Vectors and magnitude · 向量与模
| English | 中文 | Pinyin · 拼音 |
|---|---|---|
| vectors/ˈvektəz/ | 向量 | xiàng liàng |
| scalar/ˈskeɪlə/ | 标量 | biāo liàng |
| magnitude/ˈmæɡnɪtjuːd/ | 大小 | dà xiǎo |
Arrows with attitude
- Wind speed, force, velocity — they all have a size and a direction. That's what makes them vectors 向量.
- A scalar 标量 (like temperature) has only size. A vector needs both.
带方向的箭头
- 风速、力、速度——它们都有一个大小和一个方向。那就是使它们成为向量的原因。
- 一个标量(像温度)只有大小。一个向量两者都需要。
Writing vectors
- A vector is written as a column $\begin{pmatrix} x \\ y \end{pmatrix}$, as $\overrightarrow{AB}$, or in bold $\mathbf{a}$.
- $x$ is the horizontal component (right is positive), $y$ is the vertical component (up is positive).
Forces like wind are vectors, with both size and direction
书写向量
- 一个向量被写成一个列 $\begin{pmatrix} x \\ y \end{pmatrix}$,作为 $\overrightarrow{AB}$,或粗体 $\mathbf{a}$。
- $x$ 是水平分量(右为正),$y$ 是竖直分量(上为正)。

像风这样的力是向量,有大小和方向两者
Vectors · 向量
resultant = a + b
Vectors add tip-to-tail; the resultant is the single arrow that replaces them. · 向量首尾相接地相加;合向量是替换它们的单一箭头。
Adding and subtracting vectors
- Add/subtract component by component: top with top, bottom with bottom.
- $\begin{pmatrix} 3 \\ 1 \end{pmatrix} + \begin{pmatrix} 2 \\ -4 \end{pmatrix} = \begin{pmatrix} 5 \\ -3 \end{pmatrix}$.
Scalar multiply: multiply both components by the number. $3\begin{pmatrix} 3 \\ 1 \end{pmatrix} = \begin{pmatrix} 9 \\ 3 \end{pmatrix}$.
向量的加和减
- 逐分量加/减:上面与上面,下面与下面。
- $\begin{pmatrix} 3 \\ 1 \end{pmatrix} + \begin{pmatrix} 2 \\ -4 \end{pmatrix} = \begin{pmatrix} 5 \\ -3 \end{pmatrix}$.
标量乘:把两个分量都乘以那个数。$3\begin{pmatrix} 3 \\ 1 \end{pmatrix} = \begin{pmatrix} 9 \\ 3 \end{pmatrix}$。
a = (3, 1) and b = (2, −4). The top number of a + b is? · a = (3, 1) 且 b = (2, −4)。a + b 的上面的数是多少?
3 + 2 = 5.
a = (3, 1) and b = (2, −4). The bottom number of a + b is? · a = (3, 1) 且 b = (2, −4)。a + b 的下面的数是多少?
1 + (−4) = −3.
If a = (3, 1), the top number of 4a is? · 如果 a = (3, 1),4a 的上面的数是多少?
4 × 3 = 12.
To subtract vectors, you subtract each ______ separately. · 要减向量,你分别减每个______。
Subtract top from top and bottom from bottom, just like addition. · 上面减上面,下面减下面,就像加法一样。
Magnitude 大小 (length)
- The magnitude of a vector uses Pythagoras:
- $\left|\begin{pmatrix} 3 \\ 4 \end{pmatrix}\right| = \sqrt{9 + 16} = \sqrt{25} = 5$.
Magnitude, not sum. The length of $\begin{pmatrix} 3 \\ 4 \end{pmatrix}$ is $\sqrt{3^2 + 4^2} = 5$, not $3 + 4 = 7$. You must use Pythagoras.
