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3.3 · Geometry and measures

OxfordAQA · International GCSE · Mathematics · Topic 3

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Geometry and measures

Unit 3.3 has no formulae sheet, so these are the facts to recall. The circle's circumference and area, with a sector as a fraction theta over 360 of each. A…

English narration · English + 中文 subtitles burned in

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Geometry and measures

OxfordAQA 9260 unit 3.3 (specification Version 5.1) — at 31.5% of the combined specimen marks. Core rows G1–G26 cover angle facts through constructions, mensuration, similarity, trigonometry, transformations, vectors and matrices; the Extension additions add the full circle-theorem programme with proof, congruence conditions, bearings, sphere/pyramid/cone/frustum formulae, k-k²-k³ similarity, sectors, 3D Pythagoras and trigonometry, the sine/cosine rules with ½ab sinC, combined transformations with fractional/negative scale factors, vector geometry, and the 2×2 matrix programme (identity, unit-square transformations, combinations). The 1E specimen is the geometry paper; unsampled lines are labelled specification originals.

Must-know for unit 3.3 (NO formulae sheet):

Family Formulae
circle circumference 圆周 $2\pi r$; area $\pi r^2$; arc 弧 $\tfrac\theta{360}(2\pi r)$; sector $\tfrac\theta{360}\pi r^2$
solids sphere $V = \tfrac43\pi r^3$, $SA = 4\pi r^2$; cone $V = \tfrac13\pi r^2 h$; pyramid $V = \tfrac13 Ah$ (Extension)
triangles $a^2 = b^2 + c^2 - 2bc\cos A$; $\dfrac a{\sin A} = \dfrac b{\sin B}$; Area $= \tfrac12 ab\sin C$
Vocabulary Train
English
circumference/sɜːˈkʌmfrəns/
arc/ɑːk/
negative scale factor/ˈneɡətɪv skeɪl ˈfæktə/
1 2 3 4 5 6

Angles, polygons and symmetry

Conventional terms: points, lines, vertices, edges, planes; parallel, perpendicular; polygons 多边形 and regular polygons 正多边形; the standard triangle labelling. Angle facts: at a point (360°), on a line (180°), vertically opposite 对顶角; parallel lines give alternate 内错角, corresponding 同位角 and co-interior angles (use these names in reasons, never "Z angles"); triangle sum 180° with the isosceles 等腰, equilateral 等边 and scalene 不等边 families. Polygon sums: interior $(n-2) \times 180°$, exterior $360°$; for regular polygons also the angle at the centre $= \tfrac{360°} {n}$. The special quadrilaterals (square, rectangle, parallelogram, trapezium, kite, rhombus 菱形) carry their side/angle/diagonal properties, and 2D shapes have reflection and rotation symmetry 对称 counts (a regular hexagon: 6 lines, order 6).

A rectangle of area 12 and a copy three times as long and wide with area 108
Length scale factor 3 gives area scale factor 9: 12 × 9 = 108
Explore

Angles, lengths and area

Use angle facts with a stated reason

Explain why the triangle has half the rectangle area when base and height match.

Vocabulary Train
English
polygon/ˈpɒlɪɡən/
regular polygon/ˈreɡjʊlə ˈpɒlɪɡən/
vertically opposite/ˈvɜːtɪkli ˈɒpəzɪt/
alternate angles/ɔːlˈtɜːnət ˈæŋɡlz/
corresponding angles/ˌkɒrɪˈspɒndɪŋ ˈæŋɡlz/
isosceles/aɪˈsɒsəliːz/
equilateral/ˌiːkwɪˈlætərəl/
scalene/ˈskeɪliːn/
rhombus/ˈrɒmbəs/
symmetry/ˈsɪmətri/
congruent/ˈkɒŋɡruːənt/
7 8 9 17

Congruence, similarity and circle theorems

Congruence 全等 with the Extension conditions for triangles — SSS, SAS, ASA, RHS — each justified by which three independent measurements pin a triangle. Similarity 相似 scales lengths by $k$: (Extension) areas by $k^2$, volumes by $k^3$, in every direction.

