- describe the formation of polyesters: (a) the reaction between a diol and a dicarboxylic acid or dioyl chloride (b) the reaction of a hydroxycarboxylic acid
- describe the formation of polyamides: (a) the reaction between a diamine and a dicarboxylic acid or dioyl chloride (b) the reaction of an aminocarboxylic acid (c) the reaction between amino acids
- deduce the repeat unit of a condensation polymer obtained from a given monomer or pair of monomers
- identify the monomer(s) present in a given section of a condensation polymer molecule
Polymerisation
A-Level Chemistry · Topic 35
7:58
Polymerisation (A2)
Look at three very different things. A nylon rope. A plastic drinks bottle. The protein in your own hair. They seem to have nothing in common. Yet all three…
English narration · English + 中文 subtitles burned in
35.1
Condensation polymerisation
Syllabus
Source: Cambridge International syllabus
In condensation polymerisation 缩合聚合, monomers join into a long chain 链 and a small molecule 小分子 (such as water or $\text{HCl}$) is lost each time a new bond forms. Each monomer needs two reactive groups 反应基团, so the chain can grow at both ends.

Polyesters
A polyester 聚酯 has many ester links 酯键 along its chain. You can make one from:
- a diol 二醇 (two $\text{–OH}$ groups) and a dicarboxylic acid 二羧酸 (two $\text{–COOH}$ groups), or a dioyl chloride 二酰氯.
- a single hydroxycarboxylic acid 羟基羧酸, which has both an $\text{–OH}$ and a $\text{–COOH}$.

Polyamides
A polyamide 聚酰胺 has many amide links 酰胺键. You can make one from:
- a diamine 二胺 (two $\text{–NH}_2$ groups) and a dicarboxylic acid or a dioyl chloride.
- a single aminocarboxylic acid 氨基羧酸, or from amino acids 氨基酸 joining together (proteins 蛋白质 are natural polyamides).

Repeat units and monomers
The repeat unit 重复单元 of a condensation polymer contains parts of both monomers, minus the atoms lost as the small molecule. To find the monomers 单体 from a section of polymer, break the chain at each ester or amide link, then add back $\text{–OH}$ and $\text{–H}$ (or $\text{–Cl}$).

Worked example. A polymer chain contains repeating $\text{–CONH–}$ links. Name the type of polymer, identify the monomers, and give the small molecule lost. A $\text{–CONH–}$ link is an amide, so this is a polyamide made by condensation polymerisation. To find the monomers, break the chain at each amide link and give the cut ends their atoms back: the carbon side takes $\text{–OH}$, making a dicarboxylic acid, and the nitrogen side takes $\text{–H}$, making a diamine. The small molecule lost at each link is water (or $\text{HCl}$, if an acyl dichloride was used in place of the acid). Each monomer must have two functional groups, or the chain could never keep growing - if the monomer you propose has only one, you have broken the chain in the wrong place.
Condensation polymer route
Watch monomers join while a small molecule leaves each time.
| English |
|---|
| condensation polymerisation/kɒndenˈseɪʃn ˌpɒlɪməraɪˈzeɪʃn/ |
| chain |
| small molecule/smɔːl ˈmɒlɪkjuːl/ |
| reactive groups |
| polyester/ˌpɒlɪˈestə/ |
| ester links |
| diol/dɪˈɒl/ |
| dicarboxylic acid/ˌdɪkɑːbəkˈsɪlɪk ˈæsɪd/ |
| dioyl chloride |
| hydroxycarboxylic acid |
| polyamide/ˌpɒlɪˈeɪmaɪd/ |
| amide links |
| diamine/ˈdaɪəmaɪn/ |
| aminocarboxylic acid |
| amino acid/əˈmiːnəʊ ˈæsɪd/ |
| proteins/ˈprəʊtiːnz/ |
| repeat unit/rɪˈpiːt ˈjuːnɪt/ |
| monomer/ˈmɒnəʊmə/ |
35.2
Predicting the type of polymerisation
Syllabus
- predict the type of polymerisation reaction for a given monomer or pair of monomers
- deduce the type of polymerisation reaction which produces a given section of a polymer molecule
Source: Cambridge International syllabus
| Clue | Type |
|---|---|
| the monomer has a C=C double bond 碳碳双键, and nothing else is lost | addition polymerisation 加成聚合 |
| each monomer has two functional groups 官能团, and a small molecule is lost; the chain has ester or amide links | condensation polymerisation |

Polymerisation type lab
Classify monomers by whether they form addition or condensation polymers.
| English |
|---|
| C=C double bond |
| addition polymerisation/əˈdɪʃn ˌpɒlɪməraɪˈzeɪʃn/ |
| functional groups |
35.3
Degradable polymers
Syllabus
- recognise that poly(alkenes) are chemically inert and can therefore be difficult to biodegrade
- recognise that some polymers can be degraded by the action of light
- recognise that polyesters and polyamides are biodegradable by acidic and alkaline hydrolysis
Source: Cambridge International syllabus
- poly(alkene)s 聚烯烃 are chemically inert 惰性的 — they have only strong, non-polar 非极性的 C–C and C–H bonds, so they are hard to biodegrade 生物降解 and last a long time.
- some polymers are made so that light can break them down (they are photodegradable 可光降解的).
- polyesters and polyamides are biodegradable 可生物降解, because their ester and amide links can be broken by acidic or alkaline 碱性的 hydrolysis 水解.
Common mistakes.
- Drawing a condensation polymer's repeat unit with the full monomers. Remove the atoms lost as water or $\text{HCl}$ at each link, and show the bonds at both ends as continuation bonds across the brackets.
- Losing water when a dioyl chloride is used. A dioyl chloride loses $\text{HCl}$, not water.
- Breaking the chain in the wrong place to find the monomers. Cut through the C–O of the ester or the C–N of the amide (between C=O and O/N), not next to it.
- Calling a polymer with a C=C monomer a condensation polymer because the backbone looks long. If nothing is lost, it is addition polymerisation.
- Saying poly(alkene)s are biodegradable because they are "organic". Their non-polar C–C and C–H bonds give no site for hydrolysis, so they persist; only the ester and amide links of condensation polymers hydrolyse.
Degradable polymer route
Follow how polymer structure controls breakdown.
| English |
|---|
| poly(alkene)/ˈpɒlɪ/ |
| inert/ɪˈnɜːt/ |
| non-polar/nɒn ˈpəʊlə/ |
| biodegrade/ˌbaɪəʊdɪˈɡreɪd/ |
| photodegradable/ˌfəʊtəʊdɪˈɡreɪdəbl/ |
| biodegradable/ˌbaɪəʊdɪˈɡreɪdəbl/ |
| alkaline/ˈælkəlaɪn/ |
| hydrolysis/haɪˈdrɒləsɪs/ |
35.3
Exam tips
- Condensation polymers (polyesters, polyamides) form with loss of a small molecule ($\text{H}_2\text{O}$ or HCl) — draw the repeat unit and the lost molecule.
- Identify the monomers from the polymer by breaking the ester or amide link — a common question.
- Predict the type from the monomers: a $\text{C}=\text{C}$ gives addition; two functional groups give condensation.
- Polyesters and polyamides are hydrolysable (more degradable); addition polymers are not.
Interactive lessons on this topic
Work through it step by step, with instant-check exercises.