Trigonometry in right-angled triangles · Trigonometría en triángulos rectángulos
| English | Español |
|---|---|
| trigonometry/ˌtrɪɡəˈnɒmətri/ | trigonometría |
| opposite/ˈɒpəzɪt/ | opuesto |
| adjacent/əˈdʒeɪsənt/ | adyacente |
| angle of elevation/ˈæŋɡl ɒv ˌelɪˈveɪʃn/ | ángulo de elevación |
| angle of depression/ˈæŋɡl ɒv dɪˈpreʃn/ | ángulo de depresión |
How tall is that tree?
- You can't climb it with a tape measure. But standing $10$ m away and looking up at $50^{\circ}$, trigonometry 三角学 gives you the height: $10 \times \tan 50^{\circ} \approx 11.9$ m.
- Trigonometry measures the unmeasurable — using angles and one known length.
Naming the sides
- In a right-angled triangle, name the sides relative to the angle $\theta$:
- Opposite 对边 (O): the side across from $\theta$.
- Adjacent 邻边 (A): the side next to $\theta$ (not the hypotenuse).
- Hypotenuse (H): the longest side, opposite the right angle.
SOH-CAH-TOA: the three ratios that connect angles to side lengths in right-angled triangles.
Right-angled trig · Trigo de triángulo rectángulo
(cos θ, sin θ)
SOHCAHTOA comes from this circle — sin, cos and · y tan of the angle. · SOHCAHTOA proviene de este círculo — sin, cos y tan del ángulo.
The three ratios — SOH CAH TOA
- To find a side · lado: use the ratio and multiply/divide.
- To find an angle · ángulo: use the inverse ($\sin^{-1}$, $\cos^{-1}$, $\tan^{-1}$).
Opposite $4$, adjacent $3$: $\;\tan\theta = \dfrac{4}{3}$, so $\theta = \tan^{-1}\!\left(\dfrac{4}{3}\right) = 53.1^{\circ}$.
Looking up at a tower involves an angle of elevation 仰角
In a right-angled triangle the hypotenuse is 10 cm and the angle is 30°. The opposite side = 10 × sin 30°. Find it (cm). · En un triángulo rectángulo, la hipotenusa mide 10 cm y el ángulo es 30°. El lado opuesto = 10 × sin 30°. Calcúlalo (cm).
10 × sin 30° = 10 × 0.5 = 5 cm.
The opposite side is 4 cm and the adjacent side is 3 cm. Find the angle (degrees, 1 dp). · El lado opuesto mide 4 cm y el lado adyacente mide 3 cm. Encuentra el ángulo (grados, 1 decimal).
tan θ = 4/3, so θ = tan⁻¹(4/3) = 53.1°. · tan θ = 4/3, por lo tanto θ = tan⁻¹(4/3) = 53.1°.
The adjacent side is 8 cm and the angle is 60°. The hypotenuse = 8 / cos 60°. Find it (cm). · El lado adyacente mide 8 cm y el ángulo es 60°. La hipotenusa = 8 / cos 60°. Calcúlala (cm).
cos 60° = 0.5, so hyp = 8 / 0.5 = 16 cm. · cos 60° = 0.5, así que hip = 8 / 0.5 = 16 cm.
In SOH CAH TOA, sin θ = opposite / ______. · En SOH CAH TOA, sin θ = opuesto / ______.
SOH: sin θ = Opposite / Hypotenuse. · SOH: sin θ = Opuesto / Hipotenusa.
Angles of elevation and depression (Extended)
- Angle of elevation: looking up · arriba from the horizontal.
- Angle of depression 俯角: looking down · hacia abajo from the horizontal.
- Both are measured from the horizontal, not from the vertical.
From the horizontal, always. The angle of elevation/depression is measured from the horizontal line, not from the vertical. This is the most common error in these problems.
Name the sides from the angle $\theta$: the opposite is across from it, the adjacent next to it, the hypotenuse opposite the right angle (SOH-CAH-TOA)
From 50 m away, the angle of elevation to a tower top is 40°. Height = 50 × tan 40°. Find it (m, 1 dp). · Desde una distancia de 50 m, el ángulo de elevación hacia la cima de una torre es 40°. Altura = 50 × tan 40°. Calcúlala (m, 1 decimal).
50 × tan 40° = 50 × 0.839 = 42.0 m.
The angle of elevation is measured from the vertical. · El ángulo de elevación se mide desde la vertical.
Angles of elevation and depression are both measured from the horizontal, not the vertical. · Tanto los ángulos de elevación como los de depresión se miden desde la horizontal, no desde la vertical.
Worked example · Ejemplo resuelto
- $50$ m from a tower, elevation $40^{\circ}$:
- $h=d\tan\theta=50\tan40^{\circ}\approx42.0$ m. Keep the full calculator value of the tangent before rounding.
The angle of elevation looks up from the horizontal; the angle of depression looks down
You've got it
- SOH: $\sin\theta = \dfrac{\text{opp}}{\text{hyp}}$; CAH: $\cos\theta = \dfrac{\text{adj}}{\text{hyp}}$; TOA: $\tan\theta = \dfrac{\text{opp}}{\text{adj}}$
- use the inverse ($\tan^{-1}$ etc.) to find an angle
- elevation looks up, depression looks down — both from the horizontal