A circle with a 100° angle at the centre O and a 50° angle at the circumference on the same arc
The angle at the centre is twice the angle at the circumference: 100° and 50°

The Extension circle programme: angle at the centre is twice the angle at the circumference; the semicircle 半圆 angle is 90°; angles in the same segment are equal; opposite angles of a cyclic quadrilateral 圆内接四边形 sum to 180°; tangent $\perp$ radius 半径; tangents from an external point are equal; the perpendicular from the centre bisects a chord 弦; the alternate segment 弦切角 theorem. The verified chain: an angle at the circumference of 35° subtends the same arc as a centre angle of 70°, and the angle from the OPPOSITE arc is $\tfrac12(360° - 70°) = 145°$ — the two circumference angles are opposite angles of a cyclic quadrilateral ($35° + 145° = 180°$) — every step names its theorem (the 1E specimen's circle question carries answers of this family; G9's geometric proof 证明 demand).

Explore

Circle theorems and reasoned proofs

The angle at the centre is twice the angle at the circumference on the same arc

Choose the theorem from the geometric configuration before calculating the angle.

Vocabulary Train
English
similar/ˈsɪmɪlə/
semicircle/ˈsemɪsɜːkl/
cyclic quadrilateral/ˈsaɪklɪk ˌkwɒdrɪˈlætərəl/
radius/ˈreɪdɪəs/
chord/kɔːd/
alternate segment
proof/pruːf/
10 11 12 13

3D shapes, constructions and bearings

Faces, surfaces, edges and vertices of cubes, cuboids, prisms 棱柱, cylinders 圆柱, pyramids, cones and spheres; plans and elevations 平面图和立面图 (front, side, top views — a specification line not sampled by the specimens). Measure line segments and angles; scale drawings with scale factors; bearings 方位角: three-figure, clockwise from north (Extension includes the eight compass points) — the 2E specimen's 252° comes from a bearings chain: a return bearing plus an angle at a point.

Worked example: an angle from two bearings. $B$ is on a bearing of 070° from $A$, and $C$ is on a bearing of 160° from $B$. Find angle $ABC$. The bearing of $A$ FROM $B$ is the return bearing $070° + 180° = 250°$. At $B$, the direction to $A$ is 250° and the direction to $C$ is 160°, so angle $ABC = 250° - 160° = 90°$. Draw a north line at EVERY point you work from; bearings are measured at the point named after "from".

The circle x² + y² = 25 and the perpendicular bisector x = 3 of the points (0, 0) and (6, 0), meeting at (3, 4) and (3, −4)
Points 5 from O and equidistant from (0, 0) and (6, 0): x = 3 meets the circle at (3, ±4)

Ruler-and-compass constructions 作图: perpendicular bisector 垂直平分线 of a segment, perpendicular to a line from/at a point, angle bisector 角平分线, 60° angle — used to build figures and solve loci 轨迹 problems; the perpendicular distance from a point to a line is the shortest. Leave all arcs visible: the arcs are the working.

Explore

Constructions, loci and geometric conditions

Points equally distant from A and B lie on the perpendicular bisector of AB

Explain why (3,4) belongs to both loci.

Vocabulary Train
English
prism/ˈprɪzəm/
cylinder/ˈsɪlɪndə/
plans and elevations
bearings/ˈbeərɪŋz/
constructions/kənˈstrʌkʃnz/
perpendicular bisector/ˌpɜːpənˈdɪkjʊlə baɪˈsektə/
angle bisector
loci/ˈləʊsaɪ/
14 15 16 18

Units, mensuration and similarity ratios

Standard units with conversions (time 12/24-hour; length, area, volume/capacity, mass; compound units 复合单位 speed and density 密度). Areas: triangle $\tfrac12 bh$, parallelogram $bh$, trapezium $\tfrac12(a+b)h$; volume by $V = Ah$ (constant cross-section 横截面). The circle: $2\pi r$, $\pi r^2$; (Extension) sectors 扇形 arc $\tfrac\theta{360} \times 2\pi r$ and area $\tfrac\theta{360} \times \pi r^2$, plus sphere/pyramid/cone surface and volume formulae and composite solids including frustums 圆台 (specification lines, several not sampled) — a cone of $r = 5$, $h = 12$ has slant 13, $V = 100\pi$ and curved surface $65\pi$; the 1E specimen's cone problem finds a proportion $p = 15$.

