Unit 3.3 has no formulae sheet, so these are the facts to recall. The circle's circumference and area, with a sector as a fraction theta over 360 of each. A…
English narration · English + 中文 subtitles burned in
1 2 3 4 5 6
Geometry and measures
OxfordAQA 9260 unit 3.3 (specification Version 5.1) — at 31.5% of the combined
specimen marks. Core rows G1–G26 cover angle facts through constructions,
mensuration, similarity, trigonometry, transformations, vectors and matrices; the
Extension additions add the full circle-theorem programme with proof, congruence
conditions, bearings, sphere/pyramid/cone/frustum formulae, k-k²-k³ similarity,
sectors, 3D Pythagoras and trigonometry, the sine/cosine rules with ½ab sinC,
combined transformations with fractional/negative scale factors, vector geometry,
and the 2×2 matrix programme (identity, unit-square transformations, combinations).
The 1E specimen is the geometry paper; unsampled lines are labelled specification
originals.
Conventional terms: points, lines, vertices, edges, planes; parallel, perpendicular;
polygons 多边形 and regular polygons 正多边形; the standard triangle labelling. Angle facts: at a
point (360°), on a line (180°), vertically opposite 对顶角; parallel lines give
alternate 内错角, corresponding 同位角 and co-interior angles (use
these names in reasons, never "Z angles"); triangle sum 180° with the isosceles 等腰,
equilateral 等边 and scalene 不等边 families. Polygon sums: interior $(n-2) \times 180°$,
exterior $360°$; for regular polygons also the angle at the centre $= \tfrac{360°}
{n}$. The special quadrilaterals (square, rectangle, parallelogram, trapezium, kite,
rhombus 菱形) carry their side/angle/diagonal properties, and 2D shapes have reflection
and rotation symmetry 对称 counts (a regular hexagon: 6 lines, order 6).
Congruence 全等 with the Extension conditions for triangles — SSS, SAS, ASA,
RHS — each justified by which three independent measurements pin a triangle.
Similarity 相似 scales lengths by $k$: (Extension) areas by $k^2$, volumes by
$k^3$, in every direction.
The angle at the centre is twice the angle at the circumference: 100° and 50°
The Extension circle programme: angle at the centre is twice the angle at the
circumference; the semicircle 半圆 angle is 90°; angles in the same segment are equal;
opposite angles of a cyclic quadrilateral 圆内接四边形 sum to 180°; tangent $\perp$radius 半径; tangents
from an external point are equal; the perpendicular from the centre bisects a chord 弦;
the alternate segment 弦切角 theorem. The verified chain: an angle at
the circumference of 35° subtends the same arc as a centre angle of 70°, and the
angle from the OPPOSITE arc is $\tfrac12(360° - 70°) = 145°$ — the two circumference
angles are opposite angles of a cyclic quadrilateral ($35° + 145° = 180°$) — every
step names its theorem (the 1E specimen's circle question carries answers of this
family; G9's geometric proof 证明 demand).
Explore
Circle theorems and reasoned proofs
The angle at the centre is twice the angle at the circumference on the same arc
Choose the theorem from the geometric configuration before calculating the angle.
Faces, surfaces, edges and vertices of cubes, cuboids, prisms 棱柱, cylinders 圆柱, pyramids,
cones and spheres; plans and elevations 平面图和立面图 (front, side, top views — a
specification line not sampled by the specimens). Measure line segments and angles;
scale drawings with scale factors; bearings 方位角: three-figure, clockwise from
north (Extension includes the eight compass points) — the 2E specimen's 252° comes
from a bearings chain: a return bearing plus an angle at a point.
Worked example: an angle from two bearings.$B$ is on a bearing of 070° from $A$,
and $C$ is on a bearing of 160° from $B$. Find angle $ABC$. The bearing of $A$ FROM $B$
is the return bearing $070° + 180° = 250°$. At $B$, the direction to $A$ is 250° and
the direction to $C$ is 160°, so angle $ABC = 250° - 160° = 90°$. Draw a north line at
EVERY point you work from; bearings are measured at the point named after "from".
