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GAC016 Matemática III: Cálculo e Aplicações Avançadas

Matemática do GAC · Topic 3 · ⁨Tópico 3⁩

Train · ⁨Treinar⁩
3.1

O que este módulo é e como é avaliado

An average speed does not tell you every instantaneous speed, and a signed displacement does not always equal total distance. Calculus makes those distinctions precise.

GAC016 develops differentiation 微分, integration 积分 and their applications. Your centre's current brief determines assessment tasks and grading requirements; these original practice sheets do not establish a university credit decision or an official examination pattern.

State the independent variable, domain and units. The notation $dy/dx$ is a derivative with respect to x; a dot over y normally denotes a derivative with respect to time. Those notations describe the same operation only when their independent variables agree.

For applications, describe what a rate or accumulated value means in the stated model. A negative volume-change rate of 3 cubic centimetres per second means volume is falling at that rate, rather than that the volume itself is negative.

Vocabulary · ⁨Vocabulário⁩ Train · ⁨Treinar⁩
English · ⁨Inglês⁩ Chinese · ⁨Chinês⁩ Pinyin
differentiation/ˌdɪfəˌrenʃɪˈeɪʃn/ 微分 wēi fēn
integration/ˌɪntɪˈɡreɪʃn/ 积分 jī fēn
3.1

Diferenciação

Syllabus · ⁨Programa⁩
English

Unit 1 of 3 in GAC016 Mathematics III: Calculus & Advanced Applications (Level III). The module is taught over about 40 class hours plus 20 hours of independent study, and is assessed at the teaching centre and moderated by ACT — there is no external exam.

Module purpose: On completion of this module, students should be able to demonstrate a basic understanding of the principles of calculus and how they can be applied to the quantitative analysis of practical and financial situations.

The module outcomes this unit works towards:

Learning Objective GAC016.1: Determine the derivative (if it exists) of most mathematical functions and use the derivative to analyse functional behaviour.

Português

Unidade 1 de 3 em GAC016 Matemática III: Cálculo & Aplicações Avançadas (Nível III). O módulo é ministrado em cerca de 40 horas de aula mais 20 horas de estudo independente, e é avaliado no centro de ensino e moderado pela ACT — não há exame externo.

Propósito do Módulo: Ao completar este módulo, os alunos devem ser capazes de demonstrar um entendimento básico dos princípios do cálculo e como eles podem ser aplicados à análise quantitativa de situações práticas e financeiras.

Os resultados deste módulo que esta unidade busca alcançar:

Objetivo de Aprendizagem GAC016.1: Determinar a derivada (se existir) da maioria das funções matemáticas e usar a derivada para analisar o comportamento funcional.

Source: Cambridge International syllabus · ⁨Fonte: Programa Cambridge International⁩

A derivative 导数 is a rate of change: how fast $y$ changes as $x$ changes. Geometrically it is the gradient of the tangent 切线斜率 at a point.

$$f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h}$$

That limit is the definition. Differentiation from first principles 从定义求导 uses the difference quotient for nonzero h and then takes its limit. Unequal one-sided limits, as for $|x|$ at zero, prevent a derivative even when the function is continuous.

  • A power rule 幂法则, on a domain where the power is differentiable: if $y = x^n$ then $\dfrac{dy}{dx} = nx^{\,n-1}$.
  • A product rule 乘积法则: $(uv)' = u'v + uv'$.
  • A quotient rule 商法则, where $v\ne0$: $\left(\dfrac{u}{v}\right)' = \dfrac{u'v - uv'}{v^2}$.
  • A chain rule 链式法则: if $y = f(g(x))$ then $\dfrac{dy}{dx} = f'(g(x)) \cdot g'(x)$.
  • Stationary points 驻点 occur where $f'(x) = 0$. The second derivative 二阶导数 then classifies a stationary point when it is nonzero: negative gives a local maximum 极大值 and positive a local minimum 极小值. A zero second derivative is inconclusive; use derivative signs or other evidence. A stationary inflection can be neither an extremum.

Worked example. a tangent slope differs from a secant slope

The curve y equals x squared has a tangent at (1,1) and a dashed secant joining (1,1) to (2,4).

