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GAC004 Mathématiques I : Fondamentaux

GAC Mathématiques · Topic 1 · ⁨Sujet 1⁩

Train · ⁨Entrainer⁩
1.1

De quoi ce module parle-t-il et comment est-il noté

A price can fall by 20% and then rise by 20% without returning to its starting value. Mathematics I helps you explain such results with a method, units and a clear interpretation. The six units connect arithmetic, algebra, graphs, geometry, trigonometry and exponential models.

Your centre's current assessment brief is the authority for tasks, weights, permitted tools and deadlines. An in-class test 课堂测验 is completed under stated classroom conditions. Projects 项目 can involve collecting data, calculating and reporting; an examination 考试 et coursework 平时作业 may have different instructions. Do not infer an official assessment pattern from these practice sheets.

A terminology logbook 术语记录本 can record the English term, a meaning in your own words and a small example. Follow your centre's instructions if it is submitted or assessed.

Read the command word 指令词: solve asks for values satisfying a condition, simplify for an equivalent expression, and justifier for a reason. Show a valid method so a reader can check how the result follows. The mark scheme for each task determines its marks.

The six accompanying practice sheets are original GAC004-aligned material, not official papers. Their solutions award marks for stated mathematical steps rather than for the length of a written report.

Vocabulary · ⁨Vocabulaire⁩ Train · ⁨Entrainer⁩
English · ⁨Anglais⁩ Chinese · ⁨Chinois⁩ Pinyin
in-class test/ɪn klæs test/ 课堂测验 kè táng cè yàn
projects/ˈprɒdʒekts/ 项目 xiàng mù
examination/eɡˌzæmɪˈneɪʃn/ 考试 kǎo shì
coursework/ˈkɔːsjuːɜːk/ 平时作业 píng shí zuò yè
terminology logbook/ˌtɜːmɪˈnɒlədʒi ˈlɒɡbʊk/ 术语记录本 shù yǔ jì lù běn
command word/kəˈmænd wɜːd/ 指令词 zhǐ lìng cí
1.1

Terminology and arithmetic review

Syllabus · ⁨Programme⁩
English

Unit 1 of 6 in GAC004 Mathematics I: Fundamentals (Level I). The module is taught over about 40 class hours plus 20 hours of independent study, and is assessed at the teaching centre and moderated by ACT — there is no external exam.

Module purpose: On completion of this module, students should be able to demonstrate an understanding of the basic concepts of mathematics, and the language used, in preparation for tertiary study within an English-speaking environment.

The module outcomes this unit works towards:

Learning Objective GAC004.1: Solve elementary math problems using basic arithmetic operations.

Français

Unité 1 sur 6 dans GAC004 Mathématiques I : Fondamentaux (Niveau I). Le module est dispensé sur environ 40 heures de cours plus 20 heures d'étude autonome, évalué au centre d'enseignement et moderé par ACT — il n'y a pas d'examen externe.

Objectif du module : À l'issue de ce module, les étudiants devraient être capables de démontrer une compréhension des concepts fondamentaux des mathématiques et du langage utilisé, en vue d'études supérieures dans un environnement anglophone.

Les objectifs de module auxquels cette unité contribue :

Objectif d'apprentissage GAC004.1 : Résoudre des problèmes élémentaires de mathématiques en utilisant des opérations arithmétiques de base.

Source: Cambridge International syllabus · ⁨Source : Programme Cambridge International⁩

The vocabulary of number is assumed by every later unit.

An integer 整数 is a whole number, including negative whole numbers and zero. A rational number 有理数 can be written as a fraction of two integers with a nonzero denominator; an irrational number 无理数 cannot, and $\pi$ et $\sqrt{2}$ are the standard examples. A prime number 质数 is a positive integer greater than 1 with exactly two positive factors, itself and 1.