Points 5 from O and equidistant from (0, 0) and (6, 0): x = 3 meets the circle at (3, ±4)
Ruler-and-compass constructions 作图: perpendicular bisector 垂直平分线 of a segment,
perpendicular to a line from/at a point, angle bisector 角平分线, 60° angle — used to build
figures and solve loci 轨迹 problems; the perpendicular distance from a point
to a line is the shortest. Leave all arcs visible: the arcs are the working.
Explore
Constructions, loci and geometric conditions
Points equally distant from A and B lie on the perpendicular bisector of AB
Standard units with conversions (time 12/24-hour; length, area, volume/capacity,
mass; compound units 复合单位 speed and density 密度). Areas: triangle $\tfrac12 bh$,
parallelogram $bh$, trapezium $\tfrac12(a+b)h$; volume by $V = Ah$ (constant
cross-section 横截面). The circle: $2\pi r$, $\pi r^2$; (Extension) sectors 扇形 arc
$\tfrac\theta{360} \times 2\pi r$ and area $\tfrac\theta{360} \times \pi r^2$, plus
sphere/pyramid/cone surface and volume formulae and composite solids
including frustums 圆台 (specification lines, several not sampled) — a cone of
$r = 5$, $h = 12$ has slant 13, $V = 100\pi$ and curved surface $65\pi$; the 1E
specimen's cone problem finds a proportion $p = 15$.
Worked example: a sector. A sector has radius 6 cm and angle 150°. The arc is
$\tfrac{150}{360} \times 2\pi \times 6 = 5\pi = 15.7$ cm, so the perimeter is
$5\pi + 6 + 6 = 27.7$ cm (both radii count). The area is
$\tfrac{150}{360} \times \pi \times 6^2 = 15\pi = 47.1\ \text{cm}^2$. Similar figures (Extension):
lengths $k$ : areas $k^2$ : volumes $k^3$ — the 2E specimen's similar solids give
864 cm³ from a volume ratio.
Explore
Angle reasoning, similarity and mensuration
For similar shapes with length scale factor k, areas scale by k² and volumes by k³
Match the scale factors to the correct dimension before using 12 cm² or 8 cm³.
$a^2 + b^2 = c^2$ with SOH CAH TOA in right-angled triangles — 2D always, 3D
figures at Extension: extract the right triangle first (the 1E specimen's 3D trig
gives 62.7°). The sine rule 正弦定理$\dfrac a{\sin A} = \dfrac b{\sin B}$ and cosine rule 余弦定理$a^2 = b^2 + c^2 - 2bc\cos A$ cover any triangle (Extension), with Area $=
\tfrac12 ab\sin C$ reversible — the 2E specimen's cosine rule gives 102.6°, and
$\cos x = \tfrac8{11}$ yields $x = 43.3°$.
Label opposite, adjacent and hypotenuse first: 3, 4 and 5 here
Worked example: 2E cosine-rule family, adapted. A triangle has $a = 9$, $b =
11$ and angle $C = 72°$. $c^2 = 81 + 121 - 2(9)(11)\cos 72° = 202 - 198 \times
0.309 = 202 - 61.2 = 140.8$, so $c = 11.9$ (3 s.f.). Then the smallest angle sits
opposite the shortest side: $\cos A = \tfrac{b^2 + c^2 - a^2}{2bc} =
\tfrac{121 + 140.8 - 81}{2 \times 11 \times 11.87} = \tfrac{180.8}{261.1} = 0.693$,
so $A = 46.2°$ (keeping $c$ unrounded) — check $A + B + C = 180°$ with $B = 61.8°$. ✓
Explore
Right triangles and non-right triangles
In a right triangle a²+b²=c²; sinθ=opposite/hypotenuse, cosθ=adjacent/hypotenuse and tanθ=opposite/adjacent
Compare the model with the worked case and explain one change.
