during an organism's lifetime are inherited — is now known to be wrong in almost all cases.

    (Bio) Wallace: independently proposed evolution by natural selection; joint 1858 publications with Darwin prompted Darwin to publish; best known for warning colouration and pioneering work on speciation — the steps by which new species arise.

    (Bio) Mendel and the growth of genetics: mid-19th-century breeding experiments showed each characteristic is inherited through 'units' passed unchanged to descendants; late 19th century — chromosomes observed in cell division; early 20th century — the units behave like chromosomes → genes on chromosomes; mid-20th century — DNA structure determined and gene function worked out. Mendel's work was unrecognised in his lifetime.

    (Bio) Evidence for evolution: genes show characteristics pass to offspring; fossils; antibiotic resistance in bacteria.

    (Bio) Fossils form when parts do not decay (a decay condition is absent), when parts are replaced by minerals as they decay, or as preserved traces (footprints, burrows, rootlet traces). Early soft-bodied life left few traces, mostly destroyed by geological activity — so science cannot be certain how life began. Extinction means no individuals of a species remain — causes include new diseases, new predators, competition, environmental change, catastrophic events. Evolutionary trees use current classification data and fossil data.

    (Bio) Resistant bacteria: mutations produce genetic variants; some are resistant to a particular antibiotic. Susceptible bacteria are killed, while resistant survivors reproduce quickly and pass on resistance genes. The resistant strain becomes more common and can spread (for example, MRSA). This population change is evidence for evolution. Resistance can make infection harder to treat; it does not mean every antibiotic is ineffective or that people have no immune defence. Reducing inappropriate prescribing and unnecessary agricultural antibiotic use reduces avoidable selection pressure. Developing new antibiotics takes time and resources.

    Try first — resistance explanation. A population contains susceptible and resistant variants before antibiotic exposure. Explain why resistant bacteria become more common, and correct “the antibiotic makes every bacterium mutate because it needs resistance”.

    Worked reasoning. Genetic variation already exists; mutations are not directed by need. Antibiotic exposure selects survivors. Resistant bacteria reproduce and pass resistance genes to offspring, increasing their share of the population. Selection and inheritance explain the change without claiming that every individual becomes resistant.

    Use historical and fossil evidence

    Explain the history (Biology). Darwin and Wallace independently proposed natural selection; their joint writings appeared in 1858 and Darwin published his book in 1859. Acceptance was gradual: the theory challenged prevailing creation beliefs, some scientists found the evidence insufficient, and inheritance mechanisms were unknown. Mendel’s plant breeding suggested inherited units. His work’s importance was recognised after his death; later chromosome behaviour, genes on chromosomes and DNA structure connected these units to physical mechanisms.

    Apply speciation — teacher-written case. A barrier separates a population into different habitats. Different selection pressures favour different variants; survivors reproduce and pass favourable alleles to offspring. Mutations supply genetic variants. Over many generations the populations may diverge. Separation alone does not prove a new species: inability to interbreed to produce fertile offspring is the stated species criterion.

    Interpret evidence — teacher-written fossil case. A footprint preserved in rock is a trace fossil; a shell replaced by minerals illustrates mineral replacement. Conditions that prevent decay can also preserve remains. Soft-bodied organisms may leave no trace, and geological activity destroys fossils. An incomplete record still supplies evidence of past organisms and change. A species missing from one site is not necessarily extinct: extinction means no living individuals remain anywhere.

    Read the diagram. Trace A and B back to their first shared fork: this is their most recent common ancestor. A and C share the older ancestor of all four species, so A and B are more closely related. This is a schematic without a time scale; do not infer dates from branch lengths or relationships from vertical spacing. Trees use classification and fossil evidence.

    6.5

    Classification of living organisms (4.6.4)

    Syllabus

    Classification of living organisms (AQA 8461 statement 4.6.4).

    1. Describe the Linnaean system and binomial naming.
    2. Describe the three-domain system of Woese and what drove it.
    3. Interpret evolutionary trees using classification and fossil data.

