Sequences · Suites
| English | Français |
|---|---|
| sequence/ˈsiːkwəns/ | séquence |
| term-to-term rule/tɜːm tə tɜːm ruːl/ | règle terme à terme |
| common difference/ˈkɒmən ˈdɪfrəns/ | différence constante |
| nth term/ˌenˌtiːˈeɪtʃ tɜːm/ | terme n-ième |
| quadratic sequence/kwɒˈdrætɪk ˈsiːkwəns/ | suite quadratique |
| geometric sequence/ˌdʒiːəʊˈmetrɪk ˈsiːkwəns/ | suite géométrique |
| common ratio/ˈkɒmən ˈreɪʃɪəʊ/ | rapport constant |
Predicting the future
- A sunflower adds a ring of petals following the Fibonacci pattern: 1, 1, 2, 3, 5, 8, 13, …
- Sequences · Suites 数列 are patterns in numbers. Once you know the rule, you can predict any term — even the millionth.
Term-to-term rule 递推规则
- The simplest sequences add (or subtract) a fixed amount each time: $2, 5, 8, 11, \dots$ goes up by $3$.
- This is the term-to-term rule (the common difference 公差).
Romanesco broccoli: self-similar spirals form a natural number pattern
Sequences · Suites
uₙ = a + (n − 1)d
An arithmetic sequence adds the same step each time; the sum · somme grows steadily. · Une suite arithmétique ajoute toujours le même pas ; la somme augmente régulièrement.
The nth term 通项 (position-to-term rule)
- For a linear · linéaire sequence (constant difference $d$), the nth term is $dn + c$.
- $2, 5, 8, 11, \dots$: difference $d = 3$, first term $= 2$, so $3n - 1$.
- Check: $n=1 \Rightarrow 3(1)-1 = 2$ ✓; $\;n=4 \Rightarrow 3(4)-1 = 11$ ✓.
Finding c. The sequence starts at $2$ when $n=1$: $3(1) + c = 2 \Rightarrow c = -1$. So the nth term is $3n - 1$.
The nth term of 2, 5, 8, 11, … is 3n − 1. What is the 10th term? · Le terme n-ième de 2, 5, 8, 11, … est 3n − 1. Quel est le 10ème terme ?
3 × 10 − 1 = 30 − 1 = 29.
For a linear sequence going up by 3 each time, the nth term contains: · Pour une suite linéaire augmentant de 3 à chaque fois, le terme n-ième contient :
A constant difference of 3 means the nth term is 3n adjusted by a constant. · Une différence constante de 3 signifie que le terme n-ième est 3n ajusté par une constante.
The nth term of 4, 7, 10, 13, … is 3n + ______. · Le terme n-ième de 4, 7, 10, 13, … est 3n + ______.
3(1) + c = 4 → c = 1. The nth term is 3n + 1. · 3(1) + c = 4 → c = 1. Le terme n-ième est 3n + 1.
Simple quadratic sequences 二次数列
- When the first differences change but the second differences are constant, it's a quadratic sequence.
- $2, 5, 10, 17, \dots$: first differences $3, 5, 7$; second differences $2, 2$.
- The · Le $n^2$ coefficient is half the second difference: $\dfrac{2}{2} = 1$, so the $n^2$ term is $n^2$.
- Adjust: $n^2 + 1$ gives $2, 5, 10, 17$. ✓
Number lines show patterns too: in a quadratic sequence, the gaps between terms grow steadily.
Half the second difference. The · Le $n^2$ coefficient is $\dfrac{\text{second difference}}{2}$, not the second difference itself. For $2, 5, 10, 17$ the second difference is $2$, giving $n^2$ (not $2n^2$).
The nth term of 2, 5, 10, 17, … is n² + 1. What is the 5th term? · Le terme n-ième de 2, 5, 10, 17, … est n² + 1. Quel est le 5ème terme ?
5² + 1 = 25 + 1 = 26.
In a quadratic sequence, the second differences are constant. · Dans une suite quadratique, les secondes différences sont constantes.
The first differences change steadily, but the second differences (differences of differences) are constant. · Les premières différences changent régulièrement, mais les secondes différences (différences des différences) sont constantes.
Geometric sequences 等比数列
- Each term is multiplied by a fixed ratio: $3, 6, 12, 24, \dots$ (multiply by 2 each time).
- The nth term is $a \times r^{n-1}$, where $a$ is the first term and $r$ is the common ratio 公比.
- $3 \times 2^{n-1}$: $\;n=1 \Rightarrow 3$, $\;n=4 \Rightarrow 3 \times 8 = 24$. ✓
The nth term of 3, 6, 12, 24, … is 3 × 2^(n−1). What is the 6th term? · Le terme n-ième de 3, 6, 12, 24, … est 3 × 2^(n−1). Quel est le 6ème terme ?
3 × 2⁵ = 3 × 32 = 96.
Find the fifth term of uₙ = n³ + 2. · Trouvez le cinquième terme de uₙ = n³ + 2.
5³ + 2 = 125 + 2 = 127.
Cubes and a term-number check
- Core includes simple cubic sequences. $3,10,29,66$ are 2 more than $1^3,2^3,3^3,4^3$, so $u_n=n^3+2$. The fifth term is $u_5=125+2=127$.
- For · Pour $u_n=4n+3$, testing whether 100 is a term gives $4n+3=100$, so $n=24.25$. A term number must be a positive integer, so 100 is not in this sequence.
You've got it
- linear · linéaire sequence: nth term $= dn + c$ (constant difference $d$) → $2,5,8,11 \to 3n-1$
- simple quadratic: second difference $= 2 \times$ the $n^2$ coefficient → $2,5,10,17 \to n^2 + 1$
- geometric: nth term $= a \times r^{n-1}$ (constant ratio $r$) → $3,6,12,24 \to 3 \times 2^{n-1}$