Resistance, electrical energy and power · 电阻、电能与功率
| English | 中文 | Pinyin · 拼音 |
|---|---|---|
| resistance/rɪˈzɪstəns/ | 电阻 | diàn zǔ |
| ohms/əʊmz/ | 欧姆 | ōu mǔ |
| filament lamp/ˈfɪləmənt læmp/ | 灯丝灯泡 | dēng sī dēng pào |
| diode/ˈdaɪəʊd/ | 二极管 | èr jí guǎn |
| fixed resistor/fɪkst rɪˈzɪstə/ | 定值电阻 | dìng zhí diàn zǔ |
| kilowatt-hour/ˈkɪləwɒt ˈaʊə/ | 千瓦时 | qiān wǎ shí |
Slowing the flow
- Push current through a thin wire and it gets hot; through a thick one, less so.
- Resistance 电阻 measures how hard it is for current to flow.
- It controls the current, heats your toaster, and sets your electricity bill.
减慢流动
- 把电流推过一根细导线,它就变热;过一根粗的,则不那么热。
- 电阻(resistance)测量电流流动有多难。
- 它控制电流、加热你的烤面包机,并决定你的电费。
Resistance
- Resistance $R$ is measured in ohms 欧姆 ($\Omega$). A bigger resistance gives a smaller current:
- To measure it: an ammeter in series reads $I$, a voltmeter across the component reads $V$, then divide.
A pylon carries the cables that bring electricity at very high voltage
电阻
- 电阻 $R$ 以欧姆(ohms,$\Omega$)测量。一个更大的电阻给出一个更小的电流:
- 要测量它:一个串联的电流表读 $I$,一个跨过元件的电压表读 $V$,然后除。

一座电塔携带以非常高的电压带来电的电缆
Resistance · 电阻
V = R·I
Ohm's law: voltage is proportional to current — the gradient is the resistance R. · 欧姆定律:电压与电流成正比——斜率是电阻 R。
A component has $12\ \text{V}$ across it and a current of $3.0\ \text{A}$ through it. What is its resistance, in Ω? · 一个元件跨过它有 $12\ \text{V}$ 且通过它有 $3.0\ \text{A}$ 的电流。它的电阻是多少,以 Ω 计?
$R = \dfrac{V}{I} = \dfrac{12}{3.0} = 4.0\ \Omega$. · $R = \dfrac{V}{I} = \dfrac{12}{3.0} = 4.0\ \Omega$。
What changes a wire's resistance
- A longer wire has more resistance — resistance is proportional to length ($R \propto l$).
- A thicker wire has less resistance — resistance is inversely proportional to the cross-sectional area ($R \propto \tfrac{1}{A}$).
- So doubling the length doubles $R$; doubling the area halves it.
I-V graphs for a resistor, a filament lamp 灯丝灯泡 and a diode 二极管
什么改变一根导线的电阻
- 一根更长的导线有更多的电阻——电阻与长度成正比($R \propto l$)。
- 一根更粗的导线有更少的电阻——电阻与横截面积成反比($R \propto \tfrac{1}{A}$)。
- 所以长度加倍使 $R$ 加倍;面积加倍使它减半。

一个电阻器、一个灯丝灯和一个二极管的 I-V 图
I–V characteristics · 电流-电压特性曲线
A resistor gives a straight line; a filament lamp and a diode do not. Pick a component and read I and R off the curve. · 电阻给出直线;灯丝灯泡和二极管则不然。选一个元件,从曲线上读出 I 和 R。
A wire is made twice as long (same thickness). Its resistance: · 一根导线被做成两倍长(相同厚度)。它的电阻:
Resistance is proportional to length, so doubling the length doubles the resistance. · 电阻与长度成正比,所以长度加倍使电阻加倍。
Match each electrical relationship to its formula. · 把每个电学关系与它的公式配对。
Each item links the term to its correct meaning. · 每一项把术语与它正确的含义联系。
Current–voltage graphs
- A fixed resistor 定值电阻: a straight line through the origin — resistance is constant, so $I \propto V$.
- A filament lamp: an S-shape that gets flatter — the wire heats up, so its resistance rises.
- A diode: current one way only — very high resistance the "wrong" way.
电流–电压图
- 一个固定电阻器:一条穿过原点的直线——电阻恒定,所以 $I \propto V$。
- 一个灯丝灯:一个变得更平的 S 形——导线变热,所以它的电阻上升。
- 一个二极管:电流只单向——"错误"方向非常高的电阻。

The I–V graph of a fixed resistor (at constant temperature) is: · 一个固定电阻器(在恒定温度下)的 I–V 图是:
A fixed resistor has constant resistance, so $I \propto V$ — a straight line through the origin. · 一个固定电阻器有恒定的电阻,所以 $I \propto V$——一条穿过原点的直线。
Electrical power and energy
- Power is the energy transferred each second, in watts (W):
- The energy transferred in a time $t$, in joules (J), is:
电功率和能量
- 功率是每秒转移的能量,以瓦特(watts,W)计:
- 在一个时间 $t$ 内转移的能量,以焦耳(joules,J)计,是:
A device runs at $12\ \text{V}$ and draws $2.0\ \text{A}$. What is its power, in W? · 一个设备在 $12\ \text{V}$ 运行并抽取 $2.0\ \text{A}$。它的功率是多少,以 W 计?
$P = IV = 2.0 \times 12 = 24\ \text{W}$. · $P = IV = 2.0 \times 12 = 24\ \text{W}$。
The kilowatt-hour 千瓦时
- Electricity bills use a bigger unit, the kilowatt-hour (kWh): the energy a $1\ \text{kW}$ appliance uses in $1$ hour.
- Example: a $2\ \text{kW}$ heater for $3$ hours uses $6\ \text{kWh}$.
千瓦时
- 电费使用一个更大的单位,千瓦时(kilowatt-hour,kWh):一个 $1\ \text{kW}$ 的电器在 $1$ 小时使用的能量。
- 例子:一个 $2\ \text{kW}$ 的加热器用 $3$ 小时使用 $6\ \text{kWh}$。
A $2.0\ \text{kW}$ heater is on for $3.0$ hours. How much energy does it use, in kWh? · 一个 $2.0\ \text{kW}$ 的加热器开 $3.0$ 小时。它使用多少能量,以 kWh 计?
energy = power × time = $2.0 \times 3.0 = 6.0\ \text{kWh}$. · 能量 = 功率 × 时间 = $2.0 \times 3.0 = 6.0\ \text{kWh}$。
If one kWh costs $20$ cents, what does $6.0\ \text{kWh}$ cost, in cents? · 如果一 kWh 花 $20$ 分,$6.0\ \text{kWh}$ 花多少,以分计?
cost = energy × price = $6.0 \times 20 = 120$ cents. · 成本 = 能量 × 价格 = $6.0 \times 20 = 120$ 分。
You've got it
- $R = \dfrac{V}{I}$ (ohms); longer wire → more $R$, thicker wire → less $R$
- I–V graphs: resistor = straight line; lamp = S-curve (heats up); diode = one way
- power $P = IV$ (watts); energy $E = IVt$ (joules)
- kWh = power (kW) × time (h); cost = kWh × price
你掌握了
- $R = \dfrac{V}{I}$(欧姆);更长的导线 → 更多 $R$,更粗的导线 → 更少 $R$
- I–V 图:电阻器 = 直线;灯 = S 曲线(变热);二极管 = 单向
- 功率 $P = IV$(瓦特);能量 $E = IVt$(焦耳)
- kWh = 功率(kW)× 时间(h);成本 = kWh × 价格