    Source: Cambridge International syllabus

    Linnaeus: classification by structure and characteristics into kingdom, phylum, class, order, family, genus, species; organisms named by the binomial system (genus + species).

    Three-domain system (Carl Woese), from chemical-analysis evidence: archaea (a distinct domain of prokaryotes, including many organisms from extreme environments), bacteria (true bacteria), eukaryota (protists, fungi, plants, animals). Improvements in microscopes and biochemistry drove the new models.

    An evolutionary tree: branches from a common ancestor; identify the first shared fork when tracing two tips back to their most recent common ancestor; drawn lengths here are not a time scale.

    Evolutionary trees show how scientists believe organisms are related — interpret them using classification and fossil data.

    Apply classification. In Panthera leo and Panthera tigris, Panthera identifies the shared genus; the second word distinguishes the species within it. The ranks are kingdom → phylum → class → order → family → genus → species. New microscopy and chemical-analysis evidence can reveal relationships that external appearance does not show, leading to revised classification. Woese’s three domains are archaea, bacteria and eukaryota.

    Final retrieval. Without the answers, explain (1) how 23-chromosome gametes restore 46 at fertilisation; (2) the next affected-child probability for Dd × dd after three unaffected births; (3) how antibiotic exposure changes a bacterial population. Check: two gamete sets combine; the cross gives a 1/2 probability independently at each birth; resistant survivors reproduce and pass on resistance genes. Then use the earlier worked examples to retrieve gene transfer, cloning order and common ancestry.

    6.5

    Checklist before you call this topic done

    • Meiosis (four gametes, halved number) vs mitosis; sexual vs asexual advantages with named organisms.
    • All ten genetics terms; Punnett squares with ratios; polydactyly vs cystic fibrosis; XX/XY cross 1:1.
    • (Bio) DNA nucleotides and bases; (HT) protein synthesis and mutations.
    • Variation three sources; natural selection sequence; selective breeding steps and inbreeding risk; (HT) genetic engineering steps; (Bio) four cloning methods.
    • (Bio) Darwin/Wallace/Mendel history, fossil formation and why the record is incomplete, MRSA story, Linnaeus ranks and the three domains.
  • 7

    Ecology

    7.1

    Ecology: communities, cycles and human impacts

    • The Sun's energy passes through ecosystems; carbon and water cycle between the living and non-living world.
    • Communities compete and depend on each other; adaptations fit organisms to their conditions.
    • Human activity — waste, land use, deforestation, global warming — threatens biodiversity, and trophic-level biology (bio only) explains why food chains are short.
    7.1

    Adaptations, interdependence and competition (4.7.1)

    Syllabus

    Adaptations, interdependence and competition (AQA 8461 statement 4.7.1).

    1. Describe the levels of organisation in an ecosystem and define ecosystem, community, biotic and abiotic.
    2. Suggest the factors for which plants and animals compete, and explain interdependence.
    3. Explain how given abiotic and biotic factor changes affect a community.
    4. Explain structural, behavioural and functional adaptations, and extremophiles.

    Source: Cambridge International syllabus

    An ecosystem 生态系统 is the interaction of a community of living organisms (biotic 生物因子) with the non-living (abiotic factor 非生物因子) parts of their environment. Levels of organisation: individual → population → community → ecosystem.

    Competition 竞争: plants compete for light, space, water and mineral ions; animals compete for food, mates and territory. Interdependence 相互依赖: each species depends on others for food, shelter, pollination, seed dispersal — remove one species and the whole community can be affected.

    Abiotic factors affecting a community: light intensity, temperature, moisture levels, soil pH and mineral content, wind intensity and direction, carbon dioxide levels (plants), oxygen levels (aquatic animals). Biotic factors : availability of food, new predators arriving, new pathogens, one species outcompeting another until numbers fall too low to breed. Explain the effect of a change in any of these from given data.