Adding by the triangle law: draw b from the tip of a, and a+b runs from start to finish
模(长度)
- 一个向量的模(magnitude)使用勾股定理:
- $\left|\begin{pmatrix} 3 \\ 4 \end{pmatrix}\right| = \sqrt{9 + 16} = \sqrt{25} = 5$.
是模,不是和。 $\begin{pmatrix} 3 \\ 4 \end{pmatrix}$ 的长度是 $\sqrt{3^2 + 4^2} = 5$,不是 $3 + 4 = 7$。你必须使用勾股定理。

用三角形法则相加:从 a 的尖端画 b,而 a+b 从开始到结束
Find the magnitude (length) of the vector (3, 4). · 求向量 (3, 4) 的模(长度)。
√(3² + 4²) = √25 = 5.
The magnitude of the vector (3, 4) is 3 + 4 = 7. · 向量 (3, 4) 的模是 3 + 4 = 7。
Magnitude uses Pythagoras: √(3² + 4²) = 5, not the sum 3 + 4 = 7. · 模使用勾股定理:√(3² + 4²) = 5,不是和 3 + 4 = 7。
Reverse a direction
- If a vector takes you from A to B, its negative takes you from B to A.
- For $\overrightarrow{AB}=\begin{pmatrix}3\\4\end{pmatrix}$, the reverse is $\overrightarrow{BA}=\begin{pmatrix}-3\\-4\end{pmatrix}$. Both have magnitude 5.
反向向量
- 若某向量从A指向B,则其相反向量从B指向A。
- 对于$\overrightarrow{AB}=\begin{pmatrix}3\\4\end{pmatrix}$,其反向量为$\overrightarrow{BA}=\begin{pmatrix}-3\\-4\end{pmatrix}$。两者模长均为5。
Vector a = (2, −3). Find the vertical component of −2a. · 向量 a = (2, −3)。求向量 −2a 的垂直分量(y分量)。
Multiply the vertical component: −2 × (−3) = 6. · 计算垂直分量:−2 × (−3) = 6。
Scalar multiplication and a zero check
- Multiply both components: if $\mathbf a=\begin{pmatrix}2\\-3\end{pmatrix}$, then $3\mathbf a=\begin{pmatrix}6\\-9\end{pmatrix}$ and $-\mathbf a=\begin{pmatrix}-2\\3\end{pmatrix}$. A negative multiplier reverses direction.
- Magnitude remains nonnegative: $|3\mathbf a|=3\sqrt{13}$; the zero vector has magnitude 0. Nonzero parallel vectors are scalar multiples.
标量乘法与零向量检验
- 分别乘上两个分量:若结果为$\mathbf a=\begin{pmatrix}2\\-3\end{pmatrix}$,则对应$3\mathbf a=\begin{pmatrix}6\\-9\end{pmatrix}$和$-\mathbf a=\begin{pmatrix}-2\\3\end{pmatrix}$。负数标量会反转方向。
- 模长保持非负:即$|3\mathbf a|=3\sqrt{13}$;零向量的模长为0。非零平行向量互为标量倍数。
You've got it
- add/subtract vectors component by component; scalar multiply scales both
- $\begin{pmatrix} 3 \\ 1 \end{pmatrix} + \begin{pmatrix} 2 \\ -4 \end{pmatrix} = \begin{pmatrix} 5 \\ -3 \end{pmatrix}$
- magnitude $= \sqrt{x^2 + y^2}$, so $\begin{pmatrix} 3 \\ 4 \end{pmatrix}$ has length $5$
你掌握了
- 逐分量加/减向量;标量乘缩放两者
- $\begin{pmatrix} 3 \\ 1 \end{pmatrix} + \begin{pmatrix} 2 \\ -4 \end{pmatrix} = \begin{pmatrix} 5 \\ -3 \end{pmatrix}$
- 模 $= \sqrt{x^2 + y^2}$,所以 $\begin{pmatrix} 3 \\ 4 \end{pmatrix}$ 有长度 $5$