Le order of operations 运算顺序 fixes what a written expression means: brackets, then indices, then multiplication and division, then addition and subtraction, working left to right within a level.

$$3 + 4 \times 2^2 = 3 + 4 \times 4 = 3 + 16 = 19$$
  • A factor 因数 divides a number exactly; a multiple 倍数 is what you get by multiplying it. 6 is a factor of 24, and 24 is a multiple of 6.
  • Le highest common factor (HCF) 最大公因数 et lowest common multiple (LCM) 最小公倍数 come from the prime factors: $24 = 2^3 \times 3$ et $36 = 2^2 \times 3^2$, so the HCF is $2^2 \times 3 = 12$ and the LCM is $2^3 \times 3^2 = 72$.
  • A percentage 百分比 is a fraction with denominator 100. An increase of 15% multiplies by $1.15$; a decrease of 15% multiplies by $0.85$. Reversing a percentage change means dividing, never subtracting the same percentage back.
  • Significant figures 有效数字 are the digits retained to express a value at a stated precision. They do not alone establish the accuracy of a measurement. $0.004\,072$ to three significant figures is $0.004\,07$.
  • Notation scientifique 科学记数法 writes a number as $a \times 10^n$ with $1 \le |a| < 10$ for a nonzero number, with integer n. It is how a calculator shows a very large or very small answer.

Worked example. a decrease and increase use different bases

The worked price moves from 80 to 64 to 76.8 because each percentage uses the price at that stage.

Known: an invented price of 80 units falls by 20%, then rises by 20%. Why use successive multipliers? Each change is calculated from the current price.

$$P_{new}=P_{old}(1-r/100)$$
$$P_1=80(1-20/100)=64$$
$$P_{new}=P_{old}(1+r/100)$$
$$P_2=64(1+20/100)=76.8$$

The price is not back at 80. The decrease was 16, while the later increase was 12.8, because the bases differ.

Continue with practice sheet 1.1. Solve before opening the solutions, and check both the method and the final units.

Vocabulary · ⁨Vocabulaire⁩ Train · ⁨Entrainer⁩
English · ⁨Anglais⁩ Chinese · ⁨Chinois⁩ Pinyin
integer/ˈɪntɪdʒə/ 整数 zhěng shù
rational number/ˈræʃənl ˈnʌmbə/ 有理数 yǒu lǐ shù
irrational number/ɪˈræʃənl ˈnʌmbə/ 无理数 wú lǐ shù
prime number/praɪm ˈnʌmbə/ 质数 zhì shù
order of operations/ˈɔːdə ɒv ˌɒpəˈreɪʃnz/ 运算顺序 yùn suàn shùn xù
factor/ˈfæktə/ 因数 yīn shù
multiple/ˈmʌltɪpl/ 倍数 bèi shù
highest common factor (HCF)/ˈhaɪɪst ˈkɒmən ˈfæktə/ 最大公因数 zuì dà gōng yīn shù
lowest common multiple (LCM)/ˈləʊɪst ˈkɒmən ˈmʌltɪpl/ 最小公倍数 zuì xiǎo gōng bèi shù
percentage/pəˈsentɪdʒ/ 百分比 bǎi fēn bǐ
Significant figures/sɪɡˈnɪfɪkənt ˈfɪɡəz/ 有效数字 yǒu xiào shù zì
Standard form/ˈstændəd fɔːm/ 科学记数法 kē xué jì shù fǎ
1.2

Algebra I: introductory algebra

Syllabus · ⁨Programme⁩
English

Unit 2 of 6 in GAC004 Mathematics I: Fundamentals (Level I). The module is taught over about 40 class hours plus 20 hours of independent study, and is assessed at the teaching centre and moderated by ACT — there is no external exam.

The module outcomes this unit works towards:

Learning Objective GAC004.2: Perform basic algebraic operations and solve equations and inequations using algebraic methods.

Français

Unité 2 sur 6 dans GAC004 Mathématiques I : Fondamentaux (Niveau I). Le module est dispensé sur environ 40 heures de cours plus 20 heures d'étude autonome, évalué au centre d'enseignement et moderé par ACT — il n'y a pas d'examen externe.

Les objectifs de module auxquels cette unité contribue :

Objectif d'apprentissage GAC004.2 : Effectuer des opérations algébriques de base et résoudre des équations et inéquations en utilisant des méthodes algébriques.

Source: Cambridge International syllabus · ⁨Source : Programme Cambridge International⁩

Algebra is arithmetic with letters standing for numbers, and it has its own vocabulary.

In $5x^2 - 3x + 7$, the whole thing is an expression 表达式; $5x^2$, $-3x$ et $7$ are its terms 项; 5 is the coefficient 系数 of $x^2$; and 7 is a constante 常数.

An equation 方程 says two expressions are equal and is solved for a value. An identity 恒等式 is true for every value in its domain. An inégalité 不等式 compares two expressions with $<$, $\le$, $>$ ou $\ge$.