    Adaptations 适应性 — features that enable survival in normal conditions — are structural (shape/body), behavioural (actions) or functional (processes, e.g. camouflage chemistry, venom). Extremophiles 极端微生物 live in extreme environments — high temperature, pressure or salt — e.g. bacteria in deep-sea vents.

    Vocabulary Train
    English
    ecosystem/ˈiːkəʊsɪstəm/
    biotic factor/baɪˈɒtɪk ˈfæktə/
    abiotic factor/ˌæbɪˈɒtɪk ˈfæktə/
    competition/ˌkɒmpəˈtɪʃn/
    interdependence/ˌɪntədɪˈpendəns/
    adaptation/ˌædæpˈteɪʃn/
    extremophile/ekˈstreməfaɪl/
    7.2

    Organisation of an ecosystem and material cycles (4.7.2, RP9/RP10)

    Syllabus

    Organisation of an ecosystem and material cycles (AQA 8461 statement 4.7.2, RP9/RP10).

    1. Use food-chain vocabulary from producer to tertiary consumer and interpret predator-prey cycles.
    2. Describe RP9 sampling with transects and quadrats, with mean, mode and median.
    3. Explain the carbon and water cycles and the role of microorganisms.
    4. (Bio) Explain how temperature, water and oxygen affect decay rate, with RP10 and biogas.

    Source: Cambridge International syllabus

    Photosynthetic organisms are the producers 生产者 of biomass for life on Earth. Food chains: producer (green plant/alga making glucose by photosynthesis) → primary consumers 初级消费者 → secondary consumers 次级消费者 → tertiary consumers 三级消费者. A predator-prey cycle: prey numbers rise first, the predator population follows with a delay, and both oscillate.

    Predators kill and eat prey; in a stable community their numbers rise and fall in cycles — interpret the classic predator–prey graph (prey rises first, predator follows).

    Sampling (RP9): transects and quadrats measure the distribution and abundance of species; calculate mean, mode, median of abundance; plot graphs with suitable scales.

    The carbon cycle: photosynthesis takes CO2 into plants, feeding passes carbon to animals, decay by decomposers returns it, with respiration and combustion releasing CO2.

    Carbon cycle: returns carbon from organisms to the atmosphere as carbon dioxide for photosynthesis — respiration (plants, animals, decomposers), decay, combustion. Water cycle: evaporation and precipitation provide fresh water before it drains to the sea. Microorganisms recycle materials — returning carbon to the atmosphere as CO₂ and mineral ions to the soil. The nitrogen cycle is NOT required.

    (Bio) Decomposition (RP10): temperature, water and oxygen affect the rate of decay. Gardeners and farmers provide optimum conditions for rapid decay 腐解 of waste into compost — a natural fertiliser. Anaerobic decay produces methane — biogas generators. RP10: effect of temperature on the rate of decay of fresh milk by measuring pH change.

    (HT Bio) Environmental change: temperature, water availability, atmospheric-gas composition — changes may be seasonal, geographic or human-caused — shift the distribution of species.

    Vocabulary Train
    English
    producer/prəˈdjuːsə/
    primary consumer/ˈpraɪməri kənˈsuːmə/
    secondary consumer/ˈsekəndəri kənˈsuːmə/
    tertiary consumer/ˈtɜːʃjəri kənˈsuːmə/
    decomposition/ˌdiːkɒmpəˈzɪʃn/
    7.3

    Biodiversity and human interactions (4.7.3)

    Syllabus

    Biodiversity and human interactions (AQA 8461 statement 4.7.3).

    1. Define biodiversity and explain why it stabilises ecosystems.
    2. Explain how waste, land use, deforestation and global warming reduce biodiversity.
    3. Describe programmes that maintain biodiversity.

    Source: Cambridge International syllabus

    Biodiversity 生物多样性 is the variety of all different species on Earth or within an ecosystem; it stabilises ecosystems by reducing the dependence of one species on another, and our own future relies on maintaining it.

