Skip to content

TS.4 · Partition derivatives, energy fluctuations and heat capacity

GRE · GRE Subject Test · GRE 物理 · 知识点 35

训练
35.1

配分函数导数、能量涨落与热容

A thermal energy gap can keep heat capacity small at both low and high temperatures, even while the excited-state probability keeps increasing.

Prerequisites: 20.

  • Obtain canonical mean energy and free energy from a fixed energy spectrum
  • Relate energy variance to constant-volume heat capacity with fixed-spectrum conditions
  • Evaluate entropy and low/high-temperature limits for an original finite-level model
35.2

Differentiate a fixed spectrum

For a system exchanging energy with a bath at T while N and V remain fixed, let β=1/(kBT). Sum Z=Σ_i g_i exp(−βE_i) over energy levels with their degeneracies. Level probability is g_i exp(−βE_i)/Z; mean energy U is the probability-weighted energy sum. Differentiating a temperature-independent spectrum gives U=−∂lnZ/∂β. Keep the energy gap and degeneracies fixed during the derivative. Writing Δ=kBT ln3 to describe one evaluation temperature must not be read as making Δ change with T. For N independent distinguishable identical two-level subsystems, Z_total=z^N and U_total=N u. Indistinguishable particles and interactions need their own state counting rather than this product assumption.

35.3

Identify the thermodynamic quantity

The Helmholtz free energy 亥姆霍兹自由能 is F=−kBT lnZ. Canonical entropy follows from S=kB(lnZ+βU), equivalently −kBΣ p_j ln p_j over individual microstates. Constant-volume heat capacity is C_V=(∂U/∂T)_V,N. These quantities carry different units and describe different derivatives. Adding a constant energy offset ε to every state multiplies Z by exp(−βε), increases U and F by ε, and leaves probabilities, entropy and heat capacity unchanged when ε is independent of T. A negative chosen mean energy is therefore not evidence of a negative heat capacity. Use the same energy reference in the probabilities and thermodynamic expressions.

词汇 训练
English 中文 拼音
Helmholtz free energy/ˈhelmhəʊltz friː ˈenədʒi/ 亥姆霍兹自由能 hài mǔ huò zī zì yóu néng
35.4

Relate fluctuations and response

The second β derivative of lnZ gives variance Var(E)=⟨E²⟩−U². For the same fixed-spectrum canonical model, C_V=Var(E)/(kBT²), so C_V/kB=β²Var(E). Nonnegative variance implies nonnegative C_V within these conditions. The denominator includes kB, not kB², when heat capacity retains its ordinary J/K units. This fluctuation formula concerns the canonical energy distribution; it does not say each particle has exactly the mean energy. For independent subsystems variances add, while means add too. Relative energy fluctuations typically shrink like 1/√N when the mean and per-subsystem variance remain finite and nonzero.

35.5

Test finite-level temperature limits

For one ground state at E=0 and one excited state at fixed E=Δ>0, put x=Δ/(kBT). Then z=1+e^(−x), p_exc=1/(1+e^x), u=Δp_exc and C/kB=x²e^x/(1+e^x)². At low T, excitation and heat capacity vanish exponentially. At high T, p_exc tends to one half and energy saturates, so heat capacity tends to zero again. Entropy rises from zero for the unique ground state toward kB ln2 as the two states become equiprobable. The resulting finite-temperature heat-capacity peak is specific to the finite-level model; it is not the constant classical oscillator value. Ground-state degeneracy or additional levels would change the limiting entropy and temperature response.

35.6

Worked method

Hold the two energy levels 0 and Delta fixed when differentiating the partition function 配分函数.

$$Z=1+e^{-\beta\Delta},\quad U=-\partial_\beta\ln Z=\frac\Delta{1+e^{\beta\Delta}}.$$
$$\operatorname{Var}(E)=\partial_\beta^2\ln Z =\frac{\Delta^2e^{\beta\Delta}}{(1+e^{\beta\Delta})^2},\quad C_V=\operatorname{Var}(E)/(k_BT^2).$$
At $\beta\Delta=\ln3$, excited probability is 1/4, mean energy Delta/4, variance $3\Delta^2/16$ and $C_V/k_B=3(\ln3)^2/16=0.2263$. Degeneracy, if present, belongs in Z before differentiation.

Partition derivatives, energy fluctuations and heat capacity: GRE original diagram
Partition derivatives, energy fluctuations and heat capacity: original GRE teaching diagram.
词汇 训练
English 中文 拼音
partition function/pɑːˈtɪʃn ˈfʌŋkʃn/ 配分函数 pèi fēn hán shù
35.7

Check conditions and vocabulary

Hold Δ fixed when differentiating, include degeneracies in Z, and use energy variance rather than the square of mean energy in the heat-capacity formula.

energy fluctuation 能量涨落: Canonical spread of energy about its ensemble mean, quantified by the energy variance.

Helmholtz free energy: Thermodynamic potential F=U−TS, equal to −kBT lnZ for the canonical ensemble.

词汇 训练
English 中文 拼音
energy fluctuation/ˈenədʒi ˌflʌktʃuːˈeɪʃn/ 能量涨落 néng liàng zhǎng luò

该知识点的互动课程

逐步完成,配合即时检查练习。

更多 GRE · GRE Subject Test · GRE 物理 知识点

登录或创建账户

IGCSE、A-Level 与 AP