To expand 展开 is to remove brackets; to factorise 因式分解 is to put them back.

$$(x + 3)(x - 5) = x^2 - 5x + 3x - 15 = x^2 - 2x - 15$$
  • Solving a linear equation 一元一次方程 means doing the same operation to both sides until the letter stands alone.
  • A quadratic equation 一元二次方程 has the form $ax^2+bx+c=0$ with $a\ne0$. Factorise when suitable, or use $x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$.
  • Simultaneous equations 联立方程 are two equations in two unknowns, solved by substitution or by elimination. For two linear equations, a unique solution is their intersection. Parallel distinct lines have no solution; identical lines have infinitely many.
  • ⚠ An inequality reverses 反向 when you multiply or divide both sides by a negative number: from $-2x > 6$ it follows that $x < -3$.

Worked example. reverse the inequality sign when dividing by a negative

A number line shows x less than 2, with an open circle at 2.

Known: solve $7-3x>1$. Subtract 7 from both sides, then divide by negative 3. The last operation reverses the inequality.

$$7-3x>1\quad\Longrightarrow\quad -3x>-6$$
$$x<\frac{-6}{-3}=2$$

The open circle excludes 2. Check $x=1$: $7-3(1)=4>1$; the boundary $x=2$ gives equality and is excluded.

Continue with practice sheet 1.2. Solve before opening the solutions, and check both the method and the final units.

Vocabulary · ⁨Vocabulaire⁩ Train · ⁨Entrainer⁩
English · ⁨Anglais⁩ Chinese · ⁨Chinois⁩ Pinyin
expression/ekˈspreʃn/ 表达式 biǎo dá shì
terms/tɜːmz/ 项 xiàng
coefficient/ˌkəʊɪˈfɪʃənt/ 系数 xì shù
constant/ˈkɒnstənt/ 常数 cháng shù
equation/ɪˈkweɪʒn/ 方程 fāng chéng
identity/aɪˈdentɪti/ 恒等式 héng děng shì
inequality/ɪniːˈkwɒlɪti/ 不等式 bù děng shì
expand/ekˈspænd/ 展开 zhǎn kāi
factorise/ˈfæktəraɪz/ 因式分解 yīn shì fēn jiě
linear equation/ˈlɪnɪə ɪˈkweɪʒn/ 一元一次方程 yī yuán yī cì fāng chéng
quadratic equation/kwɒˈdrætɪk ɪˈkweɪʒn/ 一元二次方程 yī yuán èr cì fāng chéng
Simultaneous equations/ˌsɪməlˈteɪnɪəs ɪˈkweɪʒnz/ 联立方程 lián lì fāng chéng
reverses/rɪˈvɜːsɪz/ 反向 fǎn xiàng
1.3

Algebra: graphs and coordinate geometry

Syllabus · ⁨Programme⁩
English

Unit 3 of 6 in GAC004 Mathematics I: Fundamentals (Level I). The module is taught over about 40 class hours plus 20 hours of independent study, and is assessed at the teaching centre and moderated by ACT — there is no external exam.

The module outcomes this unit works towards:

Learning Objective GAC004.3: Graph algebraic relations and use coordinate geometry to solve problems.

Français

Unité 3 sur 6 dans GAC004 Mathématiques I : Fondamentaux (Niveau I). Le module est dispensé sur environ 40 heures de cours plus 20 heures d'étude autonome, évalué au centre d'enseignement et moderé par ACT — il n'y a pas d'examen externe.

Les objectifs de module auxquels cette unité contribue :

Objectif d'apprentissage GAC004.3 : Représenter graphiquement des relations algébriques et utiliser la géométrie analytique pour résoudre des problèmes.

Source: Cambridge International syllabus · ⁨Source : Programme Cambridge International⁩

A graph turns an equation into a picture, and coordinate geometry measures that picture.

A nonvertical straight line can be written $y = mx + c$, where $m$ is the gradient 斜率 et $c$ the y-intercept y 轴截距. The gradient is the rise divided by the run.

$$m = \frac{y_2 - y_1}{x_2 - x_1}$$
  • Distinct nonvertical lines are parallèle 平行 when their gradients are equal. Two nonvertical lines are perpendicular 垂直 when their gradients multiply to $-1$. Vertical lines have undefined gradient; a vertical and a horizontal line are perpendicular.
  • Le midpoint 中点 of a segment is the average of the endpoints, and the distance 距离 between two points comes from Pythagoras: $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$.
  • A quadratic graphs as a parabole 抛物线. Its sommet 顶点 is the turning point, and the racines 根 are the x-values where it meets the $x$-axis, the solutions of $y=0$. A repeated root touches the axis without crossing; some quadratics have no real roots.
  • To solve two equations graphically 用图像求解, draw both and read the coordinates of the intersection. The answer is only as accurate as the drawing, which is why an algebraic check matters.