Single rotations, reflections, translations (by a vector) and enlargements
(positive factor) — with the preserved properties named; the Extension additions
cover combined transformations and enlargements by fractional and negative
scale factors 负比例因子 (an inverted, shrunken image on the opposite side of the
centre). Vectors 向量: notation, sum, difference and scalar multiples
(graphically and by components), the commutative and associative laws, and simple
2D geometry — the 2E specimen proves $CB \parallel MN$ via a $\tfrac12$ ratio
using vectors.
AB = (4, 3) has magnitude √(4² + 3²) = 5
The 2×2 matrix 矩阵 programme (Extension): multiplication (2×2 by 2×2, by 2×1,
scalar), the identity matrix 单位矩阵$I$; transformations of the UNIT SQUARE —
rotations of 90°/180°/270° about the origin, reflections in $x = 0$, $y = 0$,
$y = x$, $y = -x$, enlargements centred on the origin — represented by matrices
such as $\begin{pmatrix} 0 & -1 \\ -1 & 0 \end{pmatrix}$ (reflection in $y = -x$,
the 1E specimen's matrix); combined transformations by matrix multiplication, in
the order the transformations apply.
Worked example: a combined transformation. Reflect in $y = x$, matrix
$\mathbf{M} = \begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix}$, then rotate 90°
anticlockwise about the origin, matrix $\mathbf{R} = \begin{pmatrix} 0 & -1 \\ 1 & 0
\end{pmatrix}$. The FIRST transformation sits on the RIGHT:
which is a reflection in the $y$-axis ($x = 0$). Check with a point: $(2, 1)$ reflects
to $(1, 2)$, which rotates to $(-2, 1)$, and the reflection in the $y$-axis also sends
$(2, 1)$ to $(-2, 1)$. ✓ Multiplying in the other order gives $\mathbf{M}\mathbf{R}$, a
reflection in the $x$-axis: the order matters.
The matrix columns (2, 0) and (1, 3) are the images of the basis vectors
Worked example: 1E matrix-solve family, adapted. Solve
$\begin{pmatrix} 3 & 1 \\ 1 & 2 \end{pmatrix} \begin{pmatrix} x \\ y
\end{pmatrix} = \begin{pmatrix} 10 \\ 5 \end{pmatrix}$: the equations are
$3x + y = 10$ and $x + 2y = 5$. From the first, $y = 10 - 3x$; substituting:
$x + 2(10 - 3x) = 5$, so $-5x = -15$, giving $x = 3$ and $y = 1$. Check: $3(3) + 1
= 10$. ✓ The 1E specimen's own pairs $(6, -\tfrac12)$ and $(-2, -\tfrac52)$ come
from the same method on a second, linked system.
Explore
Plane matrix transformations
Represent a plane transformation using a 2×2 matrix acting on column vectors
Compare the model with the worked case and explain one change.
Congruence with SSS/SAS/ASA/RHS; similarity with k, k², k³ ratios (G7, G17, Extension).
Circle language and the full theorem bank with proof-style reasons (G8–G9, Extension; 35° → 70° → 145° verified chain).
3D shape properties; plans and elevations (not sampled); measuring, scale factors, bearings (G10–G12).
Constructions (four ruler-and-compass types) with loci; shortest distance property (G13).
Units and compound measures; area and V = Ah formulae; circle formulae; sectors; sphere/pyramid/cone/frustum surface and volume; composite shapes (G14–G16, Extension).
Pythagoras and trigonometry in 2D and 3D; sine/cosine rules and ½ab sinC (G19–G20, Extension; 1E 62.7°, 2E 102.6° and cos x = 8/11).
Transformations including combined and fractional/negative enlargements (G21, Extension).
Vector notation and geometry (G22; 2E CB ∥ MN proof).
Matrix multiplication, identity, unit-square transformations and combinations (G23–G26, Extension; 1E matrices).
Boundary notes: NO formulae sheet in 9260. Lines marked "not sampled" (plans and
elevations, parts of the solids programme) are specification originals; the
specimens are Extension-tier only. Worked examples are adapted from the 2016
specimen pair or original.
Interactive lessons on this topic
Work through it step by step, with instant-check exercises.