Worked example: a sector. A sector has radius 6 cm and angle 150°. The arc is $\tfrac{150}{360} \times 2\pi \times 6 = 5\pi = 15.7$ cm, so the perimeter is $5\pi + 6 + 6 = 27.7$ cm (both radii count). The area is $\tfrac{150}{360} \times \pi \times 6^2 = 15\pi = 47.1\ \text{cm}^2$. Similar figures (Extension): lengths $k$ : areas $k^2$ : volumes $k^3$ — the 2E specimen's similar solids give 864 cm³ from a volume ratio.

Explore

Angle reasoning, similarity and mensuration

For similar shapes with length scale factor k, areas scale by k² and volumes by k³

Match the scale factors to the correct dimension before using 12 cm² or 8 cm³.

Vocabulary Train
English
compound units
density/ˈdensɪti/
cross-section/krɒs ˈsekʃn/
sector/ˈsektə/
frustum/ˈfrʌstəm/
19 20

Pythagoras, trigonometry and 3D problems

$a^2 + b^2 = c^2$ with SOH CAH TOA in right-angled triangles — 2D always, 3D figures at Extension: extract the right triangle first (the 1E specimen's 3D trig gives 62.7°). The sine rule 正弦定理 $\dfrac a{\sin A} = \dfrac b{\sin B}$ and cosine rule 余弦定理 $a^2 = b^2 + c^2 - 2bc\cos A$ cover any triangle (Extension), with Area $= \tfrac12 ab\sin C$ reversible — the 2E specimen's cosine rule gives 102.6°, and $\cos x = \tfrac8{11}$ yields $x = 43.3°$.

A right-angled triangle with sides 3, 4 and hypotenuse 5
Label opposite, adjacent and hypotenuse first: 3, 4 and 5 here

Worked example: 2E cosine-rule family, adapted. A triangle has $a = 9$, $b = 11$ and angle $C = 72°$. $c^2 = 81 + 121 - 2(9)(11)\cos 72° = 202 - 198 \times 0.309 = 202 - 61.2 = 140.8$, so $c = 11.9$ (3 s.f.). Then the smallest angle sits opposite the shortest side: $\cos A = \tfrac{b^2 + c^2 - a^2}{2bc} = \tfrac{121 + 140.8 - 81}{2 \times 11 \times 11.87} = \tfrac{180.8}{261.1} = 0.693$, so $A = 46.2°$ (keeping $c$ unrounded) — check $A + B + C = 180°$ with $B = 61.8°$. ✓

Explore

Right triangles and non-right triangles

In a right triangle a²+b²=c²; sinθ=opposite/hypotenuse, cosθ=adjacent/hypotenuse and tanθ=opposite/adjacent

Compare the model with the worked case and explain one change.

Vocabulary Train
English
sine rule/saɪn ruːl/
cosine rule/ˈkəʊsaɪn ruːl/
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Transformations with matrices and vectors

Single rotations, reflections, translations (by a vector) and enlargements (positive factor) — with the preserved properties named; the Extension additions cover combined transformations and enlargements by fractional and negative scale factors 负比例因子 (an inverted, shrunken image on the opposite side of the centre). Vectors 向量: notation, sum, difference and scalar multiples (graphically and by components), the commutative and associative laws, and simple 2D geometry — the 2E specimen proves $CB \parallel MN$ via a $\tfrac12$ ratio using vectors.