Worked example. a rising line through two given points

The line passes through A at (1,2) and B at (4,8), with dashed coordinate-change guides.

Known: $A=(1,2)$ et $B=(4,8)$. Use gradient because the line is nonvertical.

$$m=\frac{y_B-y_A}{x_B-x_A}=\frac{8-2}{4-1}=2$$

The line equation is $y=mx+c$. Substitute A to find the intercept.

$$c=y_A-mx_A=2-2(1)=0$$

Thus $y=2x$. The diagram's horizontal change is 3 and vertical change is 6.

Continue with practice sheet 1.3. Solve before opening the solutions, and check both the method and the final units.

Vocabulary · ⁨Vocabulaire⁩ Train · ⁨Entrainer⁩
English · ⁨Anglais⁩ Chinese · ⁨Chinois⁩ Pinyin
gradient/ˈɡreɪdɪənt/ 斜率 xié lǜ
y-intercept/waɪ ˌɪntəˈsept/ y 轴截距 y zhóu jié jù
parallel/ˈpærəlel/ 平行 píng xíng
perpendicular/ˌpɜːpənˈdɪkjʊlə/ 垂直 chuí zhí
midpoint/ˈmɪdpɔɪnt/ 中点 zhōng diǎn
distance/ˈdɪstəns/ 距离 jù lí
parabola/pəˈræbələ/ 抛物线 pāo wù xiàn
vertex/ˈvɜːteks/ 顶点 dǐng diǎn
roots/ruːts/ 根 gēn
graphically/ˈɡræfɪkli/ 用图像求解 yòng tú xiàng qiú jiě
1.4

Geometry: plane, solid and Euclidean geometry

Syllabus · ⁨Programme⁩
English

Unit 4 of 6 in GAC004 Mathematics I: Fundamentals (Level I). The module is taught over about 40 class hours plus 20 hours of independent study, and is assessed at the teaching centre and moderated by ACT — there is no external exam.

The module outcomes this unit works towards:

Learning Objective GAC004.4: Analyze simple problems involving planar shapes and solids and solve problems in Euclidean geometry.

Français

Unité 4 sur 6 dans GAC004 Mathématiques I : Fondamentaux (Niveau I). Le module est dispensé sur environ 40 heures de cours plus 20 heures d'étude autonome, évalué au centre d'enseignement et moderé par ACT — il n'y a pas d'examen externe.

Les objectifs de module auxquels cette unité contribue :

Objectif d'apprentissage GAC004.4 : Analyser des problèmes simples impliquant des formes planes et solides et résoudre des problèmes en géométrie euclidienne.

Source: Cambridge International syllabus · ⁨Source : Programme Cambridge International⁩

Plane geometry is about flat shapes, solid geometry about three-dimensional ones, and Euclidean geometry is the reasoning that connects them.

Angles on a straight line add to $180°$, angles around a point to $360°$, and the interior angles of a plane Euclidean triangle to $180°$. In a simple polygon 多边形 of $n$ sides the interior angles add to $(n - 2) \times 180°$.

  • Congruent 全等 shapes are identical in size and shape; similar 相似 shapes have the same shape with all lengths in one ratio.
  • Théorème de Pythagore 勾股定理 holds in a right-angled triangle: $a^2 + b^2 = c^2$, where $c$ is the hypotenuse 斜边.
  • Area 面积 is measured in square units and volume 体积 in cubic units. A cylinder has volume $\pi r^2 h$; a sphere has volume $\tfrac{4}{3}\pi r^3$ and surface area $4\pi r^2$.
  • ⚠ Scaling is not linear. If every length of a solid is doubled, its area is multiplied by $2^2 = 4$ and its volume by $2^3 = 8$.

Worked example. a triangular prism has a constant cross-section

A triangular prism has a right-triangle cross-section with perpendicular sides 3 and 4 cm and length 10 cm; perspective is not to scale.