    • Waste management: population growth and living standards increase resource use and waste → pollution 污染 in water (sewage, fertiliser, toxic chemicals), air (smoke, acidic gases) and on land (landfill, toxic chemicals) — killing plants and animals.
    • Land use: building, quarrying, farming and dumping waste reduce land for other species; destroying peat bogs for garden compost destroys habitat and biodiversity, and decaying or burnt peat releases CO₂.
    • Deforestation in tropical areas: land for cattle and rice fields, crops for biofuels.
    • Global warming: rising atmospheric CO₂ and methane contribute to global warming; describe biological consequences (distribution shifts, migration changes, biodiversity loss).

    Maintaining biodiversity — programmes reducing negative human effects: breeding programmes for endangered species; protection and regeneration of rare habitats; field margins and hedgerows reintroduced in single-crop areas; reduced deforestation and CO₂ emissions; recycling rather than landfill.

    Vocabulary Train
    English
    biodiversity/ˌbaɪəʊdaɪˈvɜːsɪti/
    pollution/pəˈluːʃn/
    7.4

    Trophic levels and food security — biology only (4.7.4–4.7.5)

    Syllabus

    Trophic levels and food security, biology only (AQA 8461 statements 4.7.4-4.7.5).

    1. Name the trophic levels, describe decomposers and construct pyramids of biomass.
    2. Explain biomass loss between levels and calculate transfer efficiency.
    3. Describe the biological factors threatening food security.
    4. Evaluate farming techniques, sustainable fisheries and the role of biotechnology.

    Source: Cambridge International syllabus

    Trophic levels: 1 producers (plants, algae); 2 primary consumers (herbivores); 3 secondary consumers (carnivores eating herbivores); 4 tertiary consumers (carnivores eating carnivores). Apex predators have no predators. Decomposers secrete enzymes onto dead material and absorb the small soluble food molecules.

    A pyramid of biomass with producers at the bottom and about 10 percent of biomass passing to each level above.

    Pyramids of biomass: trophic level 1 at the bottom; construct from data. Transfer of biomass: producers transfer ~1 % of incident light energy into biomass; only ~10 % of biomass passes from each level to the next — losses from egested faeces (not all ingested material is absorbed) and waste (CO₂ and water from respiration, water and urea in urine); glucose used in respiration. Calculate efficiency by percentage or fraction of mass.

    Food security 粮食安全 — having enough food for the population — is threatened by: rising birth rate; changing diets in developed countries; new pests and pathogens; environmental changes (famine when rains fail); the cost of agricultural inputs; conflicts affecting water or food availability.

    Farming techniques improve efficiency by restricting energy transfer from food animals to the environment — limiting movement and controlling temperature; high-protein feeds increase growth. Weigh these against ethical objections to intensive farming.

    Sustainable fisheries: maintain fish stocks where breeding continues — control net size and fishing quotas .

    Role of biotechnology: culturing microorganisms for food — Fusarium fungus grown on glucose syrup in aerobic conditions produces mycoprotein 菌蛋白 (protein-rich, vegetarian); GM bacteria produce insulin; GM crops such as golden rice add food or nutritional value.

    Vocabulary Train
    English
    food security/fuːd sɪˈkjʊərɪti/
    mycoprotein/ˈmaɪkəprəʊtiːn/
    7.4

    Checklist before you call this topic done

    • Definitions chain: ecosystem, community, abiotic/biotic factors with examples.
    • Plant vs animal competition; interdependence consequences; three adaptation types + extremophiles.
    • Food-chain vocabulary; predator–prey cycle read off a graph; RP9 sampling with mean/mode/median.
    • Carbon and water cycles with decomposers' role; (bio) decay factors + biogas + RP10.
    • Four human threats + five biodiversity programmes named.
    • (Bio) Trophic levels, pyramid shape, 10 % rule with efficiency calculation.
    • (Bio) Six food-security threats; efficiency farming, net size and quotas, mycoprotein, golden rice.

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