Known: $f(x)=x^2$. The secant between x equal to 1 and 2 has slope 3, but the derivative at x equal to 1 is 2.

$$m_{sec}=\frac{f(b)-f(a)}{b-a}=\frac{4-1}{2-1}=3$$
$$f'(x)=\lim_{h\to0}\frac{(x+h)^2-x^2}{h}=\lim_{h\to0}(2x+h)=2x$$
$$m_{tan}=f'(1)=2(1)=2$$

The average slope over a finite interval need not equal the instantaneous slope at either endpoint.

Use original practice sheet 3.1 to test the method, domain and interpretation against its solutions.

Vocabulary · ⁨Vocabulário⁩ Train · ⁨Treinar⁩
English · ⁨Inglês⁩ Chinese · ⁨Chinês⁩ Pinyin
derivative/dɪˈrɪvətɪv/ 导数 dǎo shù
gradient of the tangent/ˈɡreɪdɪənt ɒvðə ˈtændʒənt/ 切线斜率 qiè xiàn xié lǜ
differentiation from first principles/ˌdɪfəˌrenʃɪˈeɪʃn frɒm fɜːst ˈprɪnsɪplz/ 从定义求导 cóng dìng yì qiú dǎo
power rule/ˈpaʊə ruːl/ 幂法则 mì fǎ zé
product rule/ˈprɒdʌkt ruːl/ 乘积法则 chéng jī fǎ zé
quotient rule/ˈkwəʊʃənt ruːl/ 商法则 shāng fǎ zé
chain rule/tʃeɪn ruːl/ 链式法则 liàn shì fǎ zé
Stationary points/ˈsteɪʃənəri pɔɪnts/ 驻点 zhù diǎn
second derivative/ˈsekənd dɪˈrɪvətɪv/ 二阶导数 èr jiē dǎo shù
maximum/ˈmæksɪməm/ 极大值 jí dà zhí
minimum/ˈmɪnɪməm/ 极小值 jí xiǎo zhí
3.2

Integração

Syllabus · ⁨Programa⁩
English

Unit 2 of 3 in GAC016 Mathematics III: Calculus & Advanced Applications (Level III). The module is taught over about 40 class hours plus 20 hours of independent study, and is assessed at the teaching centre and moderated by ACT — there is no external exam.

The module outcomes this unit works towards:

Learning Objective GAC016.2: Use techniques of integration to find indefinite and definite integrals.

Português

Unidade 2 de 3 em GAC016 Matemática III: Cálculo & Aplicações Avançadas (Nível III). O módulo é ministrado em cerca de 40 horas de aula mais 20 horas de estudo independente, e é avaliado no centro de ensino e moderado pela ACT — não há exame externo.

Os resultados deste módulo que esta unidade busca alcançar:

Objetivo de Aprendizagem GAC016.2: Usar técnicas de integração para encontrar integrais indefinidas e definidas.

Source: Cambridge International syllabus · ⁨Fonte: Programa Cambridge International⁩

Indefinite integration finds antiderivatives. Definite integration measures signed accumulation, which can differ from geometric area. For a continuous integrand, the fundamental theorem of calculus 微积分基本定理 connects a definite integral to the difference of antiderivative values at its limits.

  • An indefinite integral 不定积分 has no limits and needs the constant of integration 积分常数: $\displaystyle\int x^n\,dx = \frac{x^{\,n+1}}{n+1} + c$ for $n \neq -1$.
  • A definite integral 定积分 has limits and gives a number: $\displaystyle\int_a^b f(x)\,dx = F(b) - F(a)$.
  • Integration by substitution 换元积分法 reverses the chain rule.
  • ⚠ Forgetting $+c$ on an indefinite integral is the single most frequent lost mark in the module, and it is lost on questions you have otherwise answered correctly.

Worked example. negative and positive areas can cancel

The line y equals x crosses the axis at zero, with shaded regions on both sides over negative 1 to 1.

Known: $f(x)=x$ from negative 1 to 1. Its definite integral is zero because the negative and positive contributions cancel.

$$I=\int_{-1}^{1}x\,dx=\left[\frac{x^2}{2}\right]_{-1}^{1}=\frac12-\frac12=0$$

Geometric area instead adds the magnitudes of the two triangular regions.

$$A=-\int_{-1}^{0}x\,dx+\int_0^1x\,dx=\frac12+\frac12=1$$

Use original practice sheet 3.2 to test the method, domain and interpretation against its solutions.