Known: perpendicular triangle sides are 3 and 4 cm; prism length is 10 cm. Find the cross-sectional area, then multiply by the prism length.

$$A=\frac12 bh=\frac12(3)(4)=6\ \text{cm}^2$$
$$V=AL=6(10)=60\ \text{cm}^3$$

The sloping triangle side is not its perpendicular height. Volume is not the area of the triangular end.

Continue with practice sheet 1.4. Solve before opening the solutions, and check both the method and the final units.

Vocabulary · ⁨Vocabulaire⁩ Train · ⁨Entrainer⁩
English · ⁨Anglais⁩ Chinese · ⁨Chinois⁩ Pinyin
polygon/ˈpɒlɪɡən/ 多边形 duō biān xíng
Congruent/ˈkɒŋɡruːənt/ 全等 quán děng
similar/ˈsɪmɪlə/ 相似 xiāng sì
Pythagoras' theorem/paɪˈθæɡərəs ˈθɪərəm/ 勾股定理 gōu gǔ dìng lǐ
hypotenuse/haɪˈpɒtənjuːs/ 斜边 xié biān
Area/ˈeərɪə/ 面积 miàn jī
volume/ˈvɒljuːm/ 体积 tǐ jī
1.5

Trigonométrie

Syllabus · ⁨Programme⁩
English

Unit 5 of 6 in GAC004 Mathematics I: Fundamentals (Level I). The module is taught over about 40 class hours plus 20 hours of independent study, and is assessed at the teaching centre and moderated by ACT — there is no external exam.

The module outcomes this unit works towards:

Learning Objective GAC004.5: Calculate solutions to various problems using trigonometric methods.

Français

Unité 5 sur 6 dans GAC004 Mathématiques I : Fondamentaux (Niveau I). Le module est dispensé sur environ 40 heures de cours plus 20 heures d'étude autonome, évalué au centre d'enseignement et moderé par ACT — il n'y a pas d'examen externe.

Les objectifs de module auxquels cette unité contribue :

Objectif d'apprentissage GAC004.5 : Calculer des solutions à divers problèmes en utilisant des méthodes trigonométriques.

Source: Cambridge International syllabus · ⁨Source : Programme Cambridge International⁩

Trigonometry connects the angles of a triangle to its sides.

In a right-angled triangle, with $\theta$ one of the acute angles, the three ratios are $\sin \theta = \dfrac{\text{opposite}}{\text{hypotenuse}}$, $\cos \theta = \dfrac{\text{adjacent}}{\text{hypotenuse}}$ et $\tan \theta = \dfrac{\text{opposite}}{\text{adjacent}}$.

For a nondegenerate plane Euclidean triangle, the règle du sinus 正弦定理 and the règle du cosinus 余弦定理 apply:

$$\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}, \qquad a^2 = b^2 + c^2 - 2bc\cos A$$
  • An angle can be measured in degrees 度 or in radians 弧度, where $\pi$ radians is $180°$. Check which mode your calculator is in before every question.
  • Le unit circle 单位圆 extends the ratios beyond $90°$ and explains why $\sin$ et $\cos$ repeat every $360°$: they are periodic 周期的.
  • A bearing 方位角 is measured clockwise from north and always written with three figures, such as $075°$.
  • Angles of elevation and depression 仰角与俯角 are measured from the horizontal, upwards and downwards respectively. Add the observer or instrument height if the answer needs height above the ground. With side-side-angle data, the sine rule may allow two triangles: check both supplementary angles against the remaining angle sum.

Worked example. height from a horizontal distance and angle

A right triangle has a 12 m horizontal base and an angle of elevation of 30 degrees; the unknown height is opposite the angle.

Known: horizontal distance $d=12$ m and elevation $\theta=30^\circ$. Height h is opposite and d is adjacent, so use tangent in degree mode.

$$\tan\theta=\frac{h}{d}$$
$$h=d\tan\theta=12\tan30^\circ\approx6.93\ \text{m}$$

This is the height above the observer's horizontal sight level, not automatically the height above the ground.

Continue with practice sheet 1.5. Solve before opening the solutions, and check both the method and the final units.

