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TS.3 · Thermal transport, calorimetry and expansion

GRE · GRE Subject Test · GRE 物理 · 知识点 34

训练
34.1

热输运、量热法与热膨胀

Two wall layers in series carry the same steady heat rate 热流率, but their temperature drops need not be equal.

Prerequisites: 4.

  • Combine conductive thermal resistances and distinguish heat rate from heat flux
  • Balance sensible and latent heat 潜热 with stated isolation and heat-capacity conditions
  • Calculate free thermal expansion and constrained thermal stress with their limits
词汇 训练
English 中文 拼音
latent heat/ˈleɪtənt hiːt/ 潜热 qián rè
heat rate 热流率 rè liú lǜ
34.2

Add thermal resistances

For one-dimensional steady conduction through a uniform slab, Fourier’s law gives heat flux q_x=−κ dT/dx. With constant conductivity κ, area A, length L and hot-to-cold temperature difference ΔT, heat rate is Qdot=κAΔT/L. Define thermal resistance 热阻 R_th=L/(κA), measured in K/W; temperature drop is Qdot R_th. Series layers without internal sources carry the same Qdot and their resistances add. Parallel paths at the same endpoint temperatures have heat rates that add, so inverse resistances add. Heat flux is rate per area, W/m², and need not match between layers of different area. Interface contact resistance and heat leakage must be included if specified.

词汇 训练
English 中文 拼音
thermal resistance/ˈθɜːml rɪˈzɪstəns/ 热阻 rè zǔ
34.3

Balance sensible and latent energy

Heat capacity C=dQ/dT depends on the thermodynamic path and is not the same as specific heat c per mass. For a material interval without a phase transition, Q=∫mc(T)dT, or mcΔT when c is constant. In an isolated calorimeter, sum the energy changes of all objects, including the container when relevant, and set the sum to zero. At a phase transition at its equilibrium temperature, added energy can change phase fraction rather than temperature: Q=mℓ uses latent heat ℓ in J/kg. First supply the sensible heat to reach the transition, then budget latent heat. Do not let a simple weighted-temperature average predict an impossible temperature when melting or freezing is part of the process.

34.4

Check expansion constraints

For a freely expanding rod and small temperature change, ΔL≈αL₀ΔT with linear expansion coefficient α. For an isotropic solid with small strain, each dimension acquires factor 1+αΔT, so ΔA/A≈2αΔT and ΔV/V≈3αΔT. A hole expands with the surrounding material as if its missing region had expanded too. These relations assume a nearly constant coefficient and no mechanical constraint; anisotropic crystals need directional coefficients. If an elastic rod is prevented from changing length, its mechanical strain cancels thermal strain. With tensile stress positive, σ≈−YαΔT during heating, where Y is Young’s modulus. This small-strain estimate requires elastic response without yielding or buckling.

34.5

Choose the transport model

Conduction transfers energy through a temperature gradient, convection transports it with moving matter, and thermal radiation can cross a vacuum. For a surface at T facing large surroundings at T_env, a simple grey-body model gives net radiative rate εσ_SB A(T⁴−T_env⁴). Use absolute kelvin in these fourth powers, rather than Celsius values. A lumped body whose internal temperature remains nearly uniform can obey C dT/dt=−hA(T−T_env) under Newton cooling with constant h. Then the temperature excess decays with τ=C/(hA), rather than the entire Celsius or kelvin temperature decaying toward zero. This approximation requires sufficiently small internal gradients; a conduction-limited body needs a spatial temperature model.

34.6

Worked method

Two slabs in series carry the same steady heat rate. Let resistances be 0.08 and 0.24 K/W. Boundary temperatures are 60 and 20 degrees Celsius.

$$\dot Q=\Delta T/(R_1+R_2)=(40\,\mathrm K)/(0.32\,\mathrm{K/W})=125\,\mathrm W.$$
$$\Delta T_1=\dot Q R_1=(125\,\mathrm W)(0.08\,\mathrm{K/W})=10\,\mathrm K.$$
The interface is 50 degrees Celsius when slab 1 touches the hot side. Heat rate has watt units; flux divides it by area.

Thermal transport, calorimetry and expansion: GRE original diagram
Thermal transport, calorimetry and expansion: original GRE teaching diagram.
34.7

Check conditions and vocabulary

Keep W separate from W/m², include the calorimeter or latent energy when needed, and do not use free-expansion length together with constrained-stress assumptions.

thermal resistance: Temperature difference per steady heat-transfer rate, measured in K/W.

latent heat: Energy transferred during a phase change at its transition temperature; specific latent heat is per mass.

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