The probability scale
Introduced| English | Meaning |
|---|---|
| probability/ˌprɒbəˈbɪlɪti/ | A numerical measure of how likely an event is, ranging from zero to one. |
| fair/feə/ | Unbiased: a fair coin has equally likely sides, and a fair die has equally likely faces. |
| outcomes/ˈaʊtkʌmz/ | A possible or actual result of an event, process or trial. |
| random/ˈrændəm/ | Describing outcomes governed by chance rather than being individually predictable with certainty. |
| complement/ˈkɒmplɪmənt/ | The set of elements in a specified universal set that do not belong to the given set. |
Two labels do not mean equal chances
- A club has 10 raffle tickets: 3 win a prize and 7 do not. One ticket is chosen so that each ticket has the same chance. Winning and losing are two possible labels, but they are not equally likely.
- Probability 概率 measures how likely an event is. Winning has probability $\dfrac{3}{10}=0.3=30\%$. Count the equally likely tickets, rather than just the two labels.
Ten raffle tickets are equally likely to be chosen. Three win a prize and seven do not. Find the probability of winning, as a decimal.
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Three winning tickets out of 10 give 3/10 =0.3.
Place a chance on the scale
- Probabilities lie from $0$ to $1$, including both ends. A probability of $0$ is impossible, $1$ is certain and $\dfrac{1}{2}=0.5=50\%$ is an even chance. Values below $0$ or above $1$ are invalid.
- For one roll of an ordinary six-sided die, a $7$ is impossible and a result from $1$ to $6$ is certain. A fair 公平 coin has equal chances of heads and tails; merely having two possible results does not guarantee an even chance.

The probability scale
Place a probability between 0 and 1. The default 0.5 represents an even chance, such as heads on a fair coin.
What is the probability of an impossible event?
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Impossible has probability 0; certain has probability 1.
Write the probability of an even chance as a decimal.
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One half is 0.5, or 50%.
A certain event has probability 100.
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The probability is 1, which is 100%, not 100.
If a coin has two possible results, heads and tails, each must have probability 0.5.
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Equal chances require a fair-coin model. A biased coin can still have just two results.
Which number can be a probability?
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A probability lies between 0 and 1, including both ends.
Count equally likely outcomes 结果
- A bag contains 3 red and 5 blue counters. Assume each of the 8 counters has the same chance of being chosen. The favourable outcomes for red are the 3 red counters.
- Use the total number of counters in the denominator, not the number of colours or the number of blue counters. The fraction can be left exact or converted to a decimal or percentage.
The probability of red is $\dfrac{3}{3+5}=\dfrac{3}{8}=0.375=37.5\%$. The eight individual counters are equally likely; the two colours are not.
A counter is chosen at random from 3 red and 5 blue counters, each equally likely. The probability of red is a/8. Find a.
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The 3 red counters are favourable out of 8 counters.
For equally likely outcomes, probability = favourable outcomes / ______ outcomes.
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Include all outcomes in the denominator, including those that do not meet the event.
A probability is 3/8. Write it as a percentage, entering the number before the percent sign.
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3 ÷8 =0.375, then multiply by 100 to obtain 37.5%.
Count sectors, not colour names
- An ideal fair spinner has 8 equal sectors: 4 blue, 3 red and 1 green. Each sector has probability $\dfrac{1}{8}$, so blue has probability $\dfrac{4}{8}=\dfrac{1}{2}$ and green has probability $\dfrac{1}{8}$.
- There are three colours, but each colour does not have probability $\dfrac{1}{3}$. Equal chances belong to the sectors in this model, and a colour can cover several sectors.
Use favourable divided by total only when the outcomes you count are equally likely. A random 随机 result need not have equal chances: a biased coin still has only heads and tails.
An ideal fair spinner has 8 equal sectors: 4 blue, 3 red and 1 green. Find the probability of red, as a decimal.
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Three of the 8 equal sectors are red, so 3/8 =0.375.
An ideal fair spinner has 8 equal sectors: 4 blue, 3 red and 1 green. What is the probability of blue?
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Count the 4 blue sectors out of 8, not one colour out of 3.
Read the whole total from a table
- This table records how each of 30 students travels to school. Choose one student at random, giving each student an equal chance. The chance they use the bus is $\dfrac{9}{30}=\dfrac{3}{10}$.