Vector AB drawn 4 across and 3 up
AB = (4, 3) has magnitude √(4² + 3²) = 5

The 2×2 matrix 矩阵 programme (Extension): multiplication (2×2 by 2×2, by 2×1, scalar), the identity matrix 单位矩阵 $I$; transformations of the UNIT SQUARE — rotations of 90°/180°/270° about the origin, reflections in $x = 0$, $y = 0$, $y = x$, $y = -x$, enlargements centred on the origin — represented by matrices such as $\begin{pmatrix} 0 & -1 \\ -1 & 0 \end{pmatrix}$ (reflection in $y = -x$, the 1E specimen's matrix); combined transformations by matrix multiplication, in the order the transformations apply.

Worked example: a combined transformation. Reflect in $y = x$, matrix $\mathbf{M} = \begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix}$, then rotate 90° anticlockwise about the origin, matrix $\mathbf{R} = \begin{pmatrix} 0 & -1 \\ 1 & 0 \end{pmatrix}$. The FIRST transformation sits on the RIGHT:

$$\mathbf{R}\mathbf{M} = \begin{pmatrix} 0 & -1 \\ 1 & 0 \end{pmatrix} \begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix} = \begin{pmatrix} -1 & 0 \\ 0 & 1 \end{pmatrix},$$

which is a reflection in the $y$-axis ($x = 0$). Check with a point: $(2, 1)$ reflects to $(1, 2)$, which rotates to $(-2, 1)$, and the reflection in the $y$-axis also sends $(2, 1)$ to $(-2, 1)$. ✓ Multiplying in the other order gives $\mathbf{M}\mathbf{R}$, a reflection in the $x$-axis: the order matters.

The unit square and its image, a parallelogram with corners (0, 0), (2, 0), (3, 3) and (1, 3)
The matrix columns (2, 0) and (1, 3) are the images of the basis vectors

Worked example: 1E matrix-solve family, adapted. Solve $\begin{pmatrix} 3 & 1 \\ 1 & 2 \end{pmatrix} \begin{pmatrix} x \\ y \end{pmatrix} = \begin{pmatrix} 10 \\ 5 \end{pmatrix}$: the equations are $3x + y = 10$ and $x + 2y = 5$. From the first, $y = 10 - 3x$; substituting: $x + 2(10 - 3x) = 5$, so $-5x = -15$, giving $x = 3$ and $y = 1$. Check: $3(3) + 1 = 10$. ✓ The 1E specimen's own pairs $(6, -\tfrac12)$ and $(-2, -\tfrac52)$ come from the same method on a second, linked system.

Explore

Plane matrix transformations

Represent a plane transformation using a 2×2 matrix acting on column vectors

Compare the model with the worked case and explain one change.

Vocabulary Train
English
vector/ˈvektə/
matrix/ˈmeɪtrɪks/
identity matrix/aɪˈdentɪti ˈmeɪtrɪks/
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Checklist

  • Conventional terms and triangle notation; angle facts; parallel-line angles; polygon interior/exterior/centre sums; quadrilateral properties; symmetry counts (G1–G6).
  • Congruence with SSS/SAS/ASA/RHS; similarity with k, k², k³ ratios (G7, G17, Extension).
  • Circle language and the full theorem bank with proof-style reasons (G8–G9, Extension; 35° → 70° → 145° verified chain).
  • 3D shape properties; plans and elevations (not sampled); measuring, scale factors, bearings (G10–G12).
  • Constructions (four ruler-and-compass types) with loci; shortest distance property (G13).
  • Units and compound measures; area and V = Ah formulae; circle formulae; sectors; sphere/pyramid/cone/frustum surface and volume; composite shapes (G14–G16, Extension).
  • Pythagoras and trigonometry in 2D and 3D; sine/cosine rules and ½ab sinC (G19–G20, Extension; 1E 62.7°, 2E 102.6° and cos x = 8/11).
  • Transformations including combined and fractional/negative enlargements (G21, Extension).
  • Vector notation and geometry (G22; 2E CB ∥ MN proof).
  • Matrix multiplication, identity, unit-square transformations and combinations (G23–G26, Extension; 1E matrices).

Boundary notes: NO formulae sheet in 9260. Lines marked "not sampled" (plans and elevations, parts of the solids programme) are specification originals; the specimens are Extension-tier only. Worked examples are adapted from the 2016 specimen pair or original.

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