Vocabulary · ⁨Vocabulário⁩ Train · ⁨Treinar⁩
English · ⁨Inglês⁩ Chinese · ⁨Chinês⁩ Pinyin
fundamental theorem of calculus/ˌfʌndəˈmentl ˈθɪərəm ɒv ˈkælkjʊləs/ 微积分基本定理 wēi jī fēn jī běn dìng lǐ
indefinite integral/ɪnˈdefɪnət ˈɪntɪɡrəl/ 不定积分 bù dìng jī fēn
constant of integration/ˈkɒnstənt ɒv ˌɪntɪˈɡreɪʃn/ 积分常数 jī fēn cháng shù
definite integral/ˈdefɪnət ˈɪntɪɡrəl/ 定积分 dìng jī fēn
Integration by substitution/ˌɪntɪˈɡreɪʃn baɪ ˌsʌbstɪˈtjuːʃn/ 换元积分法 huàn yuán jī fēn fǎ
3.3

Advanced applications

Syllabus · ⁨Programa⁩
English

Unit 3 of 3 in GAC016 Mathematics III: Calculus & Advanced Applications (Level III). The module is taught over about 40 class hours plus 20 hours of independent study, and is assessed at the teaching centre and moderated by ACT — there is no external exam.

The module outcomes this unit works towards:

Learning Objective GAC016.3: Apply differentiation and integration techniques in a variety of practical problems.

Português

Unidade 3 de 3 em GAC016 Matemática III: Cálculo & Aplicações Avançadas (Nível III). O módulo é ministrado em cerca de 40 horas de aula mais 20 horas de estudo independente, e é avaliado no centro de ensino e moderado pela ACT — não há exame externo.

Os resultados deste módulo que esta unidade busca alcançar:

Objetivo de Aprendizagem GAC016.3: Aplicar técnicas de diferenciação e integração em uma variedade de problemas práticos.

Source: Cambridge International syllabus · ⁨Fonte: Programa Cambridge International⁩

  • Otimização 最优化 finds the largest or smallest value of a quantity: write the quantity as a function of one variable on a stated feasible domain, differentiate, find candidates and justify the required optimum. Check included boundaries and integer constraints where relevant.
  • Rates of change 变化率 chain together: $\dfrac{dV}{dt} = \dfrac{dV}{dr} \times \dfrac{dr}{dt}$.
  • Area between two curves 两曲线间面积 is $\displaystyle\int_a^b (f(x) - g(x))\,dx$ where $f$ is the upper curve on that whole interval. Split at crossings if their order changes.
  • Marginal cost and revenue 边际成本与边际收益 are derivatives of stated continuous cost and revenue models. They are instantaneous rates, not automatically exact discrete-unit changes.

Worked example. a fixed perimeter leaves one area variable

A rectangle has width x and length 10 minus x under a fixed perimeter of 20 units.

Known: a rectangle has perimeter 20, so length plus width is 10. Let width be x; length is $10-x$ e $0.

$$A(x)=x(10-x)$$
$$A'(x)=10-2x$$

The stationary candidate is $x=5$. Since $A''(x)=-2<0$ and the area approaches zero at both domain ends, this candidate is the global maximum. It is a 5 by 5 square with area 25.

Use original practice sheet 3.3 to test the method, domain and interpretation against its solutions.

Vocabulary · ⁨Vocabulário⁩ Train · ⁨Treinar⁩
English · ⁨Inglês⁩ Chinese · ⁨Chinês⁩ Pinyin
Optimisation/ˌɒptɪmaɪˈzeɪʃn/ 最优化 zuì yōu huà
Rates of change/reɪts ɒv tʃeɪndʒ/ 变化率 biàn huà lǜ
Area between two curves/ˈeərɪə bɪˈtwiːn tuː kɜːvz/ 两曲线间面积 liǎng qū xiàn jiān miàn jī
Marginal cost and revenue/ˈmɑːdʒɪnl kɒst ænd ˈrevənjuː/ 边际成本与边际收益 biān jì chéng běn yǔ biān jì shōu yì

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