Vocabulary · ⁨Vocabulaire⁩ Train · ⁨Entrainer⁩
English · ⁨Anglais⁩ Chinese · ⁨Chinois⁩ Pinyin
sine rule/saɪn ruːl/ 正弦定理 zhèng xián dìng lǐ
cosine rule/ˈkəʊsaɪn ruːl/ 余弦定理 yú xián dìng lǐ
degrees/dɪˈɡriːz/ 度 dù
radians/ˈreɪdɪənz/ 弧度 hú dù
unit circle/ˈjuːnɪt ˈsɜːkl/ 单位圆 dān wèi yuán
periodic/ˌpɪərɪˈɒdɪk/ 周期的 zhōu qī de
bearing/ˈbeərɪŋ/ 方位角 fāng wèi jiǎo
Angles of elevation and depression/ˈæŋɡlz ɒv ˌelɪˈveɪʃn ænd dɪˈpreʃn/ 仰角与俯角 yǎng jiǎo yǔ fǔ jiǎo
1.6

Exponential and logarithmic functions

Syllabus · ⁨Programme⁩
English

Unit 6 of 6 in GAC004 Mathematics I: Fundamentals (Level I). The module is taught over about 40 class hours plus 20 hours of independent study, and is assessed at the teaching centre and moderated by ACT — there is no external exam.

The module outcomes this unit works towards:

Learning Objective GAC004.6: Solve and graph exponential and logarithmic functions and equations.

Français

Unité 6 sur 6 dans GAC004 Mathématiques I : Fondamentaux (Niveau I). Le module est dispensé sur environ 40 heures de cours plus 20 heures d'étude autonome, évalué au centre d'enseignement et moderé par ACT — il n'y a pas d'examen externe.

Les objectifs de module auxquels cette unité contribue :

Objectif d'apprentissage GAC004.6 : Résoudre et représenter graphiquement des fonctions et équations exponentielles et logarithmiques.

Source: Cambridge International syllabus · ⁨Source : Programme Cambridge International⁩

These two functions describe growth and decay, and they undo each other.

An exponential function 指数函数 has the form $y=a^x$ with $a>0$ et $a\ne1$: the variable is in the exposant 指数. Each unit step multiplies its value by a. It grows when $a>1$ and decays when $0. Its y-intercept is 1 and its values stay positive; the x-axis is a horizontal asymptote.

A logarithm 对数 answers the reverse question. $\log_a y = x$ means exactly $a^x = y$, so $\log_{10}1000=3$. For real logarithms the argument must be positive, and the base must be positive and different from 1. The graph $y=\log_a x$ passes through $(1,0)$ and has vertical asymptote $x=0$.

$$\log(mn) = \log m + \log n, \qquad \log\!\left(\frac{m}{n}\right) = \log m - \log n, \qquad \log(m^k) = k \log m$$
  • For positive arguments and the same valid base, the laws turn multiplication into addition, which is what makes a logarithm useful for solving an equation with the unknown in the exponent.
  • Natural logarithms 自然对数 use the base $e \approx 2.718$ and are written $\ln$.
  • Compound interest 复利 is exponential: $A = P(1 + r)^n$ après $n$ periods.
  • Exponential decay 指数衰减 has a base between 0 and 1, and can describe a retained proportion each period under stated assumptions. It does not guarantee that a real process follows that model indefinitely.

Worked example. repeated reductions multiply rather than subtract a fixed amount

A model starting at 100 is multiplied by 0.8 each period, giving 80 then 64.

Known: an invented quantity starts at 100 units and decreases by 20% per whole period. The retained proportion is 0.8, so use a multiplicative model.

$$Q(n)=Q_0(1-r)^n$$
$$Q(2)=100(1-0.20)^2=64$$

The first decrease is 20 units and the second is 16. A fixed subtraction of 20 each period would be a different model.

Continue with practice sheet 1.6. Solve before opening the solutions, and check both the method and the final units.

Vocabulary · ⁨Vocabulaire⁩ Train · ⁨Entrainer⁩
English · ⁨Anglais⁩ Chinese · ⁨Chinois⁩ Pinyin
exponential function/ˌekspəˈnenʃl ˈfʌŋkʃn/ 指数函数 zhǐ shù hán shù
exponent/ekˈspəʊnənt/ 指数 zhǐ shù
logarithm/ˈlɒɡərɪθəm/ 对数 duì shù
Natural logarithms/ˈnætʃərəl ˈlɒɡərɪθəmz/ 自然对数 zì rán duì shù
Compound interest/ˈkɒmpaʊnd ˈɪntrest/ 复利 fù lì
Exponential decay/ˌekspəˈnenʃl dɪˈkeɪ/ 指数衰减 zhǐ shù shuāi jiǎn

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