- Check what the table counts. Use the total number of students, not the four travel methods. Students who do not walk include all three other rows: $9+6+3=18$.
| Travel method | Students |
|---|---|
| Walk | 12 |
| Bus | 9 |
| Bicycle | 6 |
| Car | 3 |
| Total | 30 |
A class has 12 walkers, 9 bus users, 6 cyclists and 3 car users. Each student uses exactly one method. A student is chosen at random with equal chances. The probability they use the bus is 9/d. Find d.
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Use all students: 12 +9 +6 +3 =30.
A class has 12 walkers, 9 bus users, 6 cyclists and 3 car users. Each student uses exactly one method. Choose one of the 30 students at random with equal chances. Find the probability they do not walk, as a decimal.
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The 18 non-walkers are the 9 bus users, 6 cyclists and 3 car users; 18/30 =0.6.
Not an event includes every other result
- The complement 补集 of an event means all outcomes where it does not happen. An event and its complement cover every possibility without overlap, so their probabilities add to $1$.
- A bag has 2 red, 3 blue and 5 green counters, each equally likely to be chosen. Not blue includes red and green: $\dfrac{2+5}{10}=\dfrac{7}{10}$. It does not mean only red.
The probability a parcel is late is $0.28$. The probability it is not late is $1-0.28=0.72$, or $72\%$. Work in one form throughout: $100\%-28\%=72\%$ gives the same answer.
A counter is chosen at random from 3 red and 5 blue counters, each equally likely. The probability of not red is a/8. Find a.
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All 5 blue counters count as not red.
The probability a parcel is late is 0.28. Find the probability it is not late, as a decimal.
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Late and not late are complementary: 1 −0.28 =0.72.
A counter is chosen with equal chances from 2 red, 3 blue and 5 green counters. Which is the probability of not blue?
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Not blue includes the 2 red and 5 green counters.
Account for every possible outcome
- If a counter must be red, blue or green, those three colour probabilities add to $1$. If red has probability $0.35$ and blue has probability $0.25$, green must have probability $1-0.35-0.25=0.40$.
- Check a proposed model before using it. Three exhaustive colour probabilities of $0.4$, $0.45$ and $0.3$ add to $1.15$, so they cannot describe the bag. Each individual number is in range, but the total is wrong.
A counter must be red, blue or green. Red has probability 0.35 and blue has probability 0.25. Find the probability of green, as a decimal.
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Subtract both stated probabilities from 1: 1 −0.35 −0.25 =0.40.
A bag contains only red, blue and green counters. Their probabilities could be 0.4, 0.45 and 0.3 respectively.
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These mutually exclusive and exhaustive probabilities sum to 1.15 rather than 1.
Read the notation: Extended
- $\text{P}(A)$ means the probability of event $A$. A letter names the event: for example, let $A$ mean “the chosen counter is blue”.
- $A'$ means “not $A$”, so $\text{P}(A')=1-\text{P}(A)$. If $\text{P}(A)=0.3$, then $\text{P}(A')=0.7$. Core questions can use words instead; this notation is not required at Core.
Extended: if P(A)=0.3, what is P(A')?
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A' is not A, so subtract 0.3 from 1.
Show what you counted
- For a fresh problem, identify the possible outcomes and why they are equally likely. Count the favourable ones and the full total, then give a fraction, decimal or percentage.
- For “not”, include every other outcome or subtract from $1$. Check that the answer lies between $0$ and $1$ and that a complete list of separate outcomes has total probability $1$.
A box has 6 red, 4 blue and 5 green counters, each equally likely to be chosen. Find the probability of blue and the probability of not blue. Explain both totals.
Changing the target event does not remove any counters from the selection total.
An ideal fair spinner has 10 equal sectors: 5 yellow, 2 blue and 3 green. Kim says each colour has probability 1/3 because there are three colours. Correct Kim and find the probability of not yellow.
Three labels can cover unequal numbers of equally likely outcomes.
In a club, 8 members walk, 7 take a bus and 5 cycle. Each uses exactly one method. A member is chosen at random with equal chances. Find the probability they take a bus, then the probability they do not cycle.
Use all 20 members in each denominator.
Keep the model and the total clear
- Impossible is $0$, certain is $1$ and an even chance is $\dfrac{1}{2}$. A probability of $1$ is the same as $100\%$, not $100$.
- Count favourable outcomes out of the full total when the counted outcomes are equally likely. Equal numbers of labels do not guarantee equal chances.
- An event and “not the event” have probabilities that add to $1$. The complement may contain several different outcomes.
Review: a counter is chosen with equal chances from 4 red and 6 blue counters. What is the probability of red?
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Four of the 10 